363130
A monkey of mass \(m\,kg\) slides down a light rope attached to a fixed spring balance, with an acceleration \(a\). The reading of this balance is \(w k g\), then ( \(g=\) acceleration due to gravity)
1 \({m = \frac{{wg}}{{g - a}}}\)
2 \({m = w\left( {1 + \frac{a}{g}} \right)}\)
3 The force of friction exerted by the rope on the monkey in \(m(g-a)\) newton
4 The tension in the rope is \(w g\) newton.
Explanation:
The reading of the spring balance \(=\) Tension in the rope \(=\) Force of friction between the rope and monkey \(=m g-m a=m(g-a) N\)
AIIMS - 2009
PHXI05:LAWS OF MOTION
363131
As shown in figure, a \(70\;kg\) garden roller is pushed with a force of \(F = 200\;N\) at an angle of \(30^{\circ}\) with horizontal. The normal reaction on the roller is (Given \(g = 10\;m{s^{ - 2}}\))
1 \(800\;N\)
2 \(600\;N\)
3 \(200\sqrt 3 \,N\)
4 \(800\sqrt 2 \,N\)
Explanation:
\(\therefore\) Force exerted \(=\dfrac{200 m V}{t}\) Normal reaction on roller \(=\) weight + Vertical component of \(F\). \( = 700 + 200 \times \frac{1}{2} = 800\;N\)
JEE - 2023
PHXI05:LAWS OF MOTION
363132
In a free body diagram of a body
1 All forces exerted by the body are shown
2 All forces exerted on the body are shown
3 All forces including internal and external are shown
4 None of these
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363133
A particle moving with velocity \({\vec V}\) is acted by three forces shown by the vector triangle \(PQR\). The velocity of the particle will :
1 Increase
2 Decrease
3 Remain constant
4 Change according to the smallest force \(\overrightarrow {QR} \)
Explanation:
As forces are forming closed loop in same order So, \({\overrightarrow F _{net}} = 0 \Rightarrow \vec a = 0\) \( \Rightarrow \,\,\,\overrightarrow v = {\rm{constant}}\)
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PHXI05:LAWS OF MOTION
363130
A monkey of mass \(m\,kg\) slides down a light rope attached to a fixed spring balance, with an acceleration \(a\). The reading of this balance is \(w k g\), then ( \(g=\) acceleration due to gravity)
1 \({m = \frac{{wg}}{{g - a}}}\)
2 \({m = w\left( {1 + \frac{a}{g}} \right)}\)
3 The force of friction exerted by the rope on the monkey in \(m(g-a)\) newton
4 The tension in the rope is \(w g\) newton.
Explanation:
The reading of the spring balance \(=\) Tension in the rope \(=\) Force of friction between the rope and monkey \(=m g-m a=m(g-a) N\)
AIIMS - 2009
PHXI05:LAWS OF MOTION
363131
As shown in figure, a \(70\;kg\) garden roller is pushed with a force of \(F = 200\;N\) at an angle of \(30^{\circ}\) with horizontal. The normal reaction on the roller is (Given \(g = 10\;m{s^{ - 2}}\))
1 \(800\;N\)
2 \(600\;N\)
3 \(200\sqrt 3 \,N\)
4 \(800\sqrt 2 \,N\)
Explanation:
\(\therefore\) Force exerted \(=\dfrac{200 m V}{t}\) Normal reaction on roller \(=\) weight + Vertical component of \(F\). \( = 700 + 200 \times \frac{1}{2} = 800\;N\)
JEE - 2023
PHXI05:LAWS OF MOTION
363132
In a free body diagram of a body
1 All forces exerted by the body are shown
2 All forces exerted on the body are shown
3 All forces including internal and external are shown
4 None of these
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363133
A particle moving with velocity \({\vec V}\) is acted by three forces shown by the vector triangle \(PQR\). The velocity of the particle will :
1 Increase
2 Decrease
3 Remain constant
4 Change according to the smallest force \(\overrightarrow {QR} \)
Explanation:
As forces are forming closed loop in same order So, \({\overrightarrow F _{net}} = 0 \Rightarrow \vec a = 0\) \( \Rightarrow \,\,\,\overrightarrow v = {\rm{constant}}\)
363130
A monkey of mass \(m\,kg\) slides down a light rope attached to a fixed spring balance, with an acceleration \(a\). The reading of this balance is \(w k g\), then ( \(g=\) acceleration due to gravity)
1 \({m = \frac{{wg}}{{g - a}}}\)
2 \({m = w\left( {1 + \frac{a}{g}} \right)}\)
