Explanation:
If \(m = 1\,u,\;c = 3 \times {10^8}m{s^{ - 1}}\), then
\(E = 931\;MeV\) i.e., \(1\,u = 931\,MeV\)
Binding energy \( = 0.042 \times 931 = 39.10\,MeV\)
\(\therefore \) Binding ebergy per nucleon \( = \frac{{39.10}}{7} = 5.58 \approx 5.6\;MeV\)
into a lighter nucleus with higher specific binding energy,\({E_2} > {E_1}\)