Explanation:
On bending the magnet, the length
of the magnet,
\(AC = AB + BC\)
\(\,\,\,\,\,\,\,\,\, = L\sin \left( {\frac{\theta }{2}} \right) + L\sin \left( {\frac{\theta }{2}} \right)\)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mkern 1mu} \because \theta = 60^\circ \)
\(\,\,\,\, = 2L\sin 30^\circ = 2L \times 1/2 = L\)