362289
Which of the following graphs cannot possibly represent one-dimensional motion of a particle?
1 I and II
2 II and III
3 II and IV
4 All of these
Explanation:
Graph (I) does not represent the one dimensional motion, because total distance covered by a particle always increases with time. Graph (II) and Graph (III) do not represent the one-dimensional motion,because at a particular time, there cannot be two values of position or velocity. Graph (IV) is not possible, because speed can never be negative.
PHXI03:MOTION IN A STRAIGHT LINE
362290
A 150 \(m\) long train is moving with a uniform velocity of 45 \(km/h\). The time taken by the train to cross a bridge of length 850 \(m\) is
1 \(80\,\sec \)
2 \(70\,\sec \)
3 \(92\,\sec \)
4 \(68\,\sec \)
Explanation:
Total distance to be covered for crossing the bridge \( = \) length of train \( + \) length of bridge \( = 150\,m + 850\,m = 1000\,m\) \(\rm{Time} = \frac{{\rm{Distance}}}{{\rm{Velocity}}} = \frac{{1000}}{{45 \times \frac{5}{{18}}}} = 80\sec \)
PHXI03:MOTION IN A STRAIGHT LINE
362291
A particle located at \(x = 0\) at time \(t = 0\), starts moving along the positive \(x\) - direction with a velocity \('v'\) that varies as \(v = a\sqrt x .\) The displacement of the particle varies with time as
1 \(t\)
2 \({t^{3/2}}\)
3 \({t^3}\)
4 \({t^2}\)
Explanation:
\(v = \alpha \sqrt x \Rightarrow \frac{{dx}}{{dt}} = \alpha \sqrt x \Rightarrow \frac{{dx}}{{\sqrt x }} = \alpha \,dt\) By integrating both sides \(\int {{x^{ - 1/2}}dx = \int {\alpha \,dt} } \) \(\therefore \;x \propto {t^2}\)
PHXI03:MOTION IN A STRAIGHT LINE
362292
The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^{3}\) and \(y=\beta t^{3}\). The speed of the particle at time \(t\) is given by:
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI03:MOTION IN A STRAIGHT LINE
362289
Which of the following graphs cannot possibly represent one-dimensional motion of a particle?
1 I and II
2 II and III
3 II and IV
4 All of these
Explanation:
Graph (I) does not represent the one dimensional motion, because total distance covered by a particle always increases with time. Graph (II) and Graph (III) do not represent the one-dimensional motion,because at a particular time, there cannot be two values of position or velocity. Graph (IV) is not possible, because speed can never be negative.
PHXI03:MOTION IN A STRAIGHT LINE
362290
A 150 \(m\) long train is moving with a uniform velocity of 45 \(km/h\). The time taken by the train to cross a bridge of length 850 \(m\) is
1 \(80\,\sec \)
2 \(70\,\sec \)
3 \(92\,\sec \)
4 \(68\,\sec \)
Explanation:
Total distance to be covered for crossing the bridge \( = \) length of train \( + \) length of bridge \( = 150\,m + 850\,m = 1000\,m\) \(\rm{Time} = \frac{{\rm{Distance}}}{{\rm{Velocity}}} = \frac{{1000}}{{45 \times \frac{5}{{18}}}} = 80\sec \)
PHXI03:MOTION IN A STRAIGHT LINE
362291
A particle located at \(x = 0\) at time \(t = 0\), starts moving along the positive \(x\) - direction with a velocity \('v'\) that varies as \(v = a\sqrt x .\) The displacement of the particle varies with time as
1 \(t\)
2 \({t^{3/2}}\)
3 \({t^3}\)
4 \({t^2}\)
Explanation:
\(v = \alpha \sqrt x \Rightarrow \frac{{dx}}{{dt}} = \alpha \sqrt x \Rightarrow \frac{{dx}}{{\sqrt x }} = \alpha \,dt\) By integrating both sides \(\int {{x^{ - 1/2}}dx = \int {\alpha \,dt} } \) \(\therefore \;x \propto {t^2}\)
PHXI03:MOTION IN A STRAIGHT LINE
362292
The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^{3}\) and \(y=\beta t^{3}\). The speed of the particle at time \(t\) is given by:
362289
Which of the following graphs cannot possibly represent one-dimensional motion of a particle?
