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PHXI11:THERMAL PROPERTIES OF MATTER

366615 The freezing point on a thermometer is marked as $20^{\circ}$ and the boiling point as $150^{\circ}$ . A temperature of $60^{\circ} C$ on this thermometer will read as

1

40^{\circ}

2

65^{\circ}

3

98^{\circ}

4

110^{\circ}

Explanation:

$\frac{C}{100} = \frac{θ - 20}{130}$
$\frac{60}{100} = \frac{θ - 20}{130}$
$\Rightarrow θ = 98$

PHXI11:THERMAL PROPERTIES OF MATTER

366616 The graph $A B$ shown in figure is a plot of temperature of a body in degree celsius and degree Fahrenheit. Then
supporting img

1 Slope of line

A B

is

5 / 9

2 Slope of line

A B

is

9 / 5

3 Slope of line

A B

is

3 / 9

4 Slope of line is

1 / 9

Explanation:

Standard equation of line $y = m x + c$ we get slope of the line $A B$ is $m = \frac{100}{212 - 32} = \frac{5}{9}$

PHXI11:THERMAL PROPERTIES OF MATTER

366617 The temperature of a body on kelvin scale is found to be $x K$ . When it is measured by Fahrenhait thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

1 301.25

2 574.25

3 313

4 40

Explanation:

$\frac{F - 32}{9} = \frac{C}{5} = \frac{K - 273}{5} \Rightarrow \frac{x - 32}{9} = \frac{x - 273}{5}$
$\Rightarrow x = 574.25$

PHXI11:THERMAL PROPERTIES OF MATTER

366618 A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$ . What is the fall in temperature is registered by the Centigrade thermometer

1

30^{\circ}

2

40^{\circ}

3

60^{\circ}

4

80^{\circ}

Explanation:

$\frac{F - 32}{180} = \frac{C - 0}{100}$
$\Rightarrow \frac{72}{180} = \frac{Δ C}{100}$
$\Rightarrow Δ C = 40^{\circ} C$

PHXI11:THERMAL PROPERTIES OF MATTER

366615 The freezing point on a thermometer is marked as $20^{\circ}$ and the boiling point as $150^{\circ}$ . A temperature of $60^{\circ} C$ on this thermometer will read as

1

40^{\circ}

2

65^{\circ}

3

98^{\circ}

4

110^{\circ}

Explanation:

$\frac{C}{100} = \frac{θ - 20}{130}$
$\frac{60}{100} = \frac{θ - 20}{130}$
$\Rightarrow θ = 98$

PHXI11:THERMAL PROPERTIES OF MATTER

366616 The graph $A B$ shown in figure is a plot of temperature of a body in degree celsius and degree Fahrenheit. Then
supporting img

1 Slope of line

A B

is

5 / 9

2 Slope of line

A B

is

9 / 5

3 Slope of line

A B

is

3 / 9

4 Slope of line is

1 / 9

Explanation:

Standard equation of line $y = m x + c$ we get slope of the line $A B$ is $m = \frac{100}{212 - 32} = \frac{5}{9}$

PHXI11:THERMAL PROPERTIES OF MATTER

366617 The temperature of a body on kelvin scale is found to be $x K$ . When it is measured by Fahrenhait thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

1 301.25

2 574.25

3 313

4 40

Explanation:

$\frac{F - 32}{9} = \frac{C}{5} = \frac{K - 273}{5} \Rightarrow \frac{x - 32}{9} = \frac{x - 273}{5}$
$\Rightarrow x = 574.25$

PHXI11:THERMAL PROPERTIES OF MATTER

366618 A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$ . What is the fall in temperature is registered by the Centigrade thermometer

1

30^{\circ}

2

40^{\circ}

3

60^{\circ}

4

80^{\circ}

Explanation:

$\frac{F - 32}{180} = \frac{C - 0}{100}$
$\Rightarrow \frac{72}{180} = \frac{Δ C}{100}$
$\Rightarrow Δ C = 40^{\circ} C$

