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PHXII13:NUCLEI

363658 In the reaction $_{1}^{2} H +_{1}^{3} H \to_{2}^{4} H e +_{0}^{1} n,$ if the binding energies of $_{1}^{2} H,_{1}^{3} H$ and $_{2}^{4} H e$ are respectively $a, b$ and $c$ (in $M e V$ ) then the energy (in $M e V$ ) released is

1

a + b - c

2

a + b + c

3

c + a - b

4

c - a - b

Explanation:

$Q = (M_{P} - M_{R}) c^{2} = c - a - b$

PHXII13:NUCLEI

363659 The binding energies per nucleon of $L i^{7}$ and $H e^{4}$ are $5.6 MeV$ and $7.06 MeV$ respectively, then the energy of the reaction $L i^{7} + p \to 2 [_{2} H e^{4}]$ will be

1

39.2 M e V

2

17.28 M e V

3

1.46 M e V

4

28.24 M e V

Explanation:

The reaction is $_{3} L i^{7} +_{1} p^{1} \to 2 [_{2} H e^{4}]$
$E_{p} = 2 (4 \times 7.06) - 7 \times 5.6$
$= 56.48 - 39.2 = 17.28 M e V$

PHXII13:NUCLEI

363660 The binding energy per nucleon is maximum in the case of

1

_{26}^{56} F e

2

_{2}^{4} H e

3

_{92}^{235} U

4

_{56}^{141} B a

PHXII13:NUCLEI

363661 Mass numbers of the elements $A, B, C$ and $D$ are 30, 60, 90 and 120 respectively. The specific binding energy of them are $5 M e V, 8.5 M e V, 8 M e V$ and $7 M e V$ respectively. Then, in which of the following reactions energy is released? $(i) D \to 2 B (i i) C \to B + A$
(iii) $B \to 2 A$

1 In (ii), (iii)

2 Only in (i)

3 In (i), (iii)

4 In (i), (ii) and (iii)

Explanation:

If the energy is to be released then the products should have more $B$ . $E$ (More stable) than the reactants.
$D \to 2 B$
$120 \times 7 \to 2 \times 60 \times 8.5 (possible)$
$C \to B + A$
$90 \times 8 \to 60 \times 8.5 + 30 \times 5 (not p o s s i b l e)$
$B \to 2 A$
$60 \times 8.5 \to 2 \times 30 \times 5 (n o t p o s s i b l e)$
In only reaction (i) $D \to 2 B$ the $B$ . $E$ is more for products.

PHXII13:NUCLEI

363658 In the reaction $_{1}^{2} H +_{1}^{3} H \to_{2}^{4} H e +_{0}^{1} n,$ if the binding energies of $_{1}^{2} H,_{1}^{3} H$ and $_{2}^{4} H e$ are respectively $a, b$ and $c$ (in $M e V$ ) then the energy (in $M e V$ ) released is

1

a + b - c

2

a + b + c

3

c + a - b

4

c - a - b

Explanation:

$Q = (M_{P} - M_{R}) c^{2} = c - a - b$

PHXII13:NUCLEI

363659 The binding energies per nucleon of $L i^{7}$ and $H e^{4}$ are $5.6 MeV$ and $7.06 MeV$ respectively, then the energy of the reaction $L i^{7} + p \to 2 [_{2} H e^{4}]$ will be

1

39.2 M e V

2

17.28 M e V

3

1.46 M e V

4

28.24 M e V

Explanation:

The reaction is $_{3} L i^{7} +_{1} p^{1} \to 2 [_{2} H e^{4}]$
$E_{p} = 2 (4 \times 7.06) - 7 \times 5.6$
$= 56.48 - 39.2 = 17.28 M e V$

PHXII13:NUCLEI

363660 The binding energy per nucleon is maximum in the case of

1

_{26}^{56} F e

2

_{2}^{4} H e

3

_{92}^{235} U

4

_{56}^{141} B a

PHXII13:NUCLEI

363661 Mass numbers of the elements $A, B, C$ and $D$ are 30, 60, 90 and 120 respectively. The specific binding energy of them are $5 M e V, 8.5 M e V, 8 M e V$ and $7 M e V$ respectively. Then, in which of the following reactions energy is released? $(i) D \to 2 B (i i) C \to B + A$
(iii) $B \to 2 A$

1 In (ii), (iii)

2 Only in (i)

3 In (i), (iii)

4 In (i), (ii) and (iii)

Explanation:

If the energy is to be released then the products should have more $B$ . $E$ (More stable) than the reactants.
$D \to 2 B$
$120 \times 7 \to 2 \times 60 \times 8.5 (possible)$
$C \to B + A$
$90 \times 8 \to 60 \times 8.5 + 30 \times 5 (not p o s s i b l e)$
$B \to 2 A$
$60 \times 8.5 \to 2 \times 30 \times 5 (n o t p o s s i b l e)$
In only reaction (i) $D \to 2 B$ the $B$ . $E$ is more for products.