3 The force of friction exerted by the rope on the monkey in \(m(g-a)\) newton
4 The tension in the rope is \(w g\) newton.
Explanation:
The reading of the spring balance \(=\) Tension in the rope \(=\) Force of friction between the rope and monkey \(=m g-m a=m(g-a) N\)
AIIMS - 2009
PHXI05:LAWS OF MOTION
363131
As shown in figure, a \(70\;kg\) garden roller is pushed with a force of \(F = 200\;N\) at an angle of \(30^{\circ}\) with horizontal. The normal reaction on the roller is (Given \(g = 10\;m{s^{ - 2}}\))
1 \(800\;N\)
2 \(600\;N\)
3 \(200\sqrt 3 \,N\)
4 \(800\sqrt 2 \,N\)
Explanation:
\(\therefore\) Force exerted \(=\dfrac{200 m V}{t}\) Normal reaction on roller \(=\) weight + Vertical component of \(F\). \( = 700 + 200 \times \frac{1}{2} = 800\;N\)
JEE - 2023
PHXI05:LAWS OF MOTION
363132
In a free body diagram of a body
1 All forces exerted by the body are shown
2 All forces exerted on the body are shown
3 All forces including internal and external are shown
4 None of these
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363133
A particle moving with velocity \({\vec V}\) is acted by three forces shown by the vector triangle \(PQR\). The velocity of the particle will :
1 Increase
2 Decrease
3 Remain constant
4 Change according to the smallest force \(\overrightarrow {QR} \)
Explanation:
As forces are forming closed loop in same order So, \({\overrightarrow F _{net}} = 0 \Rightarrow \vec a = 0\) \( \Rightarrow \,\,\,\overrightarrow v = {\rm{constant}}\)
363130
A monkey of mass \(m\,kg\) slides down a light rope attached to a fixed spring balance, with an acceleration \(a\). The reading of this balance is \(w k g\), then ( \(g=\) acceleration due to gravity)
1 \({m = \frac{{wg}}{{g - a}}}\)
2 \({m = w\left( {1 + \frac{a}{g}} \right)}\)
3 The force of friction exerted by the rope on the monkey in \(m(g-a)\) newton
4 The tension in the rope is \(w g\) newton.
Explanation:
The reading of the spring balance \(=\) Tension in the rope \(=\) Force of friction between the rope and monkey \(=m g-m a=m(g-a) N\)
AIIMS - 2009
PHXI05:LAWS OF MOTION
363131
As shown in figure, a \(70\;kg\) garden roller is pushed with a force of \(F = 200\;N\) at an angle of \(30^{\circ}\) with horizontal. The normal reaction on the roller is (Given \(g = 10\;m{s^{ - 2}}\))
1 \(800\;N\)
2 \(600\;N\)
3 \(200\sqrt 3 \,N\)
4 \(800\sqrt 2 \,N\)
Explanation:
\(\therefore\) Force exerted \(=\dfrac{200 m V}{t}\) Normal reaction on roller \(=\) weight + Vertical component of \(F\). \( = 700 + 200 \times \frac{1}{2} = 800\;N\)
JEE - 2023
PHXI05:LAWS OF MOTION
363132
In a free body diagram of a body
1 All forces exerted by the body are shown
2 All forces exerted on the body are shown
3 All forces including internal and external are shown
4 None of these
Explanation:
Conceptual Question
PHXI05:LAWS OF MOTION
363133
A particle moving with velocity \({\vec V}\) is acted by three forces shown by the vector triangle \(PQR\). The velocity of the particle will :
1 Increase
2 Decrease
3 Remain constant
4 Change according to the smallest force \(\overrightarrow {QR} \)
Explanation:
As forces are forming closed loop in same order So, \({\overrightarrow F _{net}} = 0 \Rightarrow \vec a = 0\) \( \Rightarrow \,\,\,\overrightarrow v = {\rm{constant}}\)
