362293 A particle starts with an initial velocity of \(10.0\;m{s^{ - 1}}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\;m{s^{ - 2}}\) The time taken by the particle to reach the velocity of \(60.0\;m{s^{ - 1}}\) is

362294 A car moving with a velocity of \(20\,m{s^{ - 1}}\) is stopped in a distance of \(40 \, m\). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

362295 A body moving with a speed \({v}\) can be stopped over a distance \({x}\). If its kinetic energy is doubled, how much would be the stopping distance, for the same retarding force?

362296 Assertion :
Area under velocity-time graph gives displacement.
Reason :
Area under acceleration-time graph gives velocity.

362297 A particle starts with a velocity of \(2\,m{s^{ - 1}}\) and moves in a straight line with a retardation of \(0.1\,m{s^{ - 2}}\). The first time at which the particle is \(15\,m\) from the starting point is

362293 A particle starts with an initial velocity of \(10.0\;m{s^{ - 1}}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\;m{s^{ - 2}}\) The time taken by the particle to reach the velocity of \(60.0\;m{s^{ - 1}}\) is

362294 A car moving with a velocity of \(20\,m{s^{ - 1}}\) is stopped in a distance of \(40 \, m\). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

362295 A body moving with a speed \({v}\) can be stopped over a distance \({x}\). If its kinetic energy is doubled, how much would be the stopping distance, for the same retarding force?

362296 Assertion :
Area under velocity-time graph gives displacement.
Reason :
Area under acceleration-time graph gives velocity.

362297 A particle starts with a velocity of \(2\,m{s^{ - 1}}\) and moves in a straight line with a retardation of \(0.1\,m{s^{ - 2}}\). The first time at which the particle is \(15\,m\) from the starting point is

362293 A particle starts with an initial velocity of \(10.0\;m{s^{ - 1}}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\;m{s^{ - 2}}\) The time taken by the particle to reach the velocity of \(60.0\;m{s^{ - 1}}\) is

362294 A car moving with a velocity of \(20\,m{s^{ - 1}}\) is stopped in a distance of \(40 \, m\). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

362295 A body moving with a speed \({v}\) can be stopped over a distance \({x}\). If its kinetic energy is doubled, how much would be the stopping distance, for the same retarding force?

362296 Assertion :
Area under velocity-time graph gives displacement.
Reason :
Area under acceleration-time graph gives velocity.

362297 A particle starts with a velocity of \(2\,m{s^{ - 1}}\) and moves in a straight line with a retardation of \(0.1\,m{s^{ - 2}}\). The first time at which the particle is \(15\,m\) from the starting point is

362293 A particle starts with an initial velocity of \(10.0\;m{s^{ - 1}}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\;m{s^{ - 2}}\) The time taken by the particle to reach the velocity of \(60.0\;m{s^{ - 1}}\) is

362294 A car moving with a velocity of \(20\,m{s^{ - 1}}\) is stopped in a distance of \(40 \, m\). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

362295 A body moving with a speed \({v}\) can be stopped over a distance \({x}\). If its kinetic energy is doubled, how much would be the stopping distance, for the same retarding force?

362296 Assertion :
Area under velocity-time graph gives displacement.
Reason :
Area under acceleration-time graph gives velocity.

362297 A particle starts with a velocity of \(2\,m{s^{ - 1}}\) and moves in a straight line with a retardation of \(0.1\,m{s^{ - 2}}\). The first time at which the particle is \(15\,m\) from the starting point is

362293 A particle starts with an initial velocity of \(10.0\;m{s^{ - 1}}\) along \(x\)-direction and accelerates uniformly at the rate of \(2.0\;m{s^{ - 2}}\) The time taken by the particle to reach the velocity of \(60.0\;m{s^{ - 1}}\) is

362294 A car moving with a velocity of \(20\,m{s^{ - 1}}\) is stopped in a distance of \(40 \, m\). If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

362295 A body moving with a speed \({v}\) can be stopped over a distance \({x}\). If its kinetic energy is doubled, how much would be the stopping distance, for the same retarding force?

362296 Assertion :
Area under velocity-time graph gives displacement.
Reason :
Area under acceleration-time graph gives velocity.

362297 A particle starts with a velocity of \(2\,m{s^{ - 1}}\) and moves in a straight line with a retardation of \(0.1\,m{s^{ - 2}}\). The first time at which the particle is \(15\,m\) from the starting point is