360531
Asolenoid has core of a material with relative permeability 500 and its windings carry a current of 1\(A\). The number of turns of the solenoid is 500 per metre. The magnetisation of the material is nearly
1 \(2.0 \times {10^5}A{m^{ - 1}}\)
2 \(2.5 \times {10^5}A{m^{ - 1}}\)
3 \(5 \times {10^5}A{m^{ - 1}}\)
4 \(2.0 \times {10^3}A{m^{ - 1}}\)
Explanation:
Here, \(n = 500\)/turns/\(m,I = 1A\), \({\mu _r} = 500\) Magnetic intensity, \(H = nI = 500\,{m^{ - 1}} \times 1A = 500A{m^{ - 1}}\) As \(\mu_{r}=1+\chi\), where \(\chi\) is the magnetic susceptibility of the material \(\text { or } \chi=\left(\mu_{r}-1\right)\) Magnetisation \( = \chi H = ({\mu _r} - 1)H\) \( = (500 - 1) \times 500A{m^{ - 1}} = 499 \times 500A{m^{ - 1}}\) \( = 2.495 \times {10^5}A{m^{ - 1}}\) \( \approx 2.5 \times {10^5}A{m^{ - 1}}\)
PHXII05:MAGNETISM and MATTER
360532
The ratio of intensities of magnetic field, at distances \(x\) and \(2 x\) from the centre of magnet of length 2\(cm\) on its axis, will be
360533
A permanent magnet in the shape of a thin cylinder of length 10\(cm\) has \(M = {10^6}\;A/m\). The magnetisation current \(I_{M}\) is
1 \({10^4}A\)
2 \({10^5}A\)
3 \({10^2}A\)
4 \({10^3}A\)
Explanation:
Given, \(M\) (intensity of magnetisation) \( = {10^6}\;A/m\). \(l{\rm{ }}({\mathop{\rm length}\nolimits} ) = 10\;cm = 10 \times {10^{ - 2}}\;m = 0.1\;m\) and \(I_{M}=\) magnetisation current We know that \(M = \frac{{{I_M}}}{l}\) \( \Rightarrow {I_M} = M \times l\) \( = {10^6} \times 0.1 = {10^5}A\) Note: Here, \(\mathrm{M}=\) intensity of magnetisation as its unit is given as \(A/m\).
NCERT Exemplar
PHXII05:MAGNETISM and MATTER
360534
A solenoid of 500 turns/\(m\) is carrying a current of 2\(A\). Relative permeability of core material of solenoid is 5000 . The magnitude of the magnetic intensity is
360531
Asolenoid has core of a material with relative permeability 500 and its windings carry a current of 1\(A\). The number of turns of the solenoid is 500 per metre. The magnetisation of the material is nearly
1 \(2.0 \times {10^5}A{m^{ - 1}}\)
2 \(2.5 \times {10^5}A{m^{ - 1}}\)
3 \(5 \times {10^5}A{m^{ - 1}}\)
4 \(2.0 \times {10^3}A{m^{ - 1}}\)
Explanation:
Here, \(n = 500\)/turns/\(m,I = 1A\), \({\mu _r} = 500\) Magnetic intensity, \(H = nI = 500\,{m^{ - 1}} \times 1A = 500A{m^{ - 1}}\) As \(\mu_{r}=1+\chi\), where \(\chi\) is the magnetic susceptibility of the material \(\text { or } \chi=\left(\mu_{r}-1\right)\) Magnetisation \( = \chi H = ({\mu _r} - 1)H\) \( = (500 - 1) \times 500A{m^{ - 1}} = 499 \times 500A{m^{ - 1}}\) \( = 2.495 \times {10^5}A{m^{ - 1}}\) \( \approx 2.5 \times {10^5}A{m^{ - 1}}\)
PHXII05:MAGNETISM and MATTER
360532
The ratio of intensities of magnetic field, at distances \(x\) and \(2 x\) from the centre of magnet of length 2\(cm\) on its axis, will be
360533
A permanent magnet in the shape of a thin cylinder of length 10\(cm\) has \(M = {10^6}\;A/m\). The magnetisation current \(I_{M}\) is
1 \({10^4}A\)
2 \({10^5}A\)
3 \({10^2}A\)
4 \({10^3}A\)
Explanation:
Given, \(M\) (intensity of magnetisation) \( = {10^6}\;A/m\). \(l{\rm{ }}({\mathop{\rm length}\nolimits} ) = 10\;cm = 10 \times {10^{ - 2}}\;m = 0.1\;m\) and \(I_{M}=\) magnetisation current We know that \(M = \frac{{{I_M}}}{l}\) \( \Rightarrow {I_M} = M \times l\) \( = {10^6} \times 0.1 = {10^5}A\) Note: Here, \(\mathrm{M}=\) intensity of magnetisation as its unit is given as \(A/m\).
