363831
Atomic weight of Boron is \(10.81\) and it has two isotopes \({}_5{B^{10}}\) and \({}_5{B^{11}}.\) Then the ratio of isotopes in nature would be
1 \(10:11\)
2 \(19:81\)
3 \(81:19\)
4 \(15:16\)
Explanation:
The number of \({}^{10}B\) type atoms \( = x\) And the number of \({}^{11}B\) type atoms \( = y\) Weight of \({}^{10}B\) type atoms \( = 10x\) Weight of \({}^{11}B\) type atoms \( = 11y\) Total number of atoms \( = x + y\) \(\therefore \) Atomic weight \( = \frac{{10x + 11y}}{{x + y}} = 10.81\) \( \Rightarrow 10x + 11y = 10.81x + 10.81y\) \( \Rightarrow 0.81x = 0.19y \Rightarrow \frac{x}{y} = \frac{{19}}{{81}}\)
PHXII13:NUCLEI
363832
\(A\) and \(B\) are isotopes. \(B\) and \(C\) are isobars. All three are radioactive. Which one of the following is true?
1 \(A\), \(B\) and \(C\) must belong to the same element.
2 \(A\), \(B\) and \(C\) may belong to the same element.
3 It is possible that \(A\) will change to \(B\) through a radioactive-decay process.
4 It is possible that \(B\) will change to \(C\) through a radioactive-decay process.
Explanation:
Isotopes have same atomic number and different neutron number. Isobars have different atomic number and same mass number.
PHXII13:NUCLEI
363833
Number of protons and neutrons in \(T H_{90}^{234}\) respectively are:
1 90,234
2 144,90
3 90,144
4 234,90
Explanation:
\(P=90, n=234-90=144\).
PHXII13:NUCLEI
363834
Statement A : The whole mass of the atom is concentrated in the nucleus. Statement B : The mass of a nucleus can be either less than or more than the sum of the masses of nucleons present in it.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Mass of a nucleus is always less than the total mass of nucleons. Option (1) is correct.
363831
Atomic weight of Boron is \(10.81\) and it has two isotopes \({}_5{B^{10}}\) and \({}_5{B^{11}}.\) Then the ratio of isotopes in nature would be
1 \(10:11\)
2 \(19:81\)
3 \(81:19\)
4 \(15:16\)
Explanation:
The number of \({}^{10}B\) type atoms \( = x\) And the number of \({}^{11}B\) type atoms \( = y\) Weight of \({}^{10}B\) type atoms \( = 10x\) Weight of \({}^{11}B\) type atoms \( = 11y\) Total number of atoms \( = x + y\) \(\therefore \) Atomic weight \( = \frac{{10x + 11y}}{{x + y}} = 10.81\) \( \Rightarrow 10x + 11y = 10.81x + 10.81y\) \( \Rightarrow 0.81x = 0.19y \Rightarrow \frac{x}{y} = \frac{{19}}{{81}}\)
PHXII13:NUCLEI
363832
\(A\) and \(B\) are isotopes. \(B\) and \(C\) are isobars. All three are radioactive. Which one of the following is true?
1 \(A\), \(B\) and \(C\) must belong to the same element.
2 \(A\), \(B\) and \(C\) may belong to the same element.
3 It is possible that \(A\) will change to \(B\) through a radioactive-decay process.
4 It is possible that \(B\) will change to \(C\) through a radioactive-decay process.
Explanation:
Isotopes have same atomic number and different neutron number. Isobars have different atomic number and same mass number.
PHXII13:NUCLEI
363833
Number of protons and neutrons in \(T H_{90}^{234}\) respectively are:
1 90,234
2 144,90
3 90,144
4 234,90
Explanation:
\(P=90, n=234-90=144\).
PHXII13:NUCLEI
363834
Statement A : The whole mass of the atom is concentrated in the nucleus. Statement B : The mass of a nucleus can be either less than or more than the sum of the masses of nucleons present in it.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Mass of a nucleus is always less than the total mass of nucleons. Option (1) is correct.
