361010
In order that a floating object be in a stable equilibrium, its center of buoyancy should be
1 Vertically below its centre of gravity
2 Horizontally incline with its center of gravity
3 Vertically above its center of gravity
4 May be anywhere
Explanation:
In the tilted position \(F_{B}\) and \(W\) produce restoring couple.
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361011
Clouds to float in air due to
1 High density
2 Surface tension of air
3 Buoyancy
4 Surface tension of air
Explanation:
Conceptual Question
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361012
You are holding a bottle of sparkling water inside a car moving forward. When the driver applies the brakes:
1 Depending on the speed of the car, bubbles might move forward or backward.
2 Bubbles will start to move backward with respect to the bottle.
3 Bubbles in the middle of the liquid will start to move forward with respect to the bottle.
4 Bubbles will stay at the same horizontal location in the water.
Explanation:
When brakes are applied then pseudo force acts forward and pressure increases in forward direction and hence the bubbles move back ward (towards the less pressure side)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361013
Two solid bodies form a balance and the arm is in horizontal position. The mass of one body is \(36\;g\) and its density is \(9\;g/c{m^3}\). If the mass of the other is \(48\;g\), its density in \(g/c{m^3}\) is
1 \(\dfrac{3}{2}\)
2 \(\dfrac{4}{3}\)
3 5
4 3
Explanation:
Let \(T\) be the tension in the string. \(\begin{aligned}& T=m g-F_{b}=m g-m_{\ell} g=\left(m-\rho_{\ell} V\right) g \\& \rho_{\ell}=\text { density of water. }\end{aligned}\) As the system is in equilibrium \({T_1} = {T_2}\) \(\left( {{m_1} - {\rho _\ell }{V_1}} \right)g = \left( {{m_2} - {\rho _\ell }{V_2}} \right)g\) \(36 - 1 \times \frac{{36}}{9} = 48 - 1 \times \frac{{48}}{{{\rho _2}}}\) \( \Rightarrow {\rho _2} = 3\;g/c{m^3}\)
361010
In order that a floating object be in a stable equilibrium, its center of buoyancy should be
1 Vertically below its centre of gravity
2 Horizontally incline with its center of gravity
3 Vertically above its center of gravity
4 May be anywhere
Explanation:
In the tilted position \(F_{B}\) and \(W\) produce restoring couple.
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361011
Clouds to float in air due to
1 High density
2 Surface tension of air
3 Buoyancy
4 Surface tension of air
Explanation:
Conceptual Question
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361012
You are holding a bottle of sparkling water inside a car moving forward. When the driver applies the brakes:
1 Depending on the speed of the car, bubbles might move forward or backward.
2 Bubbles will start to move backward with respect to the bottle.
3 Bubbles in the middle of the liquid will start to move forward with respect to the bottle.
4 Bubbles will stay at the same horizontal location in the water.
Explanation:
When brakes are applied then pseudo force acts forward and pressure increases in forward direction and hence the bubbles move back ward (towards the less pressure side)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361013
Two solid bodies form a balance and the arm is in horizontal position. The mass of one body is \(36\;g\) and its density is \(9\;g/c{m^3}\). If the mass of the other is \(48\;g\), its density in \(g/c{m^3}\) is
1 \(\dfrac{3}{2}\)
2 \(\dfrac{4}{3}\)
3 5
4 3
Explanation:
Let \(T\) be the tension in the string. \(\begin{aligned}& T=m g-F_{b}=m g-m_{\ell} g=\left(m-\rho_{\ell} V\right) g \\& \rho_{\ell}=\text { density of water. }\end{aligned}\) As the system is in equilibrium \({T_1} = {T_2}\) \(\left( {{m_1} - {\rho _\ell }{V_1}} \right)g = \left( {{m_2} - {\rho _\ell }{V_2}} \right)g\) \(36 - 1 \times \frac{{36}}{9} = 48 - 1 \times \frac{{48}}{{{\rho _2}}}\) \( \Rightarrow {\rho _2} = 3\;g/c{m^3}\)
361010
In order that a floating object be in a stable equilibrium, its center of buoyancy should be
1 Vertically below its centre of gravity
2 Horizontally incline with its center of gravity
3 Vertically above its center of gravity
4 May be anywhere
Explanation:
In the tilted position \(F_{B}\) and \(W\) produce restoring couple.
