Force between Current Carrying Wires
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PHXII04:MOVING CHARGES AND MAGNETISM

362689 Figure shows an infinitely long wire carrying an outward current \({I_1}\). The current is along \(Z\) axis. There is a curved wire in \(x-y\) plane carrying current \(I_{2}\). The magnetic force on this wire between \(\left( {{x_1},{y_1}} \right)\)) and \(\left( {{x_2},{y_2}} \right)\) is:
supporting img

1 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
2 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {x_2^2{\text{ }} + {\text{ }}y_2^2} \right)}}{{\left( {x_1^2{\text{ }} + {\text{ }}y_1^2} \right)}}\)
3 \(\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}\ln \frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
4 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {{x_2} + {y_2}} \right)}}{{\left( {{x_1} + {y_1}} \right)}}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362690 Consider the diagrams shown. Work done intransferring wire from position (1) to position (2) is \(W_{1}\). Work done in transferring the wire from position (3) to position (4) is \(W_{2}\) then
supporting img

1 \(\frac{{{W_1}}}{{{W_2}}} > 1\)
2 \(\dfrac{W_{1}}{W_{2}} < 1\)
3 \(W_{1}=W_{2}=0\)
4 \(W_{1}\) is positive, \(W_{2}\) is zero
NCERT Exemplar
PHXII04:MOVING CHARGES AND MAGNETISM

362691 The length of the conductor and carrying current \(I_{2}\) is \(l\). The force acting on it due to a long current carrying conductor which carries a current \(I_{1}\) is
supporting img

1 \(\dfrac{\mu_{0} I_{1} I_{2}}{2 \pi} \log _{e} \dfrac{x+l}{x}\)
2 \(\dfrac{\mu_{0} I_{1} I_{2}}{4 \pi} \log _{e} \dfrac{x-l}{x}\)
3 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x}{x+l}\)
4 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x-2}{x}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362692 A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop
supporting img

1 Experiences a force away from wire
2 Experiences a force towards wire
3 Experiences no force
4 Experiences a torque but no force
PHXII04:MOVING CHARGES AND MAGNETISM

362693 The resultant force on the current loop \(P Q R S\) due to a long current arrying conductor will be
supporting img

1 \(1.8 \times {10^{ - 4}}\;N\)
2 \(5 \times {10^{ - 4}}\;N\)
3 \({10^{ - 4}}\;N\)
4 \(3.6 \times {10^{ - 4}}\;N\)
KCET - 2008
NEET DIGITAL LIBRARY
PHXII04:MOVING CHARGES AND MAGNETISM

362689 Figure shows an infinitely long wire carrying an outward current \({I_1}\). The current is along \(Z\) axis. There is a curved wire in \(x-y\) plane carrying current \(I_{2}\). The magnetic force on this wire between \(\left( {{x_1},{y_1}} \right)\)) and \(\left( {{x_2},{y_2}} \right)\) is:
supporting img

1 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
2 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {x_2^2{\text{ }} + {\text{ }}y_2^2} \right)}}{{\left( {x_1^2{\text{ }} + {\text{ }}y_1^2} \right)}}\)
3 \(\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}\ln \frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
4 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {{x_2} + {y_2}} \right)}}{{\left( {{x_1} + {y_1}} \right)}}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362690 Consider the diagrams shown. Work done intransferring wire from position (1) to position (2) is \(W_{1}\). Work done in transferring the wire from position (3) to position (4) is \(W_{2}\) then
supporting img

1 \(\frac{{{W_1}}}{{{W_2}}} > 1\)
2 \(\dfrac{W_{1}}{W_{2}} < 1\)
3 \(W_{1}=W_{2}=0\)
4 \(W_{1}\) is positive, \(W_{2}\) is zero
NCERT Exemplar
PHXII04:MOVING CHARGES AND MAGNETISM

362691 The length of the conductor and carrying current \(I_{2}\) is \(l\). The force acting on it due to a long current carrying conductor which carries a current \(I_{1}\) is
supporting img

1 \(\dfrac{\mu_{0} I_{1} I_{2}}{2 \pi} \log _{e} \dfrac{x+l}{x}\)
2 \(\dfrac{\mu_{0} I_{1} I_{2}}{4 \pi} \log _{e} \dfrac{x-l}{x}\)
3 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x}{x+l}\)
4 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x-2}{x}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362692 A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop
supporting img