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PHXII13:NUCLEI
363831
Atomic weight of Boron is \(10.81\) and it has two isotopes \({}_5{B^{10}}\) and \({}_5{B^{11}}.\) Then the ratio of isotopes in nature would be
1 \(10:11\)
2 \(19:81\)
3 \(81:19\)
4 \(15:16\)
Explanation:
The number of \({}^{10}B\) type atoms \( = x\) And the number of \({}^{11}B\) type atoms \( = y\) Weight of \({}^{10}B\) type atoms \( = 10x\) Weight of \({}^{11}B\) type atoms \( = 11y\) Total number of atoms \( = x + y\) \(\therefore \) Atomic weight \( = \frac{{10x + 11y}}{{x + y}} = 10.81\) \( \Rightarrow 10x + 11y = 10.81x + 10.81y\) \( \Rightarrow 0.81x = 0.19y \Rightarrow \frac{x}{y} = \frac{{19}}{{81}}\)
PHXII13:NUCLEI
363832
\(A\) and \(B\) are isotopes. \(B\) and \(C\) are isobars. All three are radioactive. Which one of the following is true?
1 \(A\), \(B\) and \(C\) must belong to the same element.
2 \(A\), \(B\) and \(C\) may belong to the same element.
3 It is possible that \(A\) will change to \(B\) through a radioactive-decay process.
4 It is possible that \(B\) will change to \(C\) through a radioactive-decay process.
Explanation:
Isotopes have same atomic number and different neutron number. Isobars have different atomic number and same mass number.
PHXII13:NUCLEI
363833
Number of protons and neutrons in \(T H_{90}^{234}\) respectively are:
1 90,234
2 144,90
3 90,144
4 234,90
Explanation:
\(P=90, n=234-90=144\).
PHXII13:NUCLEI
363834
Statement A : The whole mass of the atom is concentrated in the nucleus. Statement B : The mass of a nucleus can be either less than or more than the sum of the masses of nucleons present in it.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Mass of a nucleus is always less than the total mass of nucleons. Option (1) is correct.
363831
Atomic weight of Boron is \(10.81\) and it has two isotopes \({}_5{B^{10}}\) and \({}_5{B^{11}}.\) Then the ratio of isotopes in nature would be
1 \(10:11\)
2 \(19:81\)
3 \(81:19\)
4 \(15:16\)
Explanation:
The number of \({}^{10}B\) type atoms \( = x\) And the number of \({}^{11}B\) type atoms \( = y\) Weight of \({}^{10}B\) type atoms \( = 10x\) Weight of \({}^{11}B\) type atoms \( = 11y\) Total number of atoms \( = x + y\) \(\therefore \) Atomic weight \( = \frac{{10x + 11y}}{{x + y}} = 10.81\) \( \Rightarrow 10x + 11y = 10.81x + 10.81y\) \( \Rightarrow 0.81x = 0.19y \Rightarrow \frac{x}{y} = \frac{{19}}{{81}}\)
PHXII13:NUCLEI
363832
\(A\) and \(B\) are isotopes. \(B\) and \(C\) are isobars. All three are radioactive. Which one of the following is true?
1 \(A\), \(B\) and \(C\) must belong to the same element.
2 \(A\), \(B\) and \(C\) may belong to the same element.
3 It is possible that \(A\) will change to \(B\) through a radioactive-decay process.
4 It is possible that \(B\) will change to \(C\) through a radioactive-decay process.
Explanation:
Isotopes have same atomic number and different neutron number. Isobars have different atomic number and same mass number.
PHXII13:NUCLEI
363833
Number of protons and neutrons in \(T H_{90}^{234}\) respectively are:
1 90,234
2 144,90
3 90,144
4 234,90
Explanation:
\(P=90, n=234-90=144\).
PHXII13:NUCLEI
363834
Statement A : The whole mass of the atom is concentrated in the nucleus. Statement B : The mass of a nucleus can be either less than or more than the sum of the masses of nucleons present in it.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both Statements are correct.
4 Both Statements are incorrect.
Explanation:
Mass of a nucleus is always less than the total mass of nucleons. Option (1) is correct.