PHXI11:THERMAL PROPERTIES OF MATTER

366615 The freezing point on a thermometer is marked as $20^{\circ}$ and the boiling point as $150^{\circ}$ . A temperature of $60^{\circ} C$ on this thermometer will read as

1

40^{\circ}

2

65^{\circ}

3

98^{\circ}

4

110^{\circ}

Explanation:

$\frac{C}{100} = \frac{θ - 20}{130}$
$\frac{60}{100} = \frac{θ - 20}{130}$
$\Rightarrow θ = 98$

PHXI11:THERMAL PROPERTIES OF MATTER

366616 The graph $A B$ shown in figure is a plot of temperature of a body in degree celsius and degree Fahrenheit. Then
supporting img

1 Slope of line

A B

is

5 / 9

2 Slope of line

A B

is

9 / 5

3 Slope of line

A B

is

3 / 9

4 Slope of line is

1 / 9

Explanation:

Standard equation of line $y = m x + c$ we get slope of the line $A B$ is $m = \frac{100}{212 - 32} = \frac{5}{9}$

PHXI11:THERMAL PROPERTIES OF MATTER

366617 The temperature of a body on kelvin scale is found to be $x K$ . When it is measured by Fahrenhait thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

1 301.25

2 574.25

3 313

4 40

Explanation:

$\frac{F - 32}{9} = \frac{C}{5} = \frac{K - 273}{5} \Rightarrow \frac{x - 32}{9} = \frac{x - 273}{5}$
$\Rightarrow x = 574.25$

PHXI11:THERMAL PROPERTIES OF MATTER

366618 A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$ . What is the fall in temperature is registered by the Centigrade thermometer

1

30^{\circ}

2

40^{\circ}

3

60^{\circ}

4

80^{\circ}

Explanation:

$\frac{F - 32}{180} = \frac{C - 0}{100}$
$\Rightarrow \frac{72}{180} = \frac{Δ C}{100}$
$\Rightarrow Δ C = 40^{\circ} C$

PHXI11:THERMAL PROPERTIES OF MATTER

366615 The freezing point on a thermometer is marked as $20^{\circ}$ and the boiling point as $150^{\circ}$ . A temperature of $60^{\circ} C$ on this thermometer will read as

1

40^{\circ}

2

65^{\circ}

3

98^{\circ}

4

110^{\circ}

Explanation:

$\frac{C}{100} = \frac{θ - 20}{130}$
$\frac{60}{100} = \frac{θ - 20}{130}$
$\Rightarrow θ = 98$

PHXI11:THERMAL PROPERTIES OF MATTER

366616 The graph $A B$ shown in figure is a plot of temperature of a body in degree celsius and degree Fahrenheit. Then
supporting img

1 Slope of line

A B

is

5 / 9

2 Slope of line

A B

is

9 / 5

3 Slope of line

A B

is

3 / 9

4 Slope of line is

1 / 9

Explanation:

Standard equation of line $y = m x + c$ we get slope of the line $A B$ is $m = \frac{100}{212 - 32} = \frac{5}{9}$

PHXI11:THERMAL PROPERTIES OF MATTER

366617 The temperature of a body on kelvin scale is found to be $x K$ . When it is measured by Fahrenhait thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

1 301.25

2 574.25

3 313

4 40

Explanation:

$\frac{F - 32}{9} = \frac{C}{5} = \frac{K - 273}{5} \Rightarrow \frac{x - 32}{9} = \frac{x - 273}{5}$
$\Rightarrow x = 574.25$

PHXI11:THERMAL PROPERTIES OF MATTER

366618 A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers $140^{\circ}$ . What is the fall in temperature is registered by the Centigrade thermometer

1

30^{\circ}

2

40^{\circ}

3

60^{\circ}

4

80^{\circ}

Explanation:

$\frac{F - 32}{180} = \frac{C - 0}{100}$
$\Rightarrow \frac{72}{180} = \frac{Δ C}{100}$
$\Rightarrow Δ C = 40^{\circ} C$

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