363944
Assertion : Cobalt-60 is useful in cancer therapy. Reason : Cobalt-60 is source of \(\gamma\)-radiations capable of killing cancerous cell.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
Explanation:
Cobalt-60 is indeed used in radiotherapy for cancer treatment. Cobalt-60 is a radioactive isotope that emits \(\gamma\)-radiations, which are used to target and kill cancer cells during radiotherapy. Both Assertion and Reason are correct, and Reason is the correct explanation of Assertion. So option (1) is correct.
AIIMS - 2006
PHXII13:NUCLEI
363945
Intensity of gamma rays falls to one eighth of its value after passing through \(18 {~mm}\) of lead. What should be the thickness of the lead sheet to reduce the intensity to half?
363946
Assertion : Out of the following, viz electron, neutron, \({}_2^4He\) and proton, which is not emitted in radioactive emission is \(n\). Reason : Only charged particles can be emitted in radio activity.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive emissions involve alpha-rays \((\alpha)\), which are helium nuclei with a positive charge, beta-rays \((\beta)\), comprising high-speed electrons with a negative charge, and gammarays \((\gamma)\), which are neutral electromagnetic radiations. So correct option is (3).
PHXII13:NUCLEI
363947
In a hypothetical fission reaction, \({ }_{92} X^{236} \rightarrow_{56} Y^{141}+{ }_{36} Z^{92}+3 R\) The identity of emitted particles \((R)\) is
1 \(\gamma\)-radiations
2 electron
3 proton
4 neutron
Explanation:
\(92=56+36+Z_{R} \Rightarrow Z_{R}=0\) \(\therefore \quad R\) is a neutral particle. \(A_{R}=\dfrac{236-(141+92)}{3}=1\) So, the emitted particle \((R)\) is neutron.
363944
Assertion : Cobalt-60 is useful in cancer therapy. Reason : Cobalt-60 is source of \(\gamma\)-radiations capable of killing cancerous cell.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
Explanation:
Cobalt-60 is indeed used in radiotherapy for cancer treatment. Cobalt-60 is a radioactive isotope that emits \(\gamma\)-radiations, which are used to target and kill cancer cells during radiotherapy. Both Assertion and Reason are correct, and Reason is the correct explanation of Assertion. So option (1) is correct.
AIIMS - 2006
PHXII13:NUCLEI
363945
Intensity of gamma rays falls to one eighth of its value after passing through \(18 {~mm}\) of lead. What should be the thickness of the lead sheet to reduce the intensity to half?
363946
Assertion : Out of the following, viz electron, neutron, \({}_2^4He\) and proton, which is not emitted in radioactive emission is \(n\). Reason : Only charged particles can be emitted in radio activity.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive emissions involve alpha-rays \((\alpha)\), which are helium nuclei with a positive charge, beta-rays \((\beta)\), comprising high-speed electrons with a negative charge, and gammarays \((\gamma)\), which are neutral electromagnetic radiations. So correct option is (3).
PHXII13:NUCLEI
363947
In a hypothetical fission reaction, \({ }_{92} X^{236} \rightarrow_{56} Y^{141}+{ }_{36} Z^{92}+3 R\) The identity of emitted particles \((R)\) is
1 \(\gamma\)-radiations
2 electron
3 proton
4 neutron
Explanation:
\(92=56+36+Z_{R} \Rightarrow Z_{R}=0\) \(\therefore \quad R\) is a neutral particle. \(A_{R}=\dfrac{236-(141+92)}{3}=1\) So, the emitted particle \((R)\) is neutron.
363944
Assertion : Cobalt-60 is useful in cancer therapy. Reason : Cobalt-60 is source of \(\gamma\)-radiations capable of killing cancerous cell.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
Explanation:
Cobalt-60 is indeed used in radiotherapy for cancer treatment. Cobalt-60 is a radioactive isotope that emits \(\gamma\)-radiations, which are used to target and kill cancer cells during radiotherapy. Both Assertion and Reason are correct, and Reason is the correct explanation of Assertion. So option (1) is correct.
AIIMS - 2006
PHXII13:NUCLEI
363945
Intensity of gamma rays falls to one eighth of its value after passing through \(18 {~mm}\) of lead. What should be the thickness of the lead sheet to reduce the intensity to half?
363946
Assertion : Out of the following, viz electron, neutron, \({}_2^4He\) and proton, which is not emitted in radioactive emission is \(n\). Reason : Only charged particles can be emitted in radio activity.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive emissions involve alpha-rays \((\alpha)\), which are helium nuclei with a positive charge, beta-rays \((\beta)\), comprising high-speed electrons with a negative charge, and gammarays \((\gamma)\), which are neutral electromagnetic radiations. So correct option is (3).
PHXII13:NUCLEI
363947
In a hypothetical fission reaction, \({ }_{92} X^{236} \rightarrow_{56} Y^{141}+{ }_{36} Z^{92}+3 R\) The identity of emitted particles \((R)\) is
1 \(\gamma\)-radiations
2 electron
3 proton
4 neutron
Explanation:
\(92=56+36+Z_{R} \Rightarrow Z_{R}=0\) \(\therefore \quad R\) is a neutral particle. \(A_{R}=\dfrac{236-(141+92)}{3}=1\) So, the emitted particle \((R)\) is neutron.
363944
Assertion : Cobalt-60 is useful in cancer therapy. Reason : Cobalt-60 is source of \(\gamma\)-radiations capable of killing cancerous cell.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are incorrect.
Explanation:
Cobalt-60 is indeed used in radiotherapy for cancer treatment. Cobalt-60 is a radioactive isotope that emits \(\gamma\)-radiations, which are used to target and kill cancer cells during radiotherapy. Both Assertion and Reason are correct, and Reason is the correct explanation of Assertion. So option (1) is correct.
AIIMS - 2006
PHXII13:NUCLEI
363945
Intensity of gamma rays falls to one eighth of its value after passing through \(18 {~mm}\) of lead. What should be the thickness of the lead sheet to reduce the intensity to half?
363946
Assertion : Out of the following, viz electron, neutron, \({}_2^4He\) and proton, which is not emitted in radioactive emission is \(n\). Reason : Only charged particles can be emitted in radio activity.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Radioactive emissions involve alpha-rays \((\alpha)\), which are helium nuclei with a positive charge, beta-rays \((\beta)\), comprising high-speed electrons with a negative charge, and gammarays \((\gamma)\), which are neutral electromagnetic radiations. So correct option is (3).
PHXII13:NUCLEI
363947
In a hypothetical fission reaction, \({ }_{92} X^{236} \rightarrow_{56} Y^{141}+{ }_{36} Z^{92}+3 R\) The identity of emitted particles \((R)\) is
1 \(\gamma\)-radiations
2 electron
3 proton
4 neutron
Explanation:
\(92=56+36+Z_{R} \Rightarrow Z_{R}=0\) \(\therefore \quad R\) is a neutral particle. \(A_{R}=\dfrac{236-(141+92)}{3}=1\) So, the emitted particle \((R)\) is neutron.
