NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII05:MAGNETISM and MATTER
360670
At the magnetic north pole of the earth, the value of the horizontal component of earth's magnetic field and angle of dip are respectively
1 Maximum, maximum
2 Maximum, minimum
3 Zero, maximum
4 Minimum, maximum
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360671
In the magnetic meridian of a certain place. The horizontal component of the earths magnetic field is 0.26 and the dip angle \(60^{\circ}\). What is the magnetic field of the earth in this location?
1 \(0.48\,G\)
2 \(0.50\,G\)
3 \(0.60\,G\)
4 \(0.52\,G\)
Explanation:
Given, \(B_{H}=0.26 G, \delta=60^{\circ}\) As, \(B_{H}=B \cos \delta\) \(B=\dfrac{B_{H}}{\cos \delta}=\dfrac{0.26 G}{\cos 60^{\circ}}=\dfrac{0.26 G}{0.5}\) \(B=0.52 G\) So, correct option is (4)
AIIMS - 2013
PHXII05:MAGNETISM and MATTER
360672
The angle of dip at a place on the earth's surface gives
1 Direction of earth's magnetic field
2 Horizontal component of earth's magnetic field
3 Vertical component of earth's magnetic field
4 Location of geographic poles
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360673
A magnetic needle free to rotate in a fixed vertical plane stays at the angle \(60^{\circ}\) with the horizontal. If the dip at that place is \(37^{\circ}\), find the angle of the fixed vertical plane with the meridian.
360670
At the magnetic north pole of the earth, the value of the horizontal component of earth's magnetic field and angle of dip are respectively
1 Maximum, maximum
2 Maximum, minimum
3 Zero, maximum
4 Minimum, maximum
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360671
In the magnetic meridian of a certain place. The horizontal component of the earths magnetic field is 0.26 and the dip angle \(60^{\circ}\). What is the magnetic field of the earth in this location?
1 \(0.48\,G\)
2 \(0.50\,G\)
3 \(0.60\,G\)
4 \(0.52\,G\)
Explanation:
Given, \(B_{H}=0.26 G, \delta=60^{\circ}\) As, \(B_{H}=B \cos \delta\) \(B=\dfrac{B_{H}}{\cos \delta}=\dfrac{0.26 G}{\cos 60^{\circ}}=\dfrac{0.26 G}{0.5}\) \(B=0.52 G\) So, correct option is (4)
AIIMS - 2013
PHXII05:MAGNETISM and MATTER
360672
The angle of dip at a place on the earth's surface gives
1 Direction of earth's magnetic field
2 Horizontal component of earth's magnetic field
3 Vertical component of earth's magnetic field
4 Location of geographic poles
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360673
A magnetic needle free to rotate in a fixed vertical plane stays at the angle \(60^{\circ}\) with the horizontal. If the dip at that place is \(37^{\circ}\), find the angle of the fixed vertical plane with the meridian.
360670
At the magnetic north pole of the earth, the value of the horizontal component of earth's magnetic field and angle of dip are respectively
1 Maximum, maximum
2 Maximum, minimum
3 Zero, maximum
4 Minimum, maximum
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360671
In the magnetic meridian of a certain place. The horizontal component of the earths magnetic field is 0.26 and the dip angle \(60^{\circ}\). What is the magnetic field of the earth in this location?
1 \(0.48\,G\)
2 \(0.50\,G\)
3 \(0.60\,G\)
4 \(0.52\,G\)
Explanation:
Given, \(B_{H}=0.26 G, \delta=60^{\circ}\) As, \(B_{H}=B \cos \delta\) \(B=\dfrac{B_{H}}{\cos \delta}=\dfrac{0.26 G}{\cos 60^{\circ}}=\dfrac{0.26 G}{0.5}\) \(B=0.52 G\) So, correct option is (4)
AIIMS - 2013
PHXII05:MAGNETISM and MATTER
360672
The angle of dip at a place on the earth's surface gives
1 Direction of earth's magnetic field
2 Horizontal component of earth's magnetic field
3 Vertical component of earth's magnetic field
4 Location of geographic poles
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360673
A magnetic needle free to rotate in a fixed vertical plane stays at the angle \(60^{\circ}\) with the horizontal. If the dip at that place is \(37^{\circ}\), find the angle of the fixed vertical plane with the meridian.
360670
At the magnetic north pole of the earth, the value of the horizontal component of earth's magnetic field and angle of dip are respectively
1 Maximum, maximum
2 Maximum, minimum
3 Zero, maximum
4 Minimum, maximum
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360671
In the magnetic meridian of a certain place. The horizontal component of the earths magnetic field is 0.26 and the dip angle \(60^{\circ}\). What is the magnetic field of the earth in this location?
1 \(0.48\,G\)
2 \(0.50\,G\)
3 \(0.60\,G\)
4 \(0.52\,G\)
Explanation:
Given, \(B_{H}=0.26 G, \delta=60^{\circ}\) As, \(B_{H}=B \cos \delta\) \(B=\dfrac{B_{H}}{\cos \delta}=\dfrac{0.26 G}{\cos 60^{\circ}}=\dfrac{0.26 G}{0.5}\) \(B=0.52 G\) So, correct option is (4)
AIIMS - 2013
PHXII05:MAGNETISM and MATTER
360672
The angle of dip at a place on the earth's surface gives
1 Direction of earth's magnetic field
2 Horizontal component of earth's magnetic field
3 Vertical component of earth's magnetic field
4 Location of geographic poles
Explanation:
Conceptual Question
PHXII05:MAGNETISM and MATTER
360673
A magnetic needle free to rotate in a fixed vertical plane stays at the angle \(60^{\circ}\) with the horizontal. If the dip at that place is \(37^{\circ}\), find the angle of the fixed vertical plane with the meridian.