NCERT Exemplar
PHXII05:MAGNETISM and MATTER
360534
A solenoid of 500 turns/\(m\) is carrying a current of 2\(A\). Relative permeability of core material of solenoid is 5000 . The magnitude of the magnetic intensity is
360531
Asolenoid has core of a material with relative permeability 500 and its windings carry a current of 1\(A\). The number of turns of the solenoid is 500 per metre. The magnetisation of the material is nearly
1 \(2.0 \times {10^5}A{m^{ - 1}}\)
2 \(2.5 \times {10^5}A{m^{ - 1}}\)
3 \(5 \times {10^5}A{m^{ - 1}}\)
4 \(2.0 \times {10^3}A{m^{ - 1}}\)
Explanation:
Here, \(n = 500\)/turns/\(m,I = 1A\), \({\mu _r} = 500\) Magnetic intensity, \(H = nI = 500\,{m^{ - 1}} \times 1A = 500A{m^{ - 1}}\) As \(\mu_{r}=1+\chi\), where \(\chi\) is the magnetic susceptibility of the material \(\text { or } \chi=\left(\mu_{r}-1\right)\) Magnetisation \( = \chi H = ({\mu _r} - 1)H\) \( = (500 - 1) \times 500A{m^{ - 1}} = 499 \times 500A{m^{ - 1}}\) \( = 2.495 \times {10^5}A{m^{ - 1}}\) \( \approx 2.5 \times {10^5}A{m^{ - 1}}\)
PHXII05:MAGNETISM and MATTER
360532
The ratio of intensities of magnetic field, at distances \(x\) and \(2 x\) from the centre of magnet of length 2\(cm\) on its axis, will be
360533
A permanent magnet in the shape of a thin cylinder of length 10\(cm\) has \(M = {10^6}\;A/m\). The magnetisation current \(I_{M}\) is
1 \({10^4}A\)
2 \({10^5}A\)
3 \({10^2}A\)
4 \({10^3}A\)
Explanation:
Given, \(M\) (intensity of magnetisation) \( = {10^6}\;A/m\). \(l{\rm{ }}({\mathop{\rm length}\nolimits} ) = 10\;cm = 10 \times {10^{ - 2}}\;m = 0.1\;m\) and \(I_{M}=\) magnetisation current We know that \(M = \frac{{{I_M}}}{l}\) \( \Rightarrow {I_M} = M \times l\) \( = {10^6} \times 0.1 = {10^5}A\) Note: Here, \(\mathrm{M}=\) intensity of magnetisation as its unit is given as \(A/m\).
NCERT Exemplar
PHXII05:MAGNETISM and MATTER
360534
A solenoid of 500 turns/\(m\) is carrying a current of 2\(A\). Relative permeability of core material of solenoid is 5000 . The magnitude of the magnetic intensity is
360531
Asolenoid has core of a material with relative permeability 500 and its windings carry a current of 1\(A\). The number of turns of the solenoid is 500 per metre. The magnetisation of the material is nearly
1 \(2.0 \times {10^5}A{m^{ - 1}}\)
2 \(2.5 \times {10^5}A{m^{ - 1}}\)
3 \(5 \times {10^5}A{m^{ - 1}}\)
4 \(2.0 \times {10^3}A{m^{ - 1}}\)
Explanation:
Here, \(n = 500\)/turns/\(m,I = 1A\), \({\mu _r} = 500\) Magnetic intensity, \(H = nI = 500\,{m^{ - 1}} \times 1A = 500A{m^{ - 1}}\) As \(\mu_{r}=1+\chi\), where \(\chi\) is the magnetic susceptibility of the material \(\text { or } \chi=\left(\mu_{r}-1\right)\) Magnetisation \( = \chi H = ({\mu _r} - 1)H\) \( = (500 - 1) \times 500A{m^{ - 1}} = 499 \times 500A{m^{ - 1}}\) \( = 2.495 \times {10^5}A{m^{ - 1}}\) \( \approx 2.5 \times {10^5}A{m^{ - 1}}\)
PHXII05:MAGNETISM and MATTER
360532
The ratio of intensities of magnetic field, at distances \(x\) and \(2 x\) from the centre of magnet of length 2\(cm\) on its axis, will be
360533
A permanent magnet in the shape of a thin cylinder of length 10\(cm\) has \(M = {10^6}\;A/m\). The magnetisation current \(I_{M}\) is
1 \({10^4}A\)
2 \({10^5}A\)
3 \({10^2}A\)
4 \({10^3}A\)
Explanation:
Given, \(M\) (intensity of magnetisation) \( = {10^6}\;A/m\). \(l{\rm{ }}({\mathop{\rm length}\nolimits} ) = 10\;cm = 10 \times {10^{ - 2}}\;m = 0.1\;m\) and \(I_{M}=\) magnetisation current We know that \(M = \frac{{{I_M}}}{l}\) \( \Rightarrow {I_M} = M \times l\) \( = {10^6} \times 0.1 = {10^5}A\) Note: Here, \(\mathrm{M}=\) intensity of magnetisation as its unit is given as \(A/m\).
NCERT Exemplar
PHXII05:MAGNETISM and MATTER
360534
A solenoid of 500 turns/\(m\) is carrying a current of 2\(A\). Relative permeability of core material of solenoid is 5000 . The magnitude of the magnetic intensity is
