The Earth’s Magnetism and Magnetic Instruments
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PHXII05:MAGNETISM and MATTER

360674 The angle of dip at a place on the earth gives

1 the horizontal component of the earth's magnetic field
2 the location of geographic meridian
3 the vertical component of the earth's field
4 the direction of the earth's magnetic field
PHXII05:MAGNETISM and MATTER

360675 A dip needle lies initially in the magnetic meridian when it shows an angle of \(\operatorname{dip} \theta\) at a place. The dip circle is rotated through an angle \(x\) in the horizontal plane and then it shown an angle of \(\operatorname{dip} \theta^{\prime}\). Then \(\dfrac{\tan \theta^{\prime}}{\tan \theta}\) is

1 \(\cos x\)
2 \(\dfrac{1}{\cos x}\)
3 \(\dfrac{1}{\sin x}\)
4 \(\dfrac{1}{\tan x}\)
PHXII05:MAGNETISM and MATTER

360676 The horizontal component of earth's magnetic field at a place is \({0.3 \times 10^{-4} {~T}}\). If the angle of dip is \({60^{\circ}}\), what is the total earth's magnetic field in \({\mu {T}}\) ?

1 \(50\,\mu T\)
2 \(45\,\mu T\)
3 \(60\,\mu T\)
4 \(70\,\mu T\)
PHXII05:MAGNETISM and MATTER

360677 If the angle of dip at two places are \(30^{\circ}\) and \(45^{\circ}\) respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be (Given total field at the two places is same)

1 \(\sqrt{3}: \sqrt{2}\)
2 \(1: 2\)
3 \(1: \sqrt{2}\)
4 \(1: \sqrt{3}\)
PHXII05:MAGNETISM and MATTER

360678 The earth's magnetic field at a certain place has a horizontal component of 0.3\(G\) and total strength 0.5\(G\). The angle of dip in \(\delta\), then

1 \(\delta=\tan ^{-1} \dfrac{4}{3}\)
2 \(\delta=\tan ^{-1} \dfrac{5}{3}\)
3 \(\delta=\tan ^{-1} \dfrac{3}{5}\)
4 \(\delta=\tan ^{-1} \dfrac{3}{4}\)
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PHXII05:MAGNETISM and MATTER

360674 The angle of dip at a place on the earth gives

1 the horizontal component of the earth's magnetic field
2 the location of geographic meridian
3 the vertical component of the earth's field
4 the direction of the earth's magnetic field
PHXII05:MAGNETISM and MATTER

360675 A dip needle lies initially in the magnetic meridian when it shows an angle of \(\operatorname{dip} \theta\) at a place. The dip circle is rotated through an angle \(x\) in the horizontal plane and then it shown an angle of \(\operatorname{dip} \theta^{\prime}\). Then \(\dfrac{\tan \theta^{\prime}}{\tan \theta}\) is

1 \(\cos x\)
2 \(\dfrac{1}{\cos x}\)
3 \(\dfrac{1}{\sin x}\)
4 \(\dfrac{1}{\tan x}\)
PHXII05:MAGNETISM and MATTER

360676 The horizontal component of earth's magnetic field at a place is \({0.3 \times 10^{-4} {~T}}\). If the angle of dip is \({60^{\circ}}\), what is the total earth's magnetic field in \({\mu {T}}\) ?

1 \(50\,\mu T\)
2 \(45\,\mu T\)
3 \(60\,\mu T\)
4 \(70\,\mu T\)
PHXII05:MAGNETISM and MATTER

360677 If the angle of dip at two places are \(30^{\circ}\) and \(45^{\circ}\) respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be (Given total field at the two places is same)

1 \(\sqrt{3}: \sqrt{2}\)
2 \(1: 2\)
3 \(1: \sqrt{2}\)
4 \(1: \sqrt{3}\)
PHXII05:MAGNETISM and MATTER

360678 The earth's magnetic field at a certain place has a horizontal component of 0.3\(G\) and total strength 0.5\(G\). The angle of dip in \(\delta\), then

1 \(\delta=\tan ^{-1} \dfrac{4}{3}\)
2 \(\delta=\tan ^{-1} \dfrac{5}{3}\)
3 \(\delta=\tan ^{-1} \dfrac{3}{5}\)
4 \(\delta=\tan ^{-1} \dfrac{3}{4}\)
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PHXII05:MAGNETISM and MATTER

360674 The angle of dip at a place on the earth gives

1 the horizontal component of the earth's magnetic field
2 the location of geographic meridian
3 the vertical component of the earth's field
4 the direction of the earth's magnetic field
PHXII05:MAGNETISM and MATTER

360675 A dip needle lies initially in the magnetic meridian when it shows an angle of \(\operatorname{dip} \theta\) at a place. The dip circle is rotated through an angle \(x\) in the horizontal plane and then it shown an angle of \(\operatorname{dip} \theta^{\prime}\). Then \(\dfrac{\tan \theta^{\prime}}{\tan \theta}\) is

1 \(\cos x\)
2 \(\dfrac{1}{\cos x}\)
3 \(\dfrac{1}{\sin x}\)
4 \(\dfrac{1}{\tan x}\)
PHXII05:MAGNETISM and MATTER

360676 The horizontal component of earth's magnetic field at a place is \({0.3 \times 10^{-4} {~T}}\). If the angle of dip is \({60^{\circ}}\), what is the total earth's magnetic field in \({\mu {T}}\) ?

