Explanation:
For moving on circular path without slipping, centrifugal force must be equal to frictional force.
That is,
\( \Rightarrow mr\,{\omega ^2} = \mu \,m\,g\,\,\,\,\,\,\,\,\,\,\left[ {\therefore v = r\omega } \right]\)
\( \Rightarrow r\,{\omega ^2} = \mu \,\,g\)
\(\therefore \omega = \sqrt {\frac{{\mu \,g}}{r}} = \sqrt {\frac{{0.5 \times 9.8}}{{10}}} = \,0.7\,rad/s.\,\)