363935
The mother and daughter elements, with emission of \(\gamma\) -rays are
1 Isotopes
2 Isobars
3 Isomers
4 Isodiapheres
Explanation:
The mother and daughter elements after the emission of \(\gamma\)-rays are called isomers having same atomic number and mass number. Isotopes have same atomic number but different atomic mass and isobars have same mass number but different atomic number. Isodiaphers have same difference in proton and neutron numbers.
AIIMS - 2013
PHXII13:NUCLEI
363936
The particles emitted in the decay of \({}_{92}^{238}U\) to \({}_{92}^{234}U\)
1 \({\text{2}}\alpha {\text{ and 2}}\beta \)
2 \(1\alpha {\text{ and 2}}\beta \)
3 \(1\alpha {\text{ and 1}}\beta \)
4 \(1\alpha {\text{ only}}\)
Explanation:
\({}_{92}^{238}U \to {}_{92}^{234}U + x{}_2^4\alpha + y{}_{ - 1}^0\beta \) Using law of conservation of charges and masses \(238 = 234 + 4x\,{\text{or}}\,x = 1\) and \(92 = 92 + 2x - y\) or \(y = 2x = 2\) Therefore, one \(\alpha \) and two \(\beta \) particles are emitted
KCET - 2017
PHXII13:NUCLEI
363937
During a \(\beta \) decay
1 A neutron in the nucleus decays emitting an electron
2 A proton in the nucleus decays emitting an electron
3 An atomic electron is ejected
4 An electron which is already present within the nucleus is ejected
Explanation:
In \({\beta ^ - }\) decay \(_Z{X^A}{ \to _{Z + 1}}{Y^A} + {e^ - } + \overline v \) Thus a neutron in the nucleus decays into a proton and an electron along with the emission of an antineutrino
PHXII13:NUCLEI
363938
Assertion : Amongst \(\alpha, \beta\) and \(\gamma\) -rays, \(\alpha\) rays have maximum ionizing power. Reason : \(\gamma\) -rays have maximum penetrating power.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Gamma-rays ( \(\gamma\)-rays) have high frequency and strong penetration, lacking ionizing power. Alpha particles \((\alpha)\) are highly ionizing but less penetrative. Beta particles \((\beta)\) have moderate ionization and penetration. So correct option is (2).
PHXII13:NUCLEI
363939
The end product of decay \(_{90}T{h^{232}}\) is \(_{82}P{b^{208}}\). The number of \(\alpha \) and \(\beta \) particles emitted are respectively
1 \(6,0\)
2 \(3,3\)
3 \(4,6\)
4 \(6,4\)
Explanation:
\(_{90}T{h^{232}}{ \to _{82}}P{b^{208}}\) Change in atomic mass \( = 232 - 208 = 24\) Number of \(\alpha \)- particles emitted \( = 24/4 = 6\) Atomic number will decrease by \(6 \times 2 = 12\) Atomic number will be increase by 4 due to emission \(4\beta \) particles. So, net decrease in atomic number \( = 12 - 4 = 8\)
363935
The mother and daughter elements, with emission of \(\gamma\) -rays are
1 Isotopes
2 Isobars
3 Isomers
4 Isodiapheres
Explanation:
The mother and daughter elements after the emission of \(\gamma\)-rays are called isomers having same atomic number and mass number. Isotopes have same atomic number but different atomic mass and isobars have same mass number but different atomic number. Isodiaphers have same difference in proton and neutron numbers.
AIIMS - 2013
PHXII13:NUCLEI
363936
The particles emitted in the decay of \({}_{92}^{238}U\) to \({}_{92}^{234}U\)
1 \({\text{2}}\alpha {\text{ and 2}}\beta \)
2 \(1\alpha {\text{ and 2}}\beta \)
3 \(1\alpha {\text{ and 1}}\beta \)
4 \(1\alpha {\text{ only}}\)
Explanation:
\({}_{92}^{238}U \to {}_{92}^{234}U + x{}_2^4\alpha + y{}_{ - 1}^0\beta \) Using law of conservation of charges and masses \(238 = 234 + 4x\,{\text{or}}\,x = 1\) and \(92 = 92 + 2x - y\) or \(y = 2x = 2\) Therefore, one \(\alpha \) and two \(\beta \) particles are emitted
KCET - 2017
PHXII13:NUCLEI
363937
During a \(\beta \) decay
1 A neutron in the nucleus decays emitting an electron
2 A proton in the nucleus decays emitting an electron
3 An atomic electron is ejected
4 An electron which is already present within the nucleus is ejected
Explanation:
In \({\beta ^ - }\) decay \(_Z{X^A}{ \to _{Z + 1}}{Y^A} + {e^ - } + \overline v \) Thus a neutron in the nucleus decays into a proton and an electron along with the emission of an antineutrino
PHXII13:NUCLEI
363938
Assertion : Amongst \(\alpha, \beta\) and \(\gamma\) -rays, \(\alpha\) rays have maximum ionizing power. Reason : \(\gamma\) -rays have maximum penetrating power.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Gamma-rays ( \(\gamma\)-rays) have high frequency and strong penetration, lacking ionizing power. Alpha particles \((\alpha)\) are highly ionizing but less penetrative. Beta particles \((\beta)\) have moderate ionization and penetration. So correct option is (2).
