Applications of Newton’s Laws
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NEET DIGITAL LIBRARY
PHXI05:LAWS OF MOTION

363177 A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is \(2: 1\), find the acceleration of the lift (Take \(g=10 {~m} / {s}^{2}\) ).

1 \(2.37\,m/{s^2}\)
2 \(3.33\,m/{s^2}\)
3 \(5.42\,m/{s^2}\)
4 \(1.75\,m/{s^2}\)
PHXI05:LAWS OF MOTION

363178 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is \(T\). With what acceleration should the lift be accelerated upwards in order to reduce its period to \(T/2\)? (\(g\) is acceleration due to gravity).

1 \(4\,g\)
2 \(g\)
3 2 \(g\)
4 3 \(g\)
KCET - 2008
PHXI05:LAWS OF MOTION

363179 A reference frame attached to earth cannot be an inertial frame because

1 earth is revolving around the sun
2 earth is rotating about its axis
3 Newton's laws are applicable in this frame
4 both (1) and (2)
PHXI05:LAWS OF MOTION

363180 A pendulum of mass \(m\) hangs from a support fixed to a trolley. The direction of the string when the trolley rolls up a plane of inclination \(\alpha \) with acceleration \({a_0}\) is
supporting img

1 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0}}}{g}} \right)\)
2 \(\theta = {\tan ^{ - 1}}\alpha \)
3 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0} + g\sin \alpha }}{{g\cos \alpha }}} \right)\)
4 \(\theta = {\tan ^{ - 1}}\left( {\frac{g}{{{a_0}}}} \right)\)
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PHXI05:LAWS OF MOTION

363177 A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is \(2: 1\), find the acceleration of the lift (Take \(g=10 {~m} / {s}^{2}\) ).

1 \(2.37\,m/{s^2}\)
2 \(3.33\,m/{s^2}\)
3 \(5.42\,m/{s^2}\)
4 \(1.75\,m/{s^2}\)
PHXI05:LAWS OF MOTION

363178 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is \(T\). With what acceleration should the lift be accelerated upwards in order to reduce its period to \(T/2\)? (\(g\) is acceleration due to gravity).

1 \(4\,g\)
2 \(g\)
3 2 \(g\)
4 3 \(g\)
KCET - 2008
PHXI05:LAWS OF MOTION

363179 A reference frame attached to earth cannot be an inertial frame because

1 earth is revolving around the sun
2 earth is rotating about its axis
3 Newton's laws are applicable in this frame
4 both (1) and (2)
PHXI05:LAWS OF MOTION

363180 A pendulum of mass \(m\) hangs from a support fixed to a trolley. The direction of the string when the trolley rolls up a plane of inclination \(\alpha \) with acceleration \({a_0}\) is
supporting img

1 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0}}}{g}} \right)\)
2 \(\theta = {\tan ^{ - 1}}\alpha \)
3 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0} + g\sin \alpha }}{{g\cos \alpha }}} \right)\)
4 \(\theta = {\tan ^{ - 1}}\left( {\frac{g}{{{a_0}}}} \right)\)
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PHXI05:LAWS OF MOTION

363177 A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is \(2: 1\), find the acceleration of the lift (Take \(g=10 {~m} / {s}^{2}\) ).

1 \(2.37\,m/{s^2}\)
2 \(3.33\,m/{s^2}\)
3 \(5.42\,m/{s^2}\)
4 \(1.75\,m/{s^2}\)
PHXI05:LAWS OF MOTION

363178 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is \(T\). With what acceleration should the lift be accelerated upwards in order to reduce its period to \(T/2\)? (\(g\) is acceleration due to gravity).

1 \(4\,g\)
2 \(g\)
3 2 \(g\)
4 3 \(g\)
KCET - 2008
PHXI05:LAWS OF MOTION

363179 A reference frame attached to earth cannot be an inertial frame because

1 earth is revolving around the sun
2 earth is rotating about its axis
3 Newton's laws are applicable in this frame
4 both (1) and (2)
PHXI05:LAWS OF MOTION

363180 A pendulum of mass \(m\) hangs from a support fixed to a trolley. The direction of the string when the trolley rolls up a plane of inclination \(\alpha \) with acceleration \({a_0}\) is
supporting img

1 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0}}}{g}} \right)\)
2 \(\theta = {\tan ^{ - 1}}\alpha \)
3 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0} + g\sin \alpha }}{{g\cos \alpha }}} \right)\)
4 \(\theta = {\tan ^{ - 1}}\left( {\frac{g}{{{a_0}}}} \right)\)
NEET DIGITAL LIBRARY
PHXI05:LAWS OF MOTION

363177 A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is \(2: 1\), find the acceleration of the lift (Take \(g=10 {~m} / {s}^{2}\) ).

1 \(2.37\,m/{s^2}\)
2 \(3.33\,m/{s^2}\)
3 \(5.42\,m/{s^2}\)
4 \(1.75\,m/{s^2}\)
PHXI05:LAWS OF MOTION

363178 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is \(T\). With what acceleration should the lift be accelerated upwards in order to reduce its period to \(T/2\)? (\(g\) is acceleration due to gravity).

1 \(4\,g\)
2 \(g\)
3 2 \(g\)
4 3 \(g\)
KCET - 2008
PHXI05:LAWS OF MOTION

363179 A reference frame attached to earth cannot be an inertial frame because

1 earth is revolving around the sun
2 earth is rotating about its axis
3 Newton's laws are applicable in this frame
4 both (1) and (2)
PHXI05:LAWS OF MOTION

363180 A pendulum of mass \(m\) hangs from a support fixed to a trolley. The direction of the string when the trolley rolls up a plane of inclination \(\alpha \) with acceleration \({a_0}\) is
supporting img

1 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0}}}{g}} \right)\)
2 \(\theta = {\tan ^{ - 1}}\alpha \)
3 \(\theta = {\tan ^{ - 1}}\left( {\frac{{{a_0} + g\sin \alpha }}{{g\cos \alpha }}} \right)\)
4 \(\theta = {\tan ^{ - 1}}\left( {\frac{g}{{{a_0}}}} \right)\)
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