Power
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI06:WORK ENERGY AND POWER

355467 A car of weight \(W\) is on an inclined road that rises by 100 \(m\) over a distance of 1 \(km\) and applies a constant frictional force \(\frac{W}{{20}}\) on the car. While moving uphill on the road at a speed of \(10\;m/s\), 1 the car needs power \(P\). If it needs power \(\dfrac{P}{2}\) while moving downhill at speed \(v\) then value of \(v\) is :

1 \(5\;m{s^{ - 1}}\)
2 \(20\;m{s^{ - 1}}\)
3 \(10\;m{s^{ - 1}}\)
4 \(15\;m{s^{ - 1}}\)
PHXI06:WORK ENERGY AND POWER

355468 A particle of mass \({\dfrac{10}{7} {~kg}}\) is moving in the positive \({x}\)-direction. Its initial position is \({x=0}\) and initial velocity is \({1 {~m} / {s}}\). The velocity at \({x=10 m}\) is (use the graph given)
supporting img

1 \({4 {~m} / {s}}\)
2 \({2 {~m} / {s}}\)
3 \({3 \sqrt{2} {~m} / {s}}\)
4 \({100 / 3 {~m} / {s}}\)
PHXI06:WORK ENERGY AND POWER

355469 A force \({F}\) acting on a body depends on its displacement \({s}\) as \({F \propto s^{-1 / 3}}\). The power delivered by \({F}\) will depend on displacement as

1 \({s^{0}}\)
2 \({s}\)
3 \({s^{2 / 3}}\)
4 \({s^{1 / 2}}\)
PHXI06:WORK ENERGY AND POWER

355470 A car of mass \({m}\) is accelerating on a smooth level road under a single force \({F}\). The power delivered to the car is constant and equal to \({P}\). If the car's velocity at an instant is \({v}\), then after traveling how much distance, it gets doubled?
supporting img

1 \({\dfrac{7 m v^{3}}{3 P}}\)
2 \({\dfrac{4 m v^{3}}{3 P}}\)
3 \({\dfrac{m v^{3}}{P}}\)
4 \({\dfrac{18 m v^{3}}{7 P}}\)
PHXI06:WORK ENERGY AND POWER

355467 A car of weight \(W\) is on an inclined road that rises by 100 \(m\) over a distance of 1 \(km\) and applies a constant frictional force \(\frac{W}{{20}}\) on the car. While moving uphill on the road at a speed of \(10\;m/s\), 1 the car needs power \(P\). If it needs power \(\dfrac{P}{2}\) while moving downhill at speed \(v\) then value of \(v\) is :

1 \(5\;m{s^{ - 1}}\)
2 \(20\;m{s^{ - 1}}\)
3 \(10\;m{s^{ - 1}}\)
4 \(15\;m{s^{ - 1}}\)
PHXI06:WORK ENERGY AND POWER

355468 A particle of mass \({\dfrac{10}{7} {~kg}}\) is moving in the positive \({x}\)-direction. Its initial position is \({x=0}\) and initial velocity is \({1 {~m} / {s}}\). The velocity at \({x=10 m}\) is (use the graph given)
supporting img

1 \({4 {~m} / {s}}\)
2 \({2 {~m} / {s}}\)
3 \({3 \sqrt{2} {~m} / {s}}\)
4 \({100 / 3 {~m} / {s}}\)
PHXI06:WORK ENERGY AND POWER

355469 A force \({F}\) acting on a body depends on its displacement \({s}\) as \({F \propto s^{-1 / 3}}\). The power delivered by \({F}\) will depend on displacement as

1 \({s^{0}}\)
2 \({s}\)
3 \({s^{2 / 3}}\)
4 \({s^{1 / 2}}\)
PHXI06:WORK ENERGY AND POWER

355470 A car of mass \({m}\) is accelerating on a smooth level road under a single force \({F}\). The power delivered to the car is constant and equal to \({P}\). If the car's velocity at an instant is \({v}\), then after traveling how much distance, it gets doubled?
supporting img

1 \({\dfrac{7 m v^{3}}{3 P}}\)
2 \({\dfrac{4 m v^{3}}{3 P}}\)
3 \({\dfrac{m v^{3}}{P}}\)
4 \({\dfrac{18 m v^{3}}{7 P}}\)
PHXI06:WORK ENERGY AND POWER