PHXII13:NUCLEI

363658 In the reaction $_{1}^{2} H +_{1}^{3} H \to_{2}^{4} H e +_{0}^{1} n,$ if the binding energies of $_{1}^{2} H,_{1}^{3} H$ and $_{2}^{4} H e$ are respectively $a, b$ and $c$ (in $M e V$ ) then the energy (in $M e V$ ) released is

1

a + b - c

2

a + b + c

3

c + a - b

4

c - a - b

Explanation:

$Q = (M_{P} - M_{R}) c^{2} = c - a - b$

PHXII13:NUCLEI

363659 The binding energies per nucleon of $L i^{7}$ and $H e^{4}$ are $5.6 MeV$ and $7.06 MeV$ respectively, then the energy of the reaction $L i^{7} + p \to 2 [_{2} H e^{4}]$ will be

1

39.2 M e V

2

17.28 M e V

3

1.46 M e V

4

28.24 M e V

Explanation:

The reaction is $_{3} L i^{7} +_{1} p^{1} \to 2 [_{2} H e^{4}]$
$E_{p} = 2 (4 \times 7.06) - 7 \times 5.6$
$= 56.48 - 39.2 = 17.28 M e V$

PHXII13:NUCLEI

363660 The binding energy per nucleon is maximum in the case of

1

_{26}^{56} F e

2

_{2}^{4} H e

3

_{92}^{235} U

4

_{56}^{141} B a

PHXII13:NUCLEI

363661 Mass numbers of the elements $A, B, C$ and $D$ are 30, 60, 90 and 120 respectively. The specific binding energy of them are $5 M e V, 8.5 M e V, 8 M e V$ and $7 M e V$ respectively. Then, in which of the following reactions energy is released? $(i) D \to 2 B (i i) C \to B + A$
(iii) $B \to 2 A$

1 In (ii), (iii)

2 Only in (i)

3 In (i), (iii)

4 In (i), (ii) and (iii)

Explanation:

If the energy is to be released then the products should have more $B$ . $E$ (More stable) than the reactants.
$D \to 2 B$
$120 \times 7 \to 2 \times 60 \times 8.5 (possible)$
$C \to B + A$
$90 \times 8 \to 60 \times 8.5 + 30 \times 5 (not p o s s i b l e)$
$B \to 2 A$
$60 \times 8.5 \to 2 \times 30 \times 5 (n o t p o s s i b l e)$
In only reaction (i) $D \to 2 B$ the $B$ . $E$ is more for products.

PHXII13:NUCLEI

363658 In the reaction $_{1}^{2} H +_{1}^{3} H \to_{2}^{4} H e +_{0}^{1} n,$ if the binding energies of $_{1}^{2} H,_{1}^{3} H$ and $_{2}^{4} H e$ are respectively $a, b$ and $c$ (in $M e V$ ) then the energy (in $M e V$ ) released is

1

a + b - c

2

a + b + c

3

c + a - b

4

c - a - b

Explanation:

$Q = (M_{P} - M_{R}) c^{2} = c - a - b$

PHXII13:NUCLEI

363659 The binding energies per nucleon of $L i^{7}$ and $H e^{4}$ are $5.6 MeV$ and $7.06 MeV$ respectively, then the energy of the reaction $L i^{7} + p \to 2 [_{2} H e^{4}]$ will be

1

39.2 M e V

2

17.28 M e V

3

1.46 M e V

4

28.24 M e V

Explanation:

The reaction is $_{3} L i^{7} +_{1} p^{1} \to 2 [_{2} H e^{4}]$
$E_{p} = 2 (4 \times 7.06) - 7 \times 5.6$
$= 56.48 - 39.2 = 17.28 M e V$

PHXII13:NUCLEI

363660 The binding energy per nucleon is maximum in the case of

1

_{26}^{56} F e

2

_{2}^{4} H e

3

_{92}^{235} U

4

_{56}^{141} B a

PHXII13:NUCLEI

363661 Mass numbers of the elements $A, B, C$ and $D$ are 30, 60, 90 and 120 respectively. The specific binding energy of them are $5 M e V, 8.5 M e V, 8 M e V$ and $7 M e V$ respectively. Then, in which of the following reactions energy is released? $(i) D \to 2 B (i i) C \to B + A$
(iii) $B \to 2 A$

1 In (ii), (iii)

2 Only in (i)

3 In (i), (iii)

4 In (i), (ii) and (iii)

Explanation:

If the energy is to be released then the products should have more $B$ . $E$ (More stable) than the reactants.
$D \to 2 B$
$120 \times 7 \to 2 \times 60 \times 8.5 (possible)$
$C \to B + A$
$90 \times 8 \to 60 \times 8.5 + 30 \times 5 (not p o s s i b l e)$
$B \to 2 A$
$60 \times 8.5 \to 2 \times 30 \times 5 (n o t p o s s i b l e)$
In only reaction (i) $D \to 2 B$ the $B$ . $E$ is more for products.

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