The Work-Energy Theorem for a Constant/Variable Force
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PHXI06:WORK ENERGY AND POWER

355677 If force acting on a body is inversely proportional to its speed, then its kinetic energy is

1 Linearly related to time
2 Inversely proportional to time
3 Inversely proportional to the square of time
4 A constant
PHXI06:WORK ENERGY AND POWER

355678 A body of mass 3 \(kg\) is under a force which causes a displacement in it and is given by \(S=\dfrac{t^{3}}{3}\) (in metres). Find the work done by the force in first 2 seconds.

1 24 \(J\)
2 2 \(J\)
3 3.8 \(J\)
4 5.2 \(J\)
PHXI06:WORK ENERGY AND POWER

355679 How much work must be done by a force on 50 \(kg\) body in order to accelerate it from rest to 20 \(m/s\) in \(10 s ?\)

1 \({10^4}\;J\)
2 \(4 \times {10^4}J\)
3 \({10^{ - 3}}\;J\)
4 \(2 \times {10^3}J\)
PHXI06:WORK ENERGY AND POWER

355680 A loaded trolley and uploaded trolley are both moving with same kinetic energy. The mass of the loaded trolley is three times that of the unloaded trolley. Brakes are applied to both of them, so as to exert an equal retarding force. If \(t_{1}\) and \(t_{2}\) be the time taken by the unloaded and loaded trolleys respectively, before coming to a stop, then:

1 \(t_{1}=\sqrt{3} t_{2}\)
2 \(t_{1}=3 t_{2}\)
3 \(t_{2}=3 t_{1}\)
4 \(t_{1}=2 / 3 t_{2}\)
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PHXI06:WORK ENERGY AND POWER

355677 If force acting on a body is inversely proportional to its speed, then its kinetic energy is

1 Linearly related to time
2 Inversely proportional to time
3 Inversely proportional to the square of time
4 A constant
PHXI06:WORK ENERGY AND POWER

355678 A body of mass 3 \(kg\) is under a force which causes a displacement in it and is given by \(S=\dfrac{t^{3}}{3}\) (in metres). Find the work done by the force in first 2 seconds.

1 24 \(J\)
2 2 \(J\)
3 3.8 \(J\)
4 5.2 \(J\)
PHXI06:WORK ENERGY AND POWER

355679 How much work must be done by a force on 50 \(kg\) body in order to accelerate it from rest to 20 \(m/s\) in \(10 s ?\)

1 \({10^4}\;J\)
2 \(4 \times {10^4}J\)
3 \({10^{ - 3}}\;J\)
4 \(2 \times {10^3}J\)
PHXI06:WORK ENERGY AND POWER

355680 A loaded trolley and uploaded trolley are both moving with same kinetic energy. The mass of the loaded trolley is three times that of the unloaded trolley. Brakes are applied to both of them, so as to exert an equal retarding force. If \(t_{1}\) and \(t_{2}\) be the time taken by the unloaded and loaded trolleys respectively, before coming to a stop, then:

1 \(t_{1}=\sqrt{3} t_{2}\)
2 \(t_{1}=3 t_{2}\)
3 \(t_{2}=3 t_{1}\)
4 \(t_{1}=2 / 3 t_{2}\)
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI06:WORK ENERGY AND POWER

355677 If force acting on a body is inversely proportional to its speed, then its kinetic energy is

1 Linearly related to time
2 Inversely proportional to time
3 Inversely proportional to the square of time
4 A constant
PHXI06:WORK ENERGY AND POWER

355678 A body of mass 3 \(kg\) is under a force which causes a displacement in it and is given by \(S=\dfrac{t^{3}}{3}\) (in metres). Find the work done by the force in first 2 seconds.

1 24 \(J\)
2 2 \(J\)
3 3.8 \(J\)
4 5.2 \(J\)
PHXI06:WORK ENERGY AND POWER

355679 How much work must be done by a force on 50 \(kg\) body in order to accelerate it from rest to 20 \(m/s\) in \(10 s ?\)

1 \({10^4}\;J\)
2 \(4 \times {10^4}J\)
3 \({10^{ - 3}}\;J\)
4 \(2 \times {10^3}J\)
PHXI06:WORK ENERGY AND POWER

355680 A loaded trolley and uploaded trolley are both moving with same kinetic energy. The mass of the loaded trolley is three times that of the unloaded trolley. Brakes are applied to both of them, so as to exert an equal retarding force. If \(t_{1}\) and \(t_{2}\) be the time taken by the unloaded and loaded trolleys respectively, before coming to a stop, then:

1 \(t_{1}=\sqrt{3} t_{2}\)
2 \(t_{1}=3 t_{2}\)
3 \(t_{2}=3 t_{1}\)
4 \(t_{1}=2 / 3 t_{2}\)
NEET DIGITAL LIBRARY
PHXI06:WORK ENERGY AND POWER

355677 If force acting on a body is inversely proportional to its speed, then its kinetic energy is

1 Linearly related to time
2 Inversely proportional to time
3 Inversely proportional to the square of time
4 A constant
PHXI06:WORK ENERGY AND POWER

355678 A body of mass 3 \(kg\) is under a force which causes a displacement in it and is given by \(S=\dfrac{t^{3}}{3}\) (in metres). Find the work done by the force in first 2 seconds.

1 24 \(J\)
2 2 \(J\)
3 3.8 \(J\)
4 5.2 \(J\)
PHXI06:WORK ENERGY AND POWER

355679 How much work must be done by a force on 50 \(kg\) body in order to accelerate it from rest to 20 \(m/s\) in \(10 s ?\)

1 \({10^4}\;J\)
2 \(4 \times {10^4}J\)
3 \({10^{ - 3}}\;J\)
4 \(2 \times {10^3}J\)
PHXI06:WORK ENERGY AND POWER

355680 A loaded trolley and uploaded trolley are both moving with same kinetic energy. The mass of the loaded trolley is three times that of the unloaded trolley. Brakes are applied to both of them, so as to exert an equal retarding force. If \(t_{1}\) and \(t_{2}\) be the time taken by the unloaded and loaded trolleys respectively, before coming to a stop, then:

1 \(t_{1}=\sqrt{3} t_{2}\)
2 \(t_{1}=3 t_{2}\)
3 \(t_{2}=3 t_{1}\)
4 \(t_{1}=2 / 3 t_{2}\)
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