1 I and II
2 II and III
3 II and IV
4 All of these
Explanation:
Graph (I) does not represent the one dimensional motion, because total distance covered by a particle always increases with time. Graph (II) and Graph (III) do not represent the one-dimensional motion,because at a particular time, there cannot be two values of position or velocity. Graph (IV) is not possible, because speed can never be negative.
PHXI03:MOTION IN A STRAIGHT LINE
362290
A 150 \(m\) long train is moving with a uniform velocity of 45 \(km/h\). The time taken by the train to cross a bridge of length 850 \(m\) is
1 \(80\,\sec \)
2 \(70\,\sec \)
3 \(92\,\sec \)
4 \(68\,\sec \)
Explanation:
Total distance to be covered for crossing the bridge \( = \) length of train \( + \) length of bridge \( = 150\,m + 850\,m = 1000\,m\) \(\rm{Time} = \frac{{\rm{Distance}}}{{\rm{Velocity}}} = \frac{{1000}}{{45 \times \frac{5}{{18}}}} = 80\sec \)
PHXI03:MOTION IN A STRAIGHT LINE
362291
A particle located at \(x = 0\) at time \(t = 0\), starts moving along the positive \(x\) - direction with a velocity \('v'\) that varies as \(v = a\sqrt x .\) The displacement of the particle varies with time as
1 \(t\)
2 \({t^{3/2}}\)
3 \({t^3}\)
4 \({t^2}\)
Explanation:
\(v = \alpha \sqrt x \Rightarrow \frac{{dx}}{{dt}} = \alpha \sqrt x \Rightarrow \frac{{dx}}{{\sqrt x }} = \alpha \,dt\) By integrating both sides \(\int {{x^{ - 1/2}}dx = \int {\alpha \,dt} } \) \(\therefore \;x \propto {t^2}\)
PHXI03:MOTION IN A STRAIGHT LINE
362292
The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^{3}\) and \(y=\beta t^{3}\). The speed of the particle at time \(t\) is given by:
362289
Which of the following graphs cannot possibly represent one-dimensional motion of a particle?
1 I and II
2 II and III
3 II and IV
4 All of these
Explanation:
Graph (I) does not represent the one dimensional motion, because total distance covered by a particle always increases with time. Graph (II) and Graph (III) do not represent the one-dimensional motion,because at a particular time, there cannot be two values of position or velocity. Graph (IV) is not possible, because speed can never be negative.
PHXI03:MOTION IN A STRAIGHT LINE
362290
A 150 \(m\) long train is moving with a uniform velocity of 45 \(km/h\). The time taken by the train to cross a bridge of length 850 \(m\) is
1 \(80\,\sec \)
2 \(70\,\sec \)
3 \(92\,\sec \)
4 \(68\,\sec \)
Explanation:
Total distance to be covered for crossing the bridge \( = \) length of train \( + \) length of bridge \( = 150\,m + 850\,m = 1000\,m\) \(\rm{Time} = \frac{{\rm{Distance}}}{{\rm{Velocity}}} = \frac{{1000}}{{45 \times \frac{5}{{18}}}} = 80\sec \)
PHXI03:MOTION IN A STRAIGHT LINE
362291
A particle located at \(x = 0\) at time \(t = 0\), starts moving along the positive \(x\) - direction with a velocity \('v'\) that varies as \(v = a\sqrt x .\) The displacement of the particle varies with time as
1 \(t\)
2 \({t^{3/2}}\)
3 \({t^3}\)
4 \({t^2}\)
Explanation:
\(v = \alpha \sqrt x \Rightarrow \frac{{dx}}{{dt}} = \alpha \sqrt x \Rightarrow \frac{{dx}}{{\sqrt x }} = \alpha \,dt\) By integrating both sides \(\int {{x^{ - 1/2}}dx = \int {\alpha \,dt} } \) \(\therefore \;x \propto {t^2}\)
PHXI03:MOTION IN A STRAIGHT LINE
362292
The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^{3}\) and \(y=\beta t^{3}\). The speed of the particle at time \(t\) is given by:
