369894
If the tension on a wire is removed at once, then
1 There will be no change in its temperature
2 It will break
3 Its temperature will reduce
4 Its temperature increase
Explanation:
Due to tension, intermolecular distance between atoms is increased and therefore potential energy of the wire is increased and with the removal of force interatomic distance is reduced. This change in potential energy produces heat in the wire that will increase its temperature.
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369895
If \(x\) longitudinal strain is produced in a wire of Young's modulus Y, then energy stored in the material of the wire per unit volume is
1 \(2 Y x^{2}\)
2 \(Y x^{2}\)
3 \(\dfrac{1}{2} Y x^{2}\)
4 \(\dfrac{1}{2} Y^{2} x\)
Explanation:
Energy stored per unit volume \(\begin{gathered}=\dfrac{1}{2} \times \text { Stress } \times \text { Strain } \\=\dfrac{1}{2} \times \text { Young's modulus } \times(\text { Strain })^{2}=\dfrac{1}{2} \times Y \times x^{2} .\end{gathered}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369896
The young modulus of a wire is \(Y\). If the energy per unit volume is \(E\), \(500N\) then the strain will be
1 \(\sqrt{\dfrac{2 E}{Y}}\)
2 \({\text{E}}\sqrt {{\text{2Y}}} \)
3 \(EY\)
4 \(\dfrac{E}{Y}\)
Explanation:
Energy per unit volume \(=\dfrac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}\) \(\therefore\) strain \(=\sqrt{\dfrac{2 E}{Y}}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369897
Calculate the work done, if a wire is loaded by ' \(M g\) ' weight and the increase in length is ' \(l\) '
369894
If the tension on a wire is removed at once, then
1 There will be no change in its temperature
2 It will break
3 Its temperature will reduce
4 Its temperature increase
Explanation:
Due to tension, intermolecular distance between atoms is increased and therefore potential energy of the wire is increased and with the removal of force interatomic distance is reduced. This change in potential energy produces heat in the wire that will increase its temperature.
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369895
If \(x\) longitudinal strain is produced in a wire of Young's modulus Y, then energy stored in the material of the wire per unit volume is
1 \(2 Y x^{2}\)
2 \(Y x^{2}\)
3 \(\dfrac{1}{2} Y x^{2}\)
4 \(\dfrac{1}{2} Y^{2} x\)
Explanation:
Energy stored per unit volume \(\begin{gathered}=\dfrac{1}{2} \times \text { Stress } \times \text { Strain } \\=\dfrac{1}{2} \times \text { Young's modulus } \times(\text { Strain })^{2}=\dfrac{1}{2} \times Y \times x^{2} .\end{gathered}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369896
The young modulus of a wire is \(Y\). If the energy per unit volume is \(E\), \(500N\) then the strain will be
1 \(\sqrt{\dfrac{2 E}{Y}}\)
2 \({\text{E}}\sqrt {{\text{2Y}}} \)
3 \(EY\)
4 \(\dfrac{E}{Y}\)
Explanation:
Energy per unit volume \(=\dfrac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}\) \(\therefore\) strain \(=\sqrt{\dfrac{2 E}{Y}}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369897
Calculate the work done, if a wire is loaded by ' \(M g\) ' weight and the increase in length is ' \(l\) '
369894
If the tension on a wire is removed at once, then
1 There will be no change in its temperature
2 It will break
3 Its temperature will reduce
4 Its temperature increase
Explanation:
Due to tension, intermolecular distance between atoms is increased and therefore potential energy of the wire is increased and with the removal of force interatomic distance is reduced. This change in potential energy produces heat in the wire that will increase its temperature.
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369895
If \(x\) longitudinal strain is produced in a wire of Young's modulus Y, then energy stored in the material of the wire per unit volume is
1 \(2 Y x^{2}\)
2 \(Y x^{2}\)
3 \(\dfrac{1}{2} Y x^{2}\)
4 \(\dfrac{1}{2} Y^{2} x\)
Explanation:
Energy stored per unit volume \(\begin{gathered}=\dfrac{1}{2} \times \text { Stress } \times \text { Strain } \\=\dfrac{1}{2} \times \text { Young's modulus } \times(\text { Strain })^{2}=\dfrac{1}{2} \times Y \times x^{2} .\end{gathered}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369896
The young modulus of a wire is \(Y\). If the energy per unit volume is \(E\), \(500N\) then the strain will be
1 \(\sqrt{\dfrac{2 E}{Y}}\)
2 \({\text{E}}\sqrt {{\text{2Y}}} \)
3 \(EY\)
4 \(\dfrac{E}{Y}\)
Explanation:
Energy per unit volume \(=\dfrac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}\) \(\therefore\) strain \(=\sqrt{\dfrac{2 E}{Y}}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369897
Calculate the work done, if a wire is loaded by ' \(M g\) ' weight and the increase in length is ' \(l\) '
369894
If the tension on a wire is removed at once, then
1 There will be no change in its temperature
2 It will break
3 Its temperature will reduce
4 Its temperature increase
Explanation:
Due to tension, intermolecular distance between atoms is increased and therefore potential energy of the wire is increased and with the removal of force interatomic distance is reduced. This change in potential energy produces heat in the wire that will increase its temperature.
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369895
If \(x\) longitudinal strain is produced in a wire of Young's modulus Y, then energy stored in the material of the wire per unit volume is
1 \(2 Y x^{2}\)
2 \(Y x^{2}\)
3 \(\dfrac{1}{2} Y x^{2}\)
4 \(\dfrac{1}{2} Y^{2} x\)
Explanation:
Energy stored per unit volume \(\begin{gathered}=\dfrac{1}{2} \times \text { Stress } \times \text { Strain } \\=\dfrac{1}{2} \times \text { Young's modulus } \times(\text { Strain })^{2}=\dfrac{1}{2} \times Y \times x^{2} .\end{gathered}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369896
The young modulus of a wire is \(Y\). If the energy per unit volume is \(E\), \(500N\) then the strain will be
1 \(\sqrt{\dfrac{2 E}{Y}}\)
2 \({\text{E}}\sqrt {{\text{2Y}}} \)
3 \(EY\)
4 \(\dfrac{E}{Y}\)
Explanation:
Energy per unit volume \(=\dfrac{1}{2} \times \mathrm{Y} \times(\text { strain })^{2}\) \(\therefore\) strain \(=\sqrt{\dfrac{2 E}{Y}}\)
PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369897
Calculate the work done, if a wire is loaded by ' \(M g\) ' weight and the increase in length is ' \(l\) '
