Collisions
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PHXI06:WORK ENERGY AND POWER

355243 Two particles of masses \({m_{1}}\) and \({m_{2}}\) move with initial velocities \({u_{1}}\) and \({u_{2}}\), respectively. On collision, one of the particles gets excited to a higher level, after absorbing energy \({\varepsilon}\). If the final velocities of particles are \({v_{1}}\) and \({v_{2}}\), then

1 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}-\varepsilon}\)
2 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}-\varepsilon=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}}\)
3 \({\dfrac{1}{2} m_{1}^{2} u_{1}^{2}+\dfrac{1}{2} m_{2}^{2} u_{2}^{2}+\varepsilon=\dfrac{1}{2} m_{1}^{2} v_{1}^{2}+\dfrac{1}{2} m_{2}^{2} v_{2}^{2}}\)
4 \({m_{1}^{2} u_{1}+m_{2}^{2} u_{2}-\varepsilon=m_{1}^{2} v_{1}+m_{2}^{2} v_{2}}\)
PHXI06:WORK ENERGY AND POWER

355244 If a body dropped from a certain height \(h\) hits the ground with a velocity \(\dfrac{\sqrt{2 g h}}{2}\) after second rebound, then coefficient of restitution between the body and ground is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{\sqrt{2}}\)
3 \(\dfrac{1}{4}\)
4 \(\dfrac{1}{2^{1 / 4}}\)
PHXI06:WORK ENERGY AND POWER

355245 A ball falls from a height of \(20\;m\) on the floor and rebounds to a height of \(5\;m.\) Time of contact is \(0.02 s\). Find the acceleration during impact

1 \(1200\;m{s^{ - 2}}\)
2 \(1000\;m{s^{ - 2}}\)
3 \(2000\;m{s^{ - 2}}\)
4 \(1500\;m{s^{ - 2}}\)
PHXI06:WORK ENERGY AND POWER

355246 On a frictionless surface a block of mass \(M\) moving at speed \(v\) collides elastically with another block of mass \(M\) which is initially at rest. After collision the first block moves at an angle 90 to the direction of second particle and has a speed \(\dfrac{v}{3}\). The second block's speed after the collision is

1 \(\dfrac{2 \sqrt{2}}{3} v\)
2 \(\dfrac{3}{\sqrt{2}} v\)
3 \(\dfrac{\sqrt{3}}{2} v\)
4 \(\dfrac{3}{4} v\)
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PHXI06:WORK ENERGY AND POWER

355243 Two particles of masses \({m_{1}}\) and \({m_{2}}\) move with initial velocities \({u_{1}}\) and \({u_{2}}\), respectively. On collision, one of the particles gets excited to a higher level, after absorbing energy \({\varepsilon}\). If the final velocities of particles are \({v_{1}}\) and \({v_{2}}\), then

1 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}-\varepsilon}\)
2 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}-\varepsilon=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}}\)
3 \({\dfrac{1}{2} m_{1}^{2} u_{1}^{2}+\dfrac{1}{2} m_{2}^{2} u_{2}^{2}+\varepsilon=\dfrac{1}{2} m_{1}^{2} v_{1}^{2}+\dfrac{1}{2} m_{2}^{2} v_{2}^{2}}\)
4 \({m_{1}^{2} u_{1}+m_{2}^{2} u_{2}-\varepsilon=m_{1}^{2} v_{1}+m_{2}^{2} v_{2}}\)
PHXI06:WORK ENERGY AND POWER

355244 If a body dropped from a certain height \(h\) hits the ground with a velocity \(\dfrac{\sqrt{2 g h}}{2}\) after second rebound, then coefficient of restitution between the body and ground is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{\sqrt{2}}\)
3 \(\dfrac{1}{4}\)
4 \(\dfrac{1}{2^{1