355467 A car of weight \(W\) is on an inclined road that rises by 100 \(m\) over a distance of 1 \(km\) and applies a constant frictional force \(\frac{W}{{20}}\) on the car. While moving uphill on the road at a speed of \(10\;m/s\), 1 the car needs power \(P\). If it needs power \(\dfrac{P}{2}\) while moving downhill at speed \(v\) then value of \(v\) is :

1 \(5\;m{s^{ - 1}}\)
2 \(20\;m{s^{ - 1}}\)
3 \(10\;m{s^{ - 1}}\)
4 \(15\;m{s^{ - 1}}\)
PHXI06:WORK ENERGY AND POWER

355468 A particle of mass \({\dfrac{10}{7} {~kg}}\) is moving in the positive \({x}\)-direction. Its initial position is \({x=0}\) and initial velocity is \({1 {~m} / {s}}\). The velocity at \({x=10 m}\) is (use the graph given)
supporting img

1 \({4 {~m} / {s}}\)
2 \({2 {~m} / {s}}\)
3 \({3 \sqrt{2} {~m} / {s}}\)
4 \({100 / 3 {~m} / {s}}\)
PHXI06:WORK ENERGY AND POWER

355469 A force \({F}\) acting on a body depends on its displacement \({s}\) as \({F \propto s^{-1 / 3}}\). The power delivered by \({F}\) will depend on displacement as

1 \({s^{0}}\)
2 \({s}\)
3 \({s^{2 / 3}}\)
4 \({s^{1 / 2}}\)
PHXI06:WORK ENERGY AND POWER

355470 A car of mass \({m}\) is accelerating on a smooth level road under a single force \({F}\). The power delivered to the car is constant and equal to \({P}\). If the car's velocity at an instant is \({v}\), then after traveling how much distance, it gets doubled?
supporting img

1 \({\dfrac{7 m v^{3}}{3 P}}\)
2 \({\dfrac{4 m v^{3}}{3 P}}\)
3 \({\dfrac{m v^{3}}{P}}\)
4 \({\dfrac{18 m v^{3}}{7 P}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI06:WORK ENERGY AND POWER

355467 A car of weight \(W\) is on an inclined road that rises by 100 \(m\) over a distance of 1 \(km\) and applies a constant frictional force \(\frac{W}{{20}}\) on the car. While moving uphill on the road at a speed of \(10\;m/s\), 1 the car needs power \(P\). If it needs power \(\dfrac{P}{2}\) while moving downhill at speed \(v\) then value of \(v\) is :

1 \(5\;m{s^{ - 1}}\)
2 \(20\;m{s^{ - 1}}\)
3 \(10\;m{s^{ - 1}}\)
4 \(15\;m{s^{ - 1}}\)
PHXI06:WORK ENERGY AND POWER

355468 A particle of mass \({\dfrac{10}{7} {~kg}}\) is moving in the positive \({x}\)-direction. Its initial position is \({x=0}\) and initial velocity is \({1 {~m} / {s}}\). The velocity at \({x=10 m}\) is (use the graph given)
supporting img

1 \({4 {~m} / {s}}\)
2 \({2 {~m} / {s}}\)
3 \({3 \sqrt{2} {~m} / {s}}\)
4 \({100 / 3 {~m} / {s}}\)
PHXI06:WORK ENERGY AND POWER

355469 A force \({F}\) acting on a body depends on its displacement \({s}\) as \({F \propto s^{-1 / 3}}\). The power delivered by \({F}\) will depend on displacement as

1 \({s^{0}}\)
2 \({s}\)
3 \({s^{2 / 3}}\)
4 \({s^{1 / 2}}\)
PHXI06:WORK ENERGY AND POWER

355470 A car of mass \({m}\) is accelerating on a smooth level road under a single force \({F}\). The power delivered to the car is constant and equal to \({P}\). If the car's velocity at an instant is \({v}\), then after traveling how much distance, it gets doubled?
supporting img

1 \({\dfrac{7 m v^{3}}{3 P}}\)
2 \({\dfrac{4 m v^{3}}{3 P}}\)
3 \({\dfrac{m v^{3}}{P}}\)
4 \({\dfrac{18 m v^{3}}{7 P}}\)