1 Experiences a force away from wire
2 Experiences a force towards wire
3 Experiences no force
4 Experiences a torque but no force
PHXII04:MOVING CHARGES AND MAGNETISM

362693 The resultant force on the current loop \(P Q R S\) due to a long current arrying conductor will be
supporting img

1 \(1.8 \times {10^{ - 4}}\;N\)
2 \(5 \times {10^{ - 4}}\;N\)
3 \({10^{ - 4}}\;N\)
4 \(3.6 \times {10^{ - 4}}\;N\)
KCET - 2008
Join With Us for More Updates
PHXII04:MOVING CHARGES AND MAGNETISM

362689 Figure shows an infinitely long wire carrying an outward current \({I_1}\). The current is along \(Z\) axis. There is a curved wire in \(x-y\) plane carrying current \(I_{2}\). The magnetic force on this wire between \(\left( {{x_1},{y_1}} \right)\)) and \(\left( {{x_2},{y_2}} \right)\) is:
supporting img

1 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
2 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {x_2^2{\text{ }} + {\text{ }}y_2^2} \right)}}{{\left( {x_1^2{\text{ }} + {\text{ }}y_1^2} \right)}}\)
3 \(\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}\ln \frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
4 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {{x_2} + {y_2}} \right)}}{{\left( {{x_1} + {y_1}} \right)}}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362690 Consider the diagrams shown. Work done intransferring wire from position (1) to position (2) is \(W_{1}\). Work done in transferring the wire from position (3) to position (4) is \(W_{2}\) then
supporting img

1 \(\frac{{{W_1}}}{{{W_2}}} > 1\)
2 \(\dfrac{W_{1}}{W_{2}} < 1\)
3 \(W_{1}=W_{2}=0\)
4 \(W_{1}\) is positive, \(W_{2}\) is zero
NCERT Exemplar
PHXII04:MOVING CHARGES AND MAGNETISM

362691 The length of the conductor and carrying current \(I_{2}\) is \(l\). The force acting on it due to a long current carrying conductor which carries a current \(I_{1}\) is
supporting img

1 \(\dfrac{\mu_{0} I_{1} I_{2}}{2 \pi} \log _{e} \dfrac{x+l}{x}\)
2 \(\dfrac{\mu_{0} I_{1} I_{2}}{4 \pi} \log _{e} \dfrac{x-l}{x}\)
3 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x}{x+l}\)
4 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x-2}{x}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362692 A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop
supporting img

1 Experiences a force away from wire
2 Experiences a force towards wire
3 Experiences no force
4 Experiences a torque but no force
PHXII04:MOVING CHARGES AND MAGNETISM

362693 The resultant force on the current loop \(P Q R S\) due to a long current arrying conductor will be
supporting img

1 \(1.8 \times {10^{ - 4}}\;N\)
2 \(5 \times {10^{ - 4}}\;N\)
3 \({10^{ - 4}}\;N\)
4 \(3.6 \times {10^{ - 4}}\;N\)
KCET - 2008
For More Updates join with Us
PHXII04:MOVING CHARGES AND MAGNETISM

362689 Figure shows an infinitely long wire carrying an outward current \({I_1}\). The current is along \(Z\) axis. There is a curved wire in \(x-y\) plane carrying current \(I_{2}\). The magnetic force on this wire between \(\left( {{x_1},{y_1}} \right)\)) and \(\left( {{x_2},{y_2}} \right)\) is:
supporting img

1 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
2 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {x_2^2{\text{ }} + {\text{ }}y_2^2} \right)}}{{\left( {x_1^2{\text{ }} + {\text{ }}y_1^2} \right)}}\)
3 \(\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}\ln \frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
4 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {{x_2} + {y_2}} \right)}}{{\left( {{x_1} + {y_1}} \right)}}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362690 Consider the diagrams shown. Work done intransferring wire from position (1) to position (2) is \(W_{1}\). Work done in transferring the wire from position (3) to position (4) is \(W_{2}\) then
supporting img

