355213
A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when
1 \(M' = 2M\)
2 \(M' = M\)
3 \(M' > > M\)
4 \(M' < < M\)
Explanation:
If \(M=M^{\prime}\), then bullet will transfer whole of its velocity ( \(100 \%\) of its \(KE\)) to block and will itself come to rest.
PHXI06:WORK ENERGY AND POWER
355214
Consider the following statements (\(A\)) Linear momentum of a system of particles is zero (\(B\)) Kinetic energy of a system of particles is zero then
1 \(A\) does not imply \(B\) & \(B\) does not imply \(A\)
2 \(A\) implies \(B\) and \(B\) does not imply \(A\)
3 \(A\) does not imply \(B\) but \(B\) implies \(A\)
4 \(A\) implies \(B\) and \(B\) implies \(A\)
Explanation:
PHXI06:WORK ENERGY AND POWER
355215
When two spheres of equal masses undergo glancing elastic collision with one of them at rest, after collision they will move:
1 In the same direction
2 Opposite to one another
3 At right angle to each other
4 Together
Explanation:
In case of glancing collision of two equal masses with one of them at rest. After collision two masses move at right angle to each other.
PHXI06:WORK ENERGY AND POWER
355216
A ball is projected with initial velocity \(u\) at an angle \(\theta\) to the horizontal. Then horizontal displacement covered by ball as it collides third time to the ground be, if coefficient of restitution is \(e\) :
After each collision vertical velocity becomes e times whereas horizontal velocity remain same. So after each collision time of flight becomes e times of previous one. So that horizontal displacement \(=R+e R+e^{2} R\) \(=\left(1+e+e^{2}\right) \dfrac{u^{2} \sin 2 \theta}{g}\)
355213
A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when
1 \(M' = 2M\)
2 \(M' = M\)
3 \(M' > > M\)
4 \(M' < < M\)
Explanation:
If \(M=M^{\prime}\), then bullet will transfer whole of its velocity ( \(100 \%\) of its \(KE\)) to block and will itself come to rest.
PHXI06:WORK ENERGY AND POWER
355214
Consider the following statements (\(A\)) Linear momentum of a system of particles is zero (\(B\)) Kinetic energy of a system of particles is zero then
1 \(A\) does not imply \(B\) & \(B\) does not imply \(A\)
2 \(A\) implies \(B\) and \(B\) does not imply \(A\)
3 \(A\) does not imply \(B\) but \(B\) implies \(A\)
4 \(A\) implies \(B\) and \(B\) implies \(A\)
Explanation:
PHXI06:WORK ENERGY AND POWER
355215
When two spheres of equal masses undergo glancing elastic collision with one of them at rest, after collision they will move:
1 In the same direction
2 Opposite to one another
3 At right angle to each other
4 Together
Explanation:
In case of glancing collision of two equal masses with one of them at rest. After collision two masses move at right angle to each other.
PHXI06:WORK ENERGY AND POWER
355216
A ball is projected with initial velocity \(u\) at an angle \(\theta\) to the horizontal. Then horizontal displacement covered by ball as it collides third time to the ground be, if coefficient of restitution is \(e\) :
After each collision vertical velocity becomes e times whereas horizontal velocity remain same. So after each collision time of flight becomes e times of previous one. So that horizontal displacement \(=R+e R+e^{2} R\) \(=\left(1+e+e^{2}\right) \dfrac{u^{2} \sin 2 \theta}{g}\)
355213
A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when
1 \(M' = 2M\)
2 \(M' = M\)
3 \(M' > > M\)
4 \(M' < < M\)
Explanation:
If \(M=M^{\prime}\), then bullet will transfer whole of its velocity ( \(100 \%\) of its \(KE\)) to block and will itself come to rest.
PHXI06:WORK ENERGY AND POWER
355214
Consider the following statements (\(A\)) Linear momentum of a system of particles is zero (\(B\)) Kinetic energy of a system of particles is zero then
1 \(A\) does not imply \(B\) & \(B\) does not imply \(A\)
2 \(A\) implies \(B\) and \(B\) does not imply \(A\)
3 \(A\) does not imply \(B\) but \(B\) implies \(A\)
4 \(A\) implies \(B\) and \(B\) implies \(A\)
Explanation:
PHXI06:WORK ENERGY AND POWER
355215
When two spheres of equal masses undergo glancing elastic collision with one of them at rest, after collision they will move:
1 In the same direction
2 Opposite to one another
3 At right angle to each other
4 Together
Explanation:
In case of glancing collision of two equal masses with one of them at rest. After collision two masses move at right angle to each other.
PHXI06:WORK ENERGY AND POWER
355216
A ball is projected with initial velocity \(u\) at an angle \(\theta\) to the horizontal. Then horizontal displacement covered by ball as it collides third time to the ground be, if coefficient of restitution is \(e\) :
After each collision vertical velocity becomes e times whereas horizontal velocity remain same. So after each collision time of flight becomes e times of previous one. So that horizontal displacement \(=R+e R+e^{2} R\) \(=\left(1+e+e^{2}\right) \dfrac{u^{2} \sin 2 \theta}{g}\)
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PHXI06:WORK ENERGY AND POWER
355213
A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when
1 \(M' = 2M\)
2 \(M' = M\)
3 \(M' > > M\)
4 \(M' < < M\)
Explanation:
If \(M=M^{\prime}\), then bullet will transfer whole of its velocity ( \(100 \%\) of its \(KE\)) to block and will itself come to rest.
PHXI06:WORK ENERGY AND POWER
355214
Consider the following statements (\(A\)) Linear momentum of a system of particles is zero (\(B\)) Kinetic energy of a system of particles is zero then
1 \(A\) does not imply \(B\) & \(B\) does not imply \(A\)
2 \(A\) implies \(B\) and \(B\) does not imply \(A\)
3 \(A\) does not imply \(B\) but \(B\) implies \(A\)
4 \(A\) implies \(B\) and \(B\) implies \(A\)
Explanation:
PHXI06:WORK ENERGY AND POWER
355215
When two spheres of equal masses undergo glancing elastic collision with one of them at rest, after collision they will move:
1 In the same direction
2 Opposite to one another
3 At right angle to each other
4 Together
Explanation:
In case of glancing collision of two equal masses with one of them at rest. After collision two masses move at right angle to each other.
PHXI06:WORK ENERGY AND POWER
355216
A ball is projected with initial velocity \(u\) at an angle \(\theta\) to the horizontal. Then horizontal displacement covered by ball as it collides third time to the ground be, if coefficient of restitution is \(e\) :
After each collision vertical velocity becomes e times whereas horizontal velocity remain same. So after each collision time of flight becomes e times of previous one. So that horizontal displacement \(=R+e R+e^{2} R\) \(=\left(1+e+e^{2}\right) \dfrac{u^{2} \sin 2 \theta}{g}\)
