PHXI09:MECHANICAL PROPERTIES OF SOLIDS
369691
The bulk modulus of a liquid is \(3 \times 10^{10} \mathrm{Nm}^{-2}\). The pressure required to reduce the volume of liquid by \(2 \%\) is :
1 \(3 \times {10^8}N{m^{ - 2}}\)
2 \(9 \times {10^8}\,N{m^{ - 2}}\)
3 \(6 \times {10^8}\,N{m^{ - 2}}\)
4 \(12 \times {10^8}N{m^{ - 2}}\)
Explanation:
\(B=3 \times 10^{10} \mathrm{~N} / \mathrm{m}^{2}\).
\(-\dfrac{\Delta V}{V_{0}}=0.02\)
\(B = \left[ {\frac{P}{{ - \frac{{\Delta V}}{{{V_0}}}}}} \right]\)
\( \Rightarrow P = - B\left( {\frac{{\Delta V}}{V}} \right)\)
\( \Rightarrow P = \left( {3 \times {{10}^{10}}} \right)(0.02)\)
\( = 6 \times {10^8}\;N/{m^2}\)