Bernoulli’s Principle
« First Topic in Next Topic: Equation of Continuity »
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360835 Select the incorrect statement from the following.

1 Bunsen burner and sprayers work on Bernoulli's principle
2 Blood flow in arteries is explained by Bernoulli's principle
3 A siphon works on account of atmospheric pressure.
4 All are correct
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360836 In a siphon arrangement the water level in the supply reservoir is above the free end of \(a\) pipe as shown in the figure. If the diameter of the pipe is ' \(d\) ' (constant) what is the rate of the discharge of water.
supporting img

1 \(\pi d^{2} \sqrt{g h}\)
2 \(\pi d^{2} \sqrt{8 g h}\)
3 \(\pi d^{2} \sqrt{\dfrac{g h}{8}}\)
4 \(\pi d^{2} \sqrt{2 g h}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360837 In the figure shown find the height \(h\) at which the bubbles of water will form at point 2 .
\(\left(g=10 m / s^{2}\right)\)
supporting img

1 \(1\;m\)
2 \(3\;m\)
3 \(6\;m\)
4 \(4\;m\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360838 A siphon has a uniform circular base of diameter \(8/\sqrt \pi cm\) with its crest \(A,1.8\;m\) above the water level vessel B is of large cross section \(\left( {g = 10\;m/{s^2}} \right)\) and atmospheric pressure \({P_0} = \left( {{{10}^5}\;N/{m^2}} \right)\). Predict the wrong option.
supporting img

1 Velocity of flow through pipe is \(6\sqrt 2 \;m/s\)
2 Discharge rate of flow through pipe is \(96\sqrt 2 \times {10^{ - 4}}\;{m^3}/s\)
3 Velocity of flow through pipe is \(6\;m/s\)
4 Pressure at \(A\) is \(0.46 \times {10^5}\;N/{m^2}\)
NEET DIGITAL LIBRARY
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360835 Select the incorrect statement from the following.

1 Bunsen burner and sprayers work on Bernoulli's principle
2 Blood flow in arteries is explained by Bernoulli's principle
3 A siphon works on account of atmospheric pressure.
4 All are correct
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360836 In a siphon arrangement the water level in the supply reservoir is above the free end of \(a\) pipe as shown in the figure. If the diameter of the pipe is ' \(d\) ' (constant) what is the rate of the discharge of water.
supporting img

1 \(\pi d^{2} \sqrt{g h}\)
2 \(\pi d^{2} \sqrt{8 g h}\)
3 \(\pi d^{2} \sqrt{\dfrac{g h}{8}}\)
4 \(\pi d^{2} \sqrt{2 g h}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360837 In the figure shown find the height \(h\) at which the bubbles of water will form at point 2 .
\(\left(g=10 m / s^{2}\right)\)
supporting img

1 \(1\;m\)
2 \(3\;m\)
3 \(6\;m\)
4 \(4\;m\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360838 A siphon has a uniform circular base of diameter \(8/\sqrt \pi cm\) with its crest \(A,1.8\;m\) above the water level vessel B is of large cross section \(\left( {g = 10\;m/{s^2}} \right)\) and atmospheric pressure \({P_0} = \left( {{{10}^5}\;N/{m^2}} \right)\). Predict the wrong option.
supporting img

1 Velocity of flow through pipe is \(6\sqrt 2 \;m/s\)
2 Discharge rate of flow through pipe is \(96\sqrt 2 \times {10^{ - 4}}\;{m^3}/s\)
3 Velocity of flow through pipe is \(6\;m/s\)
4 Pressure at \(A\) is \(0.46 \times {10^5}\;N/{m^2}\)
Join With Us for More Updates
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360835 Select the incorrect statement from the following.

1 Bunsen burner and sprayers work on Bernoulli's principle
2 Blood flow in arteries is explained by Bernoulli's principle
3 A siphon works on account of atmospheric pressure.
4 All are correct
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360836 In a siphon arrangement the water level in the supply reservoir is above the free end of \(a\) pipe as shown in the figure. If the diameter of the pipe is ' \(d\) ' (constant) what is the rate of the discharge of water.
supporting img

1 \(\pi d^{2} \sqrt{g h}\)
2 \(\pi d^{2} \sqrt{8 g h}\)
3 \(\pi d^{2} \sqrt{\dfrac{g h}{8}}\)
4 \(\pi d^{2} \sqrt{2 g h}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360837 In the figure shown find the height \(h\) at which the bubbles of water will form at point 2 .
\(\left(g=10 m / s^{2}\right)\)
supporting img

1 \(1\;m\)
2 \(3\;m\)
3 \(6\;m\)
4 \(4\;m\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360838 A siphon has a uniform circular base of diameter \(8/\sqrt \pi cm\) with its crest \(A,1.8\;m\) above the water level vessel B is of large cross section \(\left( {g = 10\;m/{s^2}} \right)\) and atmospheric pressure \({P_0} = \left( {{{10}^5}\;N/{m^2}} \right)\). Predict the wrong option.
supporting img

1 Velocity of flow through pipe is \(6\sqrt 2 \;m/s\)
2 Discharge rate of flow through pipe is \(96\sqrt 2 \times {10^{ - 4}}\;{m^3}/s\)
3 Velocity of flow through pipe is \(6\;m/s\)
4 Pressure at \(A\) is \(0.46 \times {10^5}\;N/{m^2}\)
For More Updates join with Us
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360835 Select the incorrect statement from the following.

1 Bunsen burner and sprayers work on Bernoulli's principle
2 Blood flow in arteries is explained by Bernoulli's principle
3 A siphon works on account of atmospheric pressure.
4 All are correct
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360836 In a siphon arrangement the water level in the supply reservoir is above the free end of \(a\) pipe as shown in the figure. If the diameter of the pipe is ' \(d\) ' (constant) what is the rate of the discharge of water.
supporting img

1 \(\pi d^{2} \sqrt{g h}\)
2 \(\pi d^{2} \sqrt{8 g h}\)
3 \(\pi d^{2} \sqrt{\dfrac{g h}{8}}\)
4 \(\pi d^{2} \sqrt{2 g h}\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360837 In the figure shown find the height \(h\) at which the bubbles of water will form at point 2 .
\(\left(g=10 m / s^{2}\right)\)
supporting img

1 \(1\;m\)
2 \(3\;m\)
3 \(6\;m\)
4 \(4\;m\)
PHXI10:MECHANICAL PROPERTIES OF FLUIDS

360838 A siphon has a uniform circular base of diameter \(8/\sqrt \pi cm\) with its crest \(A,1.8\;m\) above the water level vessel B is of large cross section \(\left( {g = 10\;m/{s^2}} \right)\) and atmospheric pressure \({P_0} = \left( {{{10}^5}\;N/{m^2}} \right)\). Predict the wrong option.
supporting img

1 Velocity of flow through pipe is \(6\sqrt 2 \;m/s\)
2 Discharge rate of flow through pipe is \(96\sqrt 2 \times {10^{ - 4}}\;{m^3}/s\)
3 Velocity of flow through pipe is \(6\;m/s\)
4 Pressure at \(A\) is \(0.46 \times {10^5}\;N/{m^2}\)
NEET DIGITAL LIBRARY