The Earth’s Magnetism and Magnetic Instruments
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NEET DIGITAL LIBRARY
PHXII05:MAGNETISM and MATTER

360683 At certain place, horizontal component is \({\dfrac{1}{\sqrt{3}}}\) times the vertical component. The angle of dip is

1 \({30^{\circ}}\)
2 \({45^{\circ}}\)
3 \({90^{\circ}}\)
4 \({60^{\circ}}\)
PHXII05:MAGNETISM and MATTER

360684 If \(B_{H}=\dfrac{1}{\sqrt{3}} B_{V}\), then find angle of dip. ( where, symbols have their usual meanings)

1 \(30^{\circ}\)
2 \(60^{\circ}\)
3 \(90^{\circ}\)
4 \(45^{\circ}\)
PHXII05:MAGNETISM and MATTER

360685 Consider the earth as a short magnet with its centre coinciding with the centre of the earth and dipole moment \(M\). The angle of dip \(\delta \) is related to latitude \(\lambda\) as

1 \(\tan \delta = \frac{{\tan \lambda }}{2}\)
2 \(\tan \delta = 2\tan \lambda \)
3 \(\tan \delta - \cot \lambda \)
4 \(\tan \delta = \tan \lambda \)
PHXII05:MAGNETISM and MATTER

360686 The horizontal component of the earth's magnetic field at any place is \(0.36 \times {10^{ - 4}}Wb{m^{ - 2}}\). If the angle of dip at that place is \(60^{\circ}\), then the value of vertical component of the earth's magnetic field will be (in \(Wb{m^{ - 2}}\))

1 \(0.12 \times 10^{-4}\)
2 \(0.24 \times 10^{-4}\)
3 \(0.40 \times 10^{-4}\)
4 \(0.622 \times 10^{-4}\)
AIIMS - 2018
Join With Us for More Updates
PHXII05:MAGNETISM and MATTER

360683 At certain place, horizontal component is \({\dfrac{1}{\sqrt{3}}}\) times the vertical component. The angle of dip is

1 \({30^{\circ}}\)
2 \({45^{\circ}}\)
3 \({90^{\circ}}\)
4 \({60^{\circ}}\)
PHXII05:MAGNETISM and MATTER

360684 If \(B_{H}=\dfrac{1}{\sqrt{3}} B_{V}\), then find angle of dip. ( where, symbols have their usual meanings)

1 \(30^{\circ}\)
2 \(60^{\circ}\)
3 \(90^{\circ}\)
4 \(45^{\circ}\)
PHXII05:MAGNETISM and MATTER

360685 Consider the earth as a short magnet with its centre coinciding with the centre of the earth and dipole moment \(M\). The angle of dip \(\delta \) is related to latitude \(\lambda\) as

1 \(\tan \delta = \frac{{\tan \lambda }}{2}\)
2 \(\tan \delta = 2\tan \lambda \)
3 \(\tan \delta - \cot \lambda \)
4 \(\tan \delta = \tan \lambda \)
PHXII05:MAGNETISM and MATTER

360686 The horizontal component of the earth's magnetic field at any place is \(0.36 \times {10^{ - 4}}Wb{m^{ - 2}}\). If the angle of dip at that place is \(60^{\circ}\), then the value of vertical component of the earth's magnetic field will be (in \(Wb{m^{ - 2}}\))

1 \(0.12 \times 10^{-4}\)
2 \(0.24 \times 10^{-4}\)
3 \(0.40 \times 10^{-4}\)
4 \(0.622 \times 10^{-4}\)
AIIMS - 2018
For More Updates join with Us
PHXII05:MAGNETISM and MATTER

360683 At certain place, horizontal component is \({\dfrac{1}{\sqrt{3}}}\) times the vertical component. The angle of dip is

1 \({30^{\circ}}\)
2 \({45^{\circ}}\)
3 \({90^{\circ}}\)
4 \({60^{\circ}}\)
PHXII05:MAGNETISM and MATTER

360684 If \(B_{H}=\dfrac{1}{\sqrt{3}} B_{V}\), then find angle of dip. ( where, symbols have their usual meanings)

1 \(30^{\circ}\)
2 \(60^{\circ}\)
3 \(90^{\circ}\)
4 \(45^{\circ}\)
PHXII05:MAGNETISM and MATTER

360685 Consider the earth as a short magnet with its centre coinciding with the centre of the earth and dipole moment \(M\). The angle of dip \(\delta \) is related to latitude \(\lambda\) as

1 \(\tan \delta = \frac{{\tan \lambda }}{2}\)
2 \(\tan \delta = 2\tan \lambda \)
3 \(\tan \delta - \cot \lambda \)
4 \(\tan \delta = \tan \lambda \)
PHXII05:MAGNETISM and MATTER

360686 The horizontal component of the earth's magnetic field at any place is \(0.36 \times {10^{ - 4}}Wb{m^{ - 2}}\). If the angle of dip at that place is \(60^{\circ}\), then the value of vertical component of the earth's magnetic field will be (in \(Wb{m^{ - 2}}\))

1 \(0.12 \times 10^{-4}\)
2 \(0.24 \times 10^{-4}\)
3 \(0.40 \times 10^{-4}\)
4 \(0.622 \times 10^{-4}\)
AIIMS - 2018
NEET DIGITAL LIBRARY
PHXII05:MAGNETISM and MATTER

360683 At certain place, horizontal component is \({\dfrac{1}{\sqrt{3}}}\) times the vertical component. The angle of dip is

1 \({30^{\circ}}\)
2 \({45^{\circ}}\)
3 \({90^{\circ}}\)
4 \({60^{\circ}}\)
PHXII05:MAGNETISM and MATTER

360684 If \(B_{H}=\dfrac{1}{\sqrt{3}} B_{V}\), then find angle of dip. ( where, symbols have their usual meanings)

1 \(30^{\circ}\)
2 \(60^{\circ}\)
3 \(90^{\circ}\)
4 \(45^{\circ}\)
PHXII05:MAGNETISM and MATTER

360685 Consider the earth as a short magnet with its centre coinciding with the centre of the earth and dipole moment \(M\). The angle of dip \(\delta \) is related to latitude \(\lambda\) as

1 \(\tan \delta = \frac{{\tan \lambda }}{2}\)
2 \(\tan \delta = 2\tan \lambda \)
3 \(\tan \delta - \cot \lambda \)
4 \(\tan \delta = \tan \lambda \)
PHXII05:MAGNETISM and MATTER

360686 The horizontal component of the earth's magnetic field at any place is \(0.36 \times {10^{ - 4}}Wb{m^{ - 2}}\). If the angle of dip at that place is \(60^{\circ}\), then the value of vertical component of the earth's magnetic field will be (in \(Wb{m^{ - 2}}\))

1 \(0.12 \times 10^{-4}\)
2 \(0.24 \times 10^{-4}\)
3 \(0.40 \times 10^{-4}\)
4 \(0.622 \times 10^{-4}\)
AIIMS - 2018
Join With Us for More Updates