363738 Assertion :
Energy is released in nuclear fission.
Reason :
Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

363739 The nuclear binding energies of the elements \(P\) and \(Q\) are \(E_{P}\) and \(E_{Q}\), respectively. Three nuclei of elements \(Q\) fuse to form one nucleus of element \(P\). In this process, the energy released is \(e\). The correct relation between \(E_{P}, E_{Q}\), and \(e\) will be

363740 The energy released in the fusion of \(2\,kg\) of hydrogen deep in the sun is \(E_{H}\) and the energy released in the fission of \(2\,kg\) of \(^{235}U\) is \(E_{U}\). The ratio \(\dfrac{E_{H}}{E_{U}}\) is approximately (Consider the fusion reaction as, \(4_1^1H + 2{e^ - } \to _2^4He + 2v + 6\gamma + 26.7MeV\) energy released in the fission reaction of \({ }^{235} U\) is \(200\,MeV\) per fission nucleus and \({N_A} = 6.023 \times {10^{23}}\,)\)

363741 Calculate the energy released when three
\(\alpha\) - particles combined to from a \({ }^{12} C\) nucleus, the mass defect is (atomic mass of \(_2H{e^4}\) is \(4.002603 u\))

363738 Assertion :
Energy is released in nuclear fission.
Reason :
Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

363739 The nuclear binding energies of the elements \(P\) and \(Q\) are \(E_{P}\) and \(E_{Q}\), respectively. Three nuclei of elements \(Q\) fuse to form one nucleus of element \(P\). In this process, the energy released is \(e\). The correct relation between \(E_{P}, E_{Q}\), and \(e\) will be

363740 The energy released in the fusion of \(2\,kg\) of hydrogen deep in the sun is \(E_{H}\) and the energy released in the fission of \(2\,kg\) of \(^{235}U\) is \(E_{U}\). The ratio \(\dfrac{E_{H}}{E_{U}}\) is approximately (Consider the fusion reaction as, \(4_1^1H + 2{e^ - } \to _2^4He + 2v + 6\gamma + 26.7MeV\) energy released in the fission reaction of \({ }^{235} U\) is \(200\,MeV\) per fission nucleus and \({N_A} = 6.023 \times {10^{23}}\,)\)

363741 Calculate the energy released when three
\(\alpha\) - particles combined to from a \({ }^{12} C\) nucleus, the mass defect is (atomic mass of \(_2H{e^4}\) is \(4.002603 u\))

363738 Assertion :
Energy is released in nuclear fission.
Reason :
Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

363739 The nuclear binding energies of the elements \(P\) and \(Q\) are \(E_{P}\) and \(E_{Q}\), respectively. Three nuclei of elements \(Q\) fuse to form one nucleus of element \(P\). In this process, the energy released is \(e\). The correct relation between \(E_{P}, E_{Q}\), and \(e\) will be

363740 The energy released in the fusion of \(2\,kg\) of hydrogen deep in the sun is \(E_{H}\) and the energy released in the fission of \(2\,kg\) of \(^{235}U\) is \(E_{U}\). The ratio \(\dfrac{E_{H}}{E_{U}}\) is approximately (Consider the fusion reaction as, \(4_1^1H + 2{e^ - } \to _2^4He + 2v + 6\gamma + 26.7MeV\) energy released in the fission reaction of \({ }^{235} U\) is \(200\,MeV\) per fission nucleus and \({N_A} = 6.023 \times {10^{23}}\,)\)

363741 Calculate the energy released when three
\(\alpha\) - particles combined to from a \({ }^{12} C\) nucleus, the mass defect is (atomic mass of \(_2H{e^4}\) is \(4.002603 u\))

363738 Assertion :
Energy is released in nuclear fission.
Reason :
Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

363739 The nuclear binding energies of the elements \(P\) and \(Q\) are \(E_{P}\) and \(E_{Q}\), respectively. Three nuclei of elements \(Q\) fuse to form one nucleus of element \(P\). In this process, the energy released is \(e\). The correct relation between \(E_{P}, E_{Q}\), and \(e\) will be

363740 The energy released in the fusion of \(2\,kg\) of hydrogen deep in the sun is \(E_{H}\) and the energy released in the fission of \(2\,kg\) of \(^{235}U\) is \(E_{U}\). The ratio \(\dfrac{E_{H}}{E_{U}}\) is approximately (Consider the fusion reaction as, \(4_1^1H + 2{e^ - } \to _2^4He + 2v + 6\gamma + 26.7MeV\) energy released in the fission reaction of \({ }^{235} U\) is \(200\,MeV\) per fission nucleus and \({N_A} = 6.023 \times {10^{23}}\,)\)

363741 Calculate the energy released when three
\(\alpha\) - particles combined to from a \({ }^{12} C\) nucleus, the mass defect is (atomic mass of \(_2H{e^4}\) is \(4.002603 u\))