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361011
Clouds to float in air due to
1 High density
2 Surface tension of air
3 Buoyancy
4 Surface tension of air
Explanation:
Conceptual Question
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361012
You are holding a bottle of sparkling water inside a car moving forward. When the driver applies the brakes:
1 Depending on the speed of the car, bubbles might move forward or backward.
2 Bubbles will start to move backward with respect to the bottle.
3 Bubbles in the middle of the liquid will start to move forward with respect to the bottle.
4 Bubbles will stay at the same horizontal location in the water.
Explanation:
When brakes are applied then pseudo force acts forward and pressure increases in forward direction and hence the bubbles move back ward (towards the less pressure side)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361013
Two solid bodies form a balance and the arm is in horizontal position. The mass of one body is \(36\;g\) and its density is \(9\;g/c{m^3}\). If the mass of the other is \(48\;g\), its density in \(g/c{m^3}\) is
1 \(\dfrac{3}{2}\)
2 \(\dfrac{4}{3}\)
3 5
4 3
Explanation:
Let \(T\) be the tension in the string. \(\begin{aligned}& T=m g-F_{b}=m g-m_{\ell} g=\left(m-\rho_{\ell} V\right) g \\& \rho_{\ell}=\text { density of water. }\end{aligned}\) As the system is in equilibrium \({T_1} = {T_2}\) \(\left( {{m_1} - {\rho _\ell }{V_1}} \right)g = \left( {{m_2} - {\rho _\ell }{V_2}} \right)g\) \(36 - 1 \times \frac{{36}}{9} = 48 - 1 \times \frac{{48}}{{{\rho _2}}}\) \( \Rightarrow {\rho _2} = 3\;g/c{m^3}\)
361010
In order that a floating object be in a stable equilibrium, its center of buoyancy should be
1 Vertically below its centre of gravity
2 Horizontally incline with its center of gravity
3 Vertically above its center of gravity
4 May be anywhere
Explanation:
In the tilted position \(F_{B}\) and \(W\) produce restoring couple.
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361011
Clouds to float in air due to
1 High density
2 Surface tension of air
3 Buoyancy
4 Surface tension of air
Explanation:
Conceptual Question
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361012
You are holding a bottle of sparkling water inside a car moving forward. When the driver applies the brakes:
1 Depending on the speed of the car, bubbles might move forward or backward.
2 Bubbles will start to move backward with respect to the bottle.
3 Bubbles in the middle of the liquid will start to move forward with respect to the bottle.
4 Bubbles will stay at the same horizontal location in the water.
Explanation:
When brakes are applied then pseudo force acts forward and pressure increases in forward direction and hence the bubbles move back ward (towards the less pressure side)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS
361013
Two solid bodies form a balance and the arm is in horizontal position. The mass of one body is \(36\;g\) and its density is \(9\;g/c{m^3}\). If the mass of the other is \(48\;g\), its density in \(g/c{m^3}\) is
1 \(\dfrac{3}{2}\)
2 \(\dfrac{4}{3}\)
3 5
4 3
Explanation:
Let \(T\) be the tension in the string. \(\begin{aligned}& T=m g-F_{b}=m g-m_{\ell} g=\left(m-\rho_{\ell} V\right) g \\& \rho_{\ell}=\text { density of water. }\end{aligned}\) As the system is in equilibrium \({T_1} = {T_2}\) \(\left( {{m_1} - {\rho _\ell }{V_1}} \right)g = \left( {{m_2} - {\rho _\ell }{V_2}} \right)g\) \(36 - 1 \times \frac{{36}}{9} = 48 - 1 \times \frac{{48}}{{{\rho _2}}}\) \( \Rightarrow {\rho _2} = 3\;g/c{m^3}\)