PHXII13:NUCLEI
363939
The end product of decay \(_{90}T{h^{232}}\) is \(_{82}P{b^{208}}\). The number of \(\alpha \) and \(\beta \) particles emitted are respectively
1 \(6,0\)
2 \(3,3\)
3 \(4,6\)
4 \(6,4\)
Explanation:
\(_{90}T{h^{232}}{ \to _{82}}P{b^{208}}\) Change in atomic mass \( = 232 - 208 = 24\) Number of \(\alpha \)- particles emitted \( = 24/4 = 6\) Atomic number will decrease by \(6 \times 2 = 12\) Atomic number will be increase by 4 due to emission \(4\beta \) particles. So, net decrease in atomic number \( = 12 - 4 = 8\)
363935
The mother and daughter elements, with emission of \(\gamma\) -rays are
1 Isotopes
2 Isobars
3 Isomers
4 Isodiapheres
Explanation:
The mother and daughter elements after the emission of \(\gamma\)-rays are called isomers having same atomic number and mass number. Isotopes have same atomic number but different atomic mass and isobars have same mass number but different atomic number. Isodiaphers have same difference in proton and neutron numbers.
AIIMS - 2013
PHXII13:NUCLEI
363936
The particles emitted in the decay of \({}_{92}^{238}U\) to \({}_{92}^{234}U\)
1 \({\text{2}}\alpha {\text{ and 2}}\beta \)
2 \(1\alpha {\text{ and 2}}\beta \)
3 \(1\alpha {\text{ and 1}}\beta \)
4 \(1\alpha {\text{ only}}\)
Explanation:
\({}_{92}^{238}U \to {}_{92}^{234}U + x{}_2^4\alpha + y{}_{ - 1}^0\beta \) Using law of conservation of charges and masses \(238 = 234 + 4x\,{\text{or}}\,x = 1\) and \(92 = 92 + 2x - y\) or \(y = 2x = 2\) Therefore, one \(\alpha \) and two \(\beta \) particles are emitted
KCET - 2017
PHXII13:NUCLEI
363937
During a \(\beta \) decay
1 A neutron in the nucleus decays emitting an electron
2 A proton in the nucleus decays emitting an electron
3 An atomic electron is ejected
4 An electron which is already present within the nucleus is ejected
Explanation:
In \({\beta ^ - }\) decay \(_Z{X^A}{ \to _{Z + 1}}{Y^A} + {e^ - } + \overline v \) Thus a neutron in the nucleus decays into a proton and an electron along with the emission of an antineutrino
PHXII13:NUCLEI
363938
Assertion : Amongst \(\alpha, \beta\) and \(\gamma\) -rays, \(\alpha\) rays have maximum ionizing power. Reason : \(\gamma\) -rays have maximum penetrating power.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Gamma-rays ( \(\gamma\)-rays) have high frequency and strong penetration, lacking ionizing power. Alpha particles \((\alpha)\) are highly ionizing but less penetrative. Beta particles \((\beta)\) have moderate ionization and penetration. So correct option is (2).
PHXII13:NUCLEI
363939
The end product of decay \(_{90}T{h^{232}}\) is \(_{82}P{b^{208}}\). The number of \(\alpha \) and \(\beta \) particles emitted are respectively
1 \(6,0\)
2 \(3,3\)
3 \(4,6\)
4 \(6,4\)
Explanation:
\(_{90}T{h^{232}}{ \to _{82}}P{b^{208}}\) Change in atomic mass \( = 232 - 208 = 24\) Number of \(\alpha \)- particles emitted \( = 24/4 = 6\) Atomic number will decrease by \(6 \times 2 = 12\) Atomic number will be increase by 4 due to emission \(4\beta \) particles. So, net decrease in atomic number \( = 12 - 4 = 8\)
363935
The mother and daughter elements, with emission of \(\gamma\) -rays are
1 Isotopes
2 Isobars
3 Isomers
4 Isodiapheres
Explanation:
The mother and daughter elements after the emission of \(\gamma\)-rays are called isomers having same atomic number and mass number. Isotopes have same atomic number but different atomic mass and isobars have same mass number but different atomic number. Isodiaphers have same difference in proton and neutron numbers.
AIIMS - 2013
PHXII13:NUCLEI
363936
The particles emitted in the decay of \({}_{92}^{238}U\) to \({}_{92}^{234}U\)
1 \({\text{2}}\alpha {\text{ and 2}}\beta \)
2 \(1\alpha {\text{ and 2}}\beta \)
3 \(1\alpha {\text{ and 1}}\beta \)
4 \(1\alpha {\text{ only}}\)
Explanation:
\({}_{92}^{238}U \to {}_{92}^{234}U + x{}_2^4\alpha + y{}_{ - 1}^0\beta \) Using law of conservation of charges and masses \(238 = 234 + 4x\,{\text{or}}\,x = 1\) and \(92 = 92 + 2x - y\) or \(y = 2x = 2\) Therefore, one \(\alpha \) and two \(\beta \) particles are emitted
KCET - 2017
PHXII13:NUCLEI
363937
During a \(\beta \) decay
1 A neutron in the nucleus decays emitting an electron
2 A proton in the nucleus decays emitting an electron
3 An atomic electron is ejected
4 An electron which is already present within the nucleus is ejected
Explanation:
In \({\beta ^ - }\) decay \(_Z{X^A}{ \to _{Z + 1}}{Y^A} + {e^ - } + \overline v \) Thus a neutron in the nucleus decays into a proton and an electron along with the emission of an antineutrino
PHXII13:NUCLEI
363938
Assertion : Amongst \(\alpha, \beta\) and \(\gamma\) -rays, \(\alpha\) rays have maximum ionizing power. Reason : \(\gamma\) -rays have maximum penetrating power.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Gamma-rays ( \(\gamma\)-rays) have high frequency and strong penetration, lacking ionizing power. Alpha particles \((\alpha)\) are highly ionizing but less penetrative. Beta particles \((\beta)\) have moderate ionization and penetration. So correct option is (2).
PHXII13:NUCLEI
363939
The end product of decay \(_{90}T{h^{232}}\) is \(_{82}P{b^{208}}\). The number of \(\alpha \) and \(\beta \) particles emitted are respectively
1 \(6,0\)
2 \(3,3\)
3 \(4,6\)
4 \(6,4\)
Explanation:
\(_{90}T{h^{232}}{ \to _{82}}P{b^{208}}\) Change in atomic mass \( = 232 - 208 = 24\) Number of \(\alpha \)- particles emitted \( = 24/4 = 6\) Atomic number will decrease by \(6 \times 2 = 12\) Atomic number will be increase by 4 due to emission \(4\beta \) particles. So, net decrease in atomic number \( = 12 - 4 = 8\)
363935
The mother and daughter elements, with emission of \(\gamma\) -rays are
1 Isotopes
2 Isobars
3 Isomers
4 Isodiapheres
Explanation:
The mother and daughter elements after the emission of \(\gamma\)-rays are called isomers having same atomic number and mass number. Isotopes have same atomic number but different atomic mass and isobars have same mass number but different atomic number. Isodiaphers have same difference in proton and neutron numbers.
AIIMS - 2013
PHXII13:NUCLEI
363936
The particles emitted in the decay of \({}_{92}^{238}U\) to \({}_{92}^{234}U\)
1 \({\text{2}}\alpha {\text{ and 2}}\beta \)
2 \(1\alpha {\text{ and 2}}\beta \)
3 \(1\alpha {\text{ and 1}}\beta \)
4 \(1\alpha {\text{ only}}\)
Explanation:
\({}_{92}^{238}U \to {}_{92}^{234}U + x{}_2^4\alpha + y{}_{ - 1}^0\beta \) Using law of conservation of charges and masses \(238 = 234 + 4x\,{\text{or}}\,x = 1\) and \(92 = 92 + 2x - y\) or \(y = 2x = 2\) Therefore, one \(\alpha \) and two \(\beta \) particles are emitted
KCET - 2017
PHXII13:NUCLEI
363937
During a \(\beta \) decay
1 A neutron in the nucleus decays emitting an electron
2 A proton in the nucleus decays emitting an electron
3 An atomic electron is ejected
4 An electron which is already present within the nucleus is ejected
Explanation:
In \({\beta ^ - }\) decay \(_Z{X^A}{ \to _{Z + 1}}{Y^A} + {e^ - } + \overline v \) Thus a neutron in the nucleus decays into a proton and an electron along with the emission of an antineutrino
PHXII13:NUCLEI
363938
Assertion : Amongst \(\alpha, \beta\) and \(\gamma\) -rays, \(\alpha\) rays have maximum ionizing power. Reason : \(\gamma\) -rays have maximum penetrating power.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Gamma-rays ( \(\gamma\)-rays) have high frequency and strong penetration, lacking ionizing power. Alpha particles \((\alpha)\) are highly ionizing but less penetrative. Beta particles \((\beta)\) have moderate ionization and penetration. So correct option is (2).
PHXII13:NUCLEI
363939
The end product of decay \(_{90}T{h^{232}}\) is \(_{82}P{b^{208}}\). The number of \(\alpha \) and \(\beta \) particles emitted are respectively
1 \(6,0\)
2 \(3,3\)
3 \(4,6\)
4 \(6,4\)
Explanation:
\(_{90}T{h^{232}}{ \to _{82}}P{b^{208}}\) Change in atomic mass \( = 232 - 208 = 24\) Number of \(\alpha \)- particles emitted \( = 24/4 = 6\) Atomic number will decrease by \(6 \times 2 = 12\) Atomic number will be increase by 4 due to emission \(4\beta \) particles. So, net decrease in atomic number \( = 12 - 4 = 8\)
