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PHXII13:NUCLEI

363684 The binding energy per nucleon of dueterium and helium nuclei are $1.1 M e V$ and $7 M e V$ respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

1

24.6 M e V

2

25.1 M e V

3

22.3 M e V

4

23.6 M e V

Explanation:

$_{1} H^{2} +_{1} H^{2} \to 2 H e^{4} + Δ E$
The binding energy per nucleon of a deuterium $= 1.1 M e V$ .
$∴$ Total binding energy $= 4 \times 1.1 = 4.4 M e V$ .
The binding energy per nucleon of a helium nuclei $= 7 M e V$ .
$∴$ Total binding energy $= 4 \times 7 = 28 M e V$ .
Hence, energy released.
$Δ E = (28 - 4.4) M e V = 23.6 M e V .$

PHXII13:NUCLEI

363685 Pick out the correct statement from the following:

1 Energy released per unit mass of the reactant is less in case of fusion reaction

2 Packing fraction may be positive or may be negative

3

P u^{239}

is not suitable for a fission reaction

4 For stable nucleus, the specific binding energy is low

KCET - 2010

PHXII13:NUCLEI

363686 Average binding energy per nucleon over a wide range is

1

8 M e V

2

8.8 M e V

3

5.6 M e V

4

1.1 M e V

PHXII13:NUCLEI

363687 The binding energy of two nuclei $p^{n}$ and $Q^{2 n}$ are joule $x$ and $y$ joule respectively. If $2 x > y,$ then the energy change in the reaction $p^{n} + p^{n} = Q^{2 n}$ will be

1

2 x - y

2

2 x + y

3

x + y

4

x y

Explanation:

Energy released $=$ intial $B E$ $-$ final $B E$ $= 2 x - y$

PHXII13:NUCLEI

363684 The binding energy per nucleon of dueterium and helium nuclei are $1.1 M e V$ and $7 M e V$ respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

1

24.6 M e V

2

25.1 M e V

3

22.3 M e V

4

23.6 M e V

Explanation:

$_{1} H^{2} +_{1} H^{2} \to 2 H e^{4} + Δ E$
The binding energy per nucleon of a deuterium $= 1.1 M e V$ .
$∴$ Total binding energy $= 4 \times 1.1 = 4.4 M e V$ .
The binding energy per nucleon of a helium nuclei $= 7 M e V$ .
$∴$ Total binding energy $= 4 \times 7 = 28 M e V$ .
Hence, energy released.
$Δ E = (28 - 4.4) M e V = 23.6 M e V .$

PHXII13:NUCLEI

363685 Pick out the correct statement from the following:

1 Energy released per unit mass of the reactant is less in case of fusion reaction

2 Packing fraction may be positive or may be negative

3

P u^{239}

is not suitable for a fission reaction

4 For stable nucleus, the specific binding energy is low

KCET - 2010

PHXII13:NUCLEI

363686 Average binding energy per nucleon over a wide range is

1

8 M e V

2

8.8 M e V

3

5.6 M e V

4

1.1 M e V

PHXII13:NUCLEI

363687 The binding energy of two nuclei $p^{n}$ and $Q^{2 n}$ are joule $x$ and $y$ joule respectively. If $2 x > y,$ then the energy change in the reaction $p^{n} + p^{n} = Q^{2 n}$ will be

1

2 x - y

2

2 x + y

3

x + y

4

x y

Explanation:

Energy released $=$ intial $B E$ $-$ final $B E$ $= 2 x - y$

PHXII13:NUCLEI

363684 The binding energy per nucleon of dueterium and helium nuclei are $1.1 M e V$ and $7 M e V$ respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

1

24.6 M e V

2

25.1 M e V

3

22.3 M e V

4

23.6 M e V

Explanation:

$_{1} H^{2} +_{1} H^{2} \to 2 H e^{4} + Δ E$
The binding energy per nucleon of a deuterium $= 1.1 M e V$ .
$∴$ Total binding energy $= 4 \times 1.1 = 4.4 M e V$ .
The binding energy per nucleon of a helium nuclei $= 7 M e V$ .
$∴$ Total binding energy $= 4 \times 7 = 28 M e V$ .
Hence, energy released.
$Δ E = (28 - 4.4) M e V = 23.6 M e V .$

PHXII13:NUCLEI

363685 Pick out the correct statement from the following:

1 Energy released per unit mass of the reactant is less in case of fusion reaction

2 Packing fraction may be positive or may be negative

3

P u^{239}

is not suitable for a fission reaction

4 For stable nucleus, the specific binding energy is low

KCET - 2010

PHXII13:NUCLEI

363686 Average binding energy per nucleon over a wide range is

1

8 M e V

2

8.8 M e V

3

5.6 M e V

4

1.1 M e V

PHXII13:NUCLEI

363687 The binding energy of two nuclei $p^{n}$ and $Q^{2 n}$ are joule $x$ and $y$ joule respectively. If $2 x > y,$ then the energy change in the reaction $p^{n} + p^{n} = Q^{2 n}$ will be

1

2 x - y

2

2 x + y

3

x + y

4

x y

Explanation:

Energy released $=$ intial $B E$ $-$ final $B E$ $= 2 x - y$

PHXII13:NUCLEI

363684 The binding energy per nucleon of dueterium and helium nuclei are $1.1 M e V$ and $7 M e V$ respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is:

1

24.6 M e V

2

25.1 M e V

3

22.3 M e V

4

23.6 M e V

Explanation:

$_{1} H^{2} +_{1} H^{2} \to 2 H e^{4} + Δ E$
The binding energy per nucleon of a deuterium $= 1.1 M e V$ .
$∴$ Total binding energy $= 4 \times 1.1 = 4.4 M e V$ .
The binding energy per nucleon of a helium nuclei $= 7 M e V$ .
$∴$ Total binding energy $= 4 \times 7 = 28 M e V$ .
Hence, energy released.
$Δ E = (28 - 4.4) M e V = 23.6 M e V .$

PHXII13:NUCLEI

363685 Pick out the correct statement from the following:

1 Energy released per unit mass of the reactant is less in case of fusion reaction

2 Packing fraction may be positive or may be negative

3

P u^{239}

is not suitable for a fission reaction

4 For stable nucleus, the specific binding energy is low

KCET - 2010

PHXII13:NUCLEI

363686 Average binding energy per nucleon over a wide range is

1

8 M e V

2

8.8 M e V

3

5.6 M e V

4

1.1 M e V

PHXII13:NUCLEI

363687 The binding energy of two nuclei $p^{n}$ and $Q^{2 n}$ are joule $x$ and $y$ joule respectively. If $2 x > y,$ then the energy change in the reaction $p^{n} + p^{n} = Q^{2 n}$ will be

1

2 x - y

2

2 x + y

3

x + y

4

x y

Explanation:

Energy released $=$ intial $B E$ $-$ final $B E$ $= 2 x - y$

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