Explanation:
The r.m.s velocity of the gas molecules
\({v_{rms}} = \sqrt {\frac{{3RT}}{M}} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 1 \right)\)
Now Temperature ' \(T\) ' increased to \(5 T\).
\({v_{rms}} = \sqrt {\frac{{3R(5T)}}{M}} = \sqrt 5 \,{v_{rms}}\)