1 \(50\,\mu T\)
2 \(45\,\mu T\)
3 \(60\,\mu T\)
4 \(70\,\mu T\)
PHXII05:MAGNETISM and MATTER

360677 If the angle of dip at two places are \(30^{\circ}\) and \(45^{\circ}\) respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be (Given total field at the two places is same)

1 \(\sqrt{3}: \sqrt{2}\)
2 \(1: 2\)
3 \(1: \sqrt{2}\)
4 \(1: \sqrt{3}\)
PHXII05:MAGNETISM and MATTER

360678 The earth's magnetic field at a certain place has a horizontal component of 0.3\(G\) and total strength 0.5\(G\). The angle of dip in \(\delta\), then

1 \(\delta=\tan ^{-1} \dfrac{4}{3}\)
2 \(\delta=\tan ^{-1} \dfrac{5}{3}\)
3 \(\delta=\tan ^{-1} \dfrac{3}{5}\)
4 \(\delta=\tan ^{-1} \dfrac{3}{4}\)
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PHXII05:MAGNETISM and MATTER

360674 The angle of dip at a place on the earth gives

1 the horizontal component of the earth's magnetic field
2 the location of geographic meridian
3 the vertical component of the earth's field
4 the direction of the earth's magnetic field
PHXII05:MAGNETISM and MATTER

360675 A dip needle lies initially in the magnetic meridian when it shows an angle of \(\operatorname{dip} \theta\) at a place. The dip circle is rotated through an angle \(x\) in the horizontal plane and then it shown an angle of \(\operatorname{dip} \theta^{\prime}\). Then \(\dfrac{\tan \theta^{\prime}}{\tan \theta}\) is

1 \(\cos x\)
2 \(\dfrac{1}{\cos x}\)
3 \(\dfrac{1}{\sin x}\)
4 \(\dfrac{1}{\tan x}\)
PHXII05:MAGNETISM and MATTER

360676 The horizontal component of earth's magnetic field at a place is \({0.3 \times 10^{-4} {~T}}\). If the angle of dip is \({60^{\circ}}\), what is the total earth's magnetic field in \({\mu {T}}\) ?

1 \(50\,\mu T\)
2 \(45\,\mu T\)
3 \(60\,\mu T\)
4 \(70\,\mu T\)
PHXII05:MAGNETISM and MATTER

360677 If the angle of dip at two places are \(30^{\circ}\) and \(45^{\circ}\) respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be (Given total field at the two places is same)

1 \(\sqrt{3}: \sqrt{2}\)
2 \(1: 2\)
3 \(1: \sqrt{2}\)
4 \(1: \sqrt{3}\)
PHXII05:MAGNETISM and MATTER

360678 The earth's magnetic field at a certain place has a horizontal component of 0.3\(G\) and total strength 0.5\(G\). The angle of dip in \(\delta\), then

1 \(\delta=\tan ^{-1} \dfrac{4}{3}\)
2 \(\delta=\tan ^{-1} \dfrac{5}{3}\)
3 \(\delta=\tan ^{-1} \dfrac{3}{5}\)
4 \(\delta=\tan ^{-1} \dfrac{3}{4}\)
Join With Us for More Updates
PHXII05:MAGNETISM and MATTER

360674 The angle of dip at a place on the earth gives

1 the horizontal component of the earth's magnetic field
2 the location of geographic meridian
3 the vertical component of the earth's field
4 the direction of the earth's magnetic field
PHXII05:MAGNETISM and MATTER

360675 A dip needle lies initially in the magnetic meridian when it shows an angle of \(\operatorname{dip} \theta\) at a place. The dip circle is rotated through an angle \(x\) in the horizontal plane and then it shown an angle of \(\operatorname{dip} \theta^{\prime}\). Then \(\dfrac{\tan \theta^{\prime}}{\tan \theta}\) is

1 \(\cos x\)
2 \(\dfrac{1}{\cos x}\)
3 \(\dfrac{1}{\sin x}\)
4 \(\dfrac{1}{\tan x}\)
PHXII05:MAGNETISM and MATTER

360676 The horizontal component of earth's magnetic field at a place is \({0.3 \times 10^{-4} {~T}}\). If the angle of dip is \({60^{\circ}}\), what is the total earth's magnetic field in \({\mu {T}}\) ?

1 \(50\,\mu T\)
2 \(45\,\mu T\)
3 \(60\,\mu T\)
4 \(70\,\mu T\)
PHXII05:MAGNETISM and MATTER

360677 If the angle of dip at two places are \(30^{\circ}\) and \(45^{\circ}\) respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be (Given total field at the two places is same)

1 \(\sqrt{3}: \sqrt{2}\)
2 \(1: 2\)
3 \(1: \sqrt{2}\)
4 \(1: \sqrt{3}\)
PHXII05:MAGNETISM and MATTER

360678 The earth's magnetic field at a certain place has a horizontal component of 0.3\(G\) and total strength 0.5\(G\). The angle of dip in \(\delta\), then

1 \(\delta=\tan ^{-1} \dfrac{4}{3}\)
2 \(\delta=\tan ^{-1} \dfrac{5}{3}\)
3 \(\delta=\tan ^{-1} \dfrac{3}{5}\)
4 \(\delta=\tan ^{-1} \dfrac{3}{4}\)