NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI13:KINETIC THEORY
360243
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is \({2 {~km} / {s}}\), the root mean square velocity of oxygen at the same condition in \({{km} / {s}}\) is
1 1.0
2 1.5
3 2.0
4 0.5
Explanation:
\(RMS\) velocity of gas particles is given by \(\begin{gathered}v_{r m s}=\sqrt{\dfrac{3 R T}{M}} \Rightarrow v_{r m s} \propto \dfrac{1}{\sqrt{M}} \\\Rightarrow \dfrac{v_{O_{2}}}{v_{O_{2}}}=\sqrt{\dfrac{M_{H_{2}}}{M_{O_{2}}}} \Rightarrow \dfrac{V_{O_{2}}}{2}=\sqrt{\dfrac{2}{32}}\end{gathered}\) \({\Rightarrow V_{{O}_{2}}=2 \times \dfrac{1}{4}=0.5 {~km} / {s}}\)
JEE - 2024
PHXI13:KINETIC THEORY
360244
1 mole of \({H_2}\) and 1 mole of \(He\) at a pressure of \({P_0}\) and \(2{P_0}\) respectively and a temperatures \({T_0}\) are kept in two different containers. The ratio of their rms velocities is \({c_{{H_2}}}:{c_{He}} = \)
360243
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is \({2 {~km} / {s}}\), the root mean square velocity of oxygen at the same condition in \({{km} / {s}}\) is
1 1.0
2 1.5
3 2.0
4 0.5
Explanation:
\(RMS\) velocity of gas particles is given by \(\begin{gathered}v_{r m s}=\sqrt{\dfrac{3 R T}{M}} \Rightarrow v_{r m s} \propto \dfrac{1}{\sqrt{M}} \\\Rightarrow \dfrac{v_{O_{2}}}{v_{O_{2}}}=\sqrt{\dfrac{M_{H_{2}}}{M_{O_{2}}}} \Rightarrow \dfrac{V_{O_{2}}}{2}=\sqrt{\dfrac{2}{32}}\end{gathered}\) \({\Rightarrow V_{{O}_{2}}=2 \times \dfrac{1}{4}=0.5 {~km} / {s}}\)
JEE - 2024
PHXI13:KINETIC THEORY
360244
1 mole of \({H_2}\) and 1 mole of \(He\) at a pressure of \({P_0}\) and \(2{P_0}\) respectively and a temperatures \({T_0}\) are kept in two different containers. The ratio of their rms velocities is \({c_{{H_2}}}:{c_{He}} = \)
360243
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is \({2 {~km} / {s}}\), the root mean square velocity of oxygen at the same condition in \({{km} / {s}}\) is
1 1.0
2 1.5
3 2.0
4 0.5
Explanation:
\(RMS\) velocity of gas particles is given by \(\begin{gathered}v_{r m s}=\sqrt{\dfrac{3 R T}{M}} \Rightarrow v_{r m s} \propto \dfrac{1}{\sqrt{M}} \\\Rightarrow \dfrac{v_{O_{2}}}{v_{O_{2}}}=\sqrt{\dfrac{M_{H_{2}}}{M_{O_{2}}}} \Rightarrow \dfrac{V_{O_{2}}}{2}=\sqrt{\dfrac{2}{32}}\end{gathered}\) \({\Rightarrow V_{{O}_{2}}=2 \times \dfrac{1}{4}=0.5 {~km} / {s}}\)
JEE - 2024
PHXI13:KINETIC THEORY
360244
1 mole of \({H_2}\) and 1 mole of \(He\) at a pressure of \({P_0}\) and \(2{P_0}\) respectively and a temperatures \({T_0}\) are kept in two different containers. The ratio of their rms velocities is \({c_{{H_2}}}:{c_{He}} = \)
360243
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is \({2 {~km} / {s}}\), the root mean square velocity of oxygen at the same condition in \({{km} / {s}}\) is
1 1.0
2 1.5
3 2.0
4 0.5
Explanation:
\(RMS\) velocity of gas particles is given by \(\begin{gathered}v_{r m s}=\sqrt{\dfrac{3 R T}{M}} \Rightarrow v_{r m s} \propto \dfrac{1}{\sqrt{M}} \\\Rightarrow \dfrac{v_{O_{2}}}{v_{O_{2}}}=\sqrt{\dfrac{M_{H_{2}}}{M_{O_{2}}}} \Rightarrow \dfrac{V_{O_{2}}}{2}=\sqrt{\dfrac{2}{32}}\end{gathered}\) \({\Rightarrow V_{{O}_{2}}=2 \times \dfrac{1}{4}=0.5 {~km} / {s}}\)
JEE - 2024
PHXI13:KINETIC THEORY
360244
1 mole of \({H_2}\) and 1 mole of \(He\) at a pressure of \({P_0}\) and \(2{P_0}\) respectively and a temperatures \({T_0}\) are kept in two different containers. The ratio of their rms velocities is \({c_{{H_2}}}:{c_{He}} = \)