1 \(\frac{{{W_1}}}{{{W_2}}} > 1\)
2 \(\dfrac{W_{1}}{W_{2}} < 1\)
3 \(W_{1}=W_{2}=0\)
4 \(W_{1}\) is positive, \(W_{2}\) is zero
NCERT Exemplar
PHXII04:MOVING CHARGES AND MAGNETISM

362691 The length of the conductor and carrying current \(I_{2}\) is \(l\). The force acting on it due to a long current carrying conductor which carries a current \(I_{1}\) is
supporting img

1 \(\dfrac{\mu_{0} I_{1} I_{2}}{2 \pi} \log _{e} \dfrac{x+l}{x}\)
2 \(\dfrac{\mu_{0} I_{1} I_{2}}{4 \pi} \log _{e} \dfrac{x-l}{x}\)
3 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x}{x+l}\)
4 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x-2}{x}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362692 A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop
supporting img

1 Experiences a force away from wire
2 Experiences a force towards wire
3 Experiences no force
4 Experiences a torque but no force
PHXII04:MOVING CHARGES AND MAGNETISM

362693 The resultant force on the current loop \(P Q R S\) due to a long current arrying conductor will be
supporting img

1 \(1.8 \times {10^{ - 4}}\;N\)
2 \(5 \times {10^{ - 4}}\;N\)
3 \({10^{ - 4}}\;N\)
4 \(3.6 \times {10^{ - 4}}\;N\)
KCET - 2008
NEET DIGITAL LIBRARY
PHXII04:MOVING CHARGES AND MAGNETISM

362689 Figure shows an infinitely long wire carrying an outward current \({I_1}\). The current is along \(Z\) axis. There is a curved wire in \(x-y\) plane carrying current \(I_{2}\). The magnetic force on this wire between \(\left( {{x_1},{y_1}} \right)\)) and \(\left( {{x_2},{y_2}} \right)\) is:
supporting img

1 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
2 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {x_2^2{\text{ }} + {\text{ }}y_2^2} \right)}}{{\left( {x_1^2{\text{ }} + {\text{ }}y_1^2} \right)}}\)
3 \(\frac{{{\mu _0}{I_1}{I_2}}}{{2\pi }}\ln \frac{{\left( {x_2^2 + y_2^2} \right)}}{{\left( {x_1^2 + y_1^2} \right)}}\)
4 \(\frac{{{\mu _0}{I_1}{I_2}}}{{4\pi }}\ln \frac{{\left( {{x_2} + {y_2}} \right)}}{{\left( {{x_1} + {y_1}} \right)}}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362690 Consider the diagrams shown. Work done intransferring wire from position (1) to position (2) is \(W_{1}\). Work done in transferring the wire from position (3) to position (4) is \(W_{2}\) then
supporting img

1 \(\frac{{{W_1}}}{{{W_2}}} > 1\)
2 \(\dfrac{W_{1}}{W_{2}} < 1\)
3 \(W_{1}=W_{2}=0\)
4 \(W_{1}\) is positive, \(W_{2}\) is zero
NCERT Exemplar
PHXII04:MOVING CHARGES AND MAGNETISM

362691 The length of the conductor and carrying current \(I_{2}\) is \(l\). The force acting on it due to a long current carrying conductor which carries a current \(I_{1}\) is
supporting img

1 \(\dfrac{\mu_{0} I_{1} I_{2}}{2 \pi} \log _{e} \dfrac{x+l}{x}\)
2 \(\dfrac{\mu_{0} I_{1} I_{2}}{4 \pi} \log _{e} \dfrac{x-l}{x}\)
3 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x}{x+l}\)
4 \(\dfrac{\mu_{0} I_{1} I_{2}}{\pi} \log _{e} \dfrac{x-2}{x}\)
PHXII04:MOVING CHARGES AND MAGNETISM

362692 A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop
supporting img

1 Experiences a force away from wire
2 Experiences a force towards wire
3 Experiences no force
4 Experiences a torque but no force
PHXII04:MOVING CHARGES AND MAGNETISM

362693 The resultant force on the current loop \(P Q R S\) due to a long current arrying conductor will be
supporting img

1 \(1.8 \times {10^{ - 4}}\;N\)
2 \(5 \times {10^{ - 4}}\;N\)
3 \({10^{ - 4}}\;N\)
4 \(3.6 \times {10^{ - 4}}\;N\)
KCET - 2008