Explanation:
Mass of child \( = 5\;kg\),
Radius of merry-go-round \( = 2{\mkern 1mu} \,m\)
Angular velocity \(\omega=\dfrac{2 \pi}{T}=\dfrac{2 \times 3.14}{3.14}\)
\(F_{c}=m \omega^{2} R\)
\( \Rightarrow \omega = 2\,rad{\rm{/}}s\)
\(\therefore F_{C}=\) Contribugal Force
\(=m \omega^{2} R\)
\( = 5 \times {(2)^2} \times 2\,N = 40\,N\)