363865 The particle \(A\) is converted into \(C\) via following reaction
\(A \to B{ + _2}H{e^4}\)
\(B \rightarrow C+2 e^{-}\)
Then

363866 Two nuclei have mass number in ratio of \(1: 4\). The ratio of their nuclear densities is:

363867 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
The nuclear density of nuclides \(_5^{10}B,\,_3^6Li,\,_{26}^{56}Fe,\,_{10}^{20}\,Ne\) and \(_{83}^{209}Bi\) can be arranged as \(\rho_{B i}^{N}>\rho_{F e}^{N}>\rho_{N e}^{N}>\rho_{B}^{N}>\rho_{L i}^{N}\)
Reason :
The radius \(R\) of nucleus is related to its mass number \(A\) as \(R=R_{0} A^{1 / 3}\), where \(R_{0}\) is a constant.

363868 The ratio of volume of \({A l^{27}}\) nucleus to its surface area is (Given \({R_{0}=1.2 \times 10^{-15} {~m}}\) )

363865 The particle \(A\) is converted into \(C\) via following reaction
\(A \to B{ + _2}H{e^4}\)
\(B \rightarrow C+2 e^{-}\)
Then

363866 Two nuclei have mass number in ratio of \(1: 4\). The ratio of their nuclear densities is:

363867 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
The nuclear density of nuclides \(_5^{10}B,\,_3^6Li,\,_{26}^{56}Fe,\,_{10}^{20}\,Ne\) and \(_{83}^{209}Bi\) can be arranged as \(\rho_{B i}^{N}>\rho_{F e}^{N}>\rho_{N e}^{N}>\rho_{B}^{N}>\rho_{L i}^{N}\)
Reason :
The radius \(R\) of nucleus is related to its mass number \(A\) as \(R=R_{0} A^{1 / 3}\), where \(R_{0}\) is a constant.

363868 The ratio of volume of \({A l^{27}}\) nucleus to its surface area is (Given \({R_{0}=1.2 \times 10^{-15} {~m}}\) )

363865 The particle \(A\) is converted into \(C\) via following reaction
\(A \to B{ + _2}H{e^4}\)
\(B \rightarrow C+2 e^{-}\)
Then

363866 Two nuclei have mass number in ratio of \(1: 4\). The ratio of their nuclear densities is:

363867 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
The nuclear density of nuclides \(_5^{10}B,\,_3^6Li,\,_{26}^{56}Fe,\,_{10}^{20}\,Ne\) and \(_{83}^{209}Bi\) can be arranged as \(\rho_{B i}^{N}>\rho_{F e}^{N}>\rho_{N e}^{N}>\rho_{B}^{N}>\rho_{L i}^{N}\)
Reason :
The radius \(R\) of nucleus is related to its mass number \(A\) as \(R=R_{0} A^{1 / 3}\), where \(R_{0}\) is a constant.

363868 The ratio of volume of \({A l^{27}}\) nucleus to its surface area is (Given \({R_{0}=1.2 \times 10^{-15} {~m}}\) )

363865 The particle \(A\) is converted into \(C\) via following reaction
\(A \to B{ + _2}H{e^4}\)
\(B \rightarrow C+2 e^{-}\)
Then

363866 Two nuclei have mass number in ratio of \(1: 4\). The ratio of their nuclear densities is:

363867 Read the Assertion and Reason carefully to mark the correct options given below:
Assertion :
The nuclear density of nuclides \(_5^{10}B,\,_3^6Li,\,_{26}^{56}Fe,\,_{10}^{20}\,Ne\) and \(_{83}^{209}Bi\) can be arranged as \(\rho_{B i}^{N}>\rho_{F e}^{N}>\rho_{N e}^{N}>\rho_{B}^{N}>\rho_{L i}^{N}\)
Reason :
The radius \(R\) of nucleus is related to its mass number \(A\) as \(R=R_{0} A^{1 / 3}\), where \(R_{0}\) is a constant.

363868 The ratio of volume of \({A l^{27}}\) nucleus to its surface area is (Given \({R_{0}=1.2 \times 10^{-15} {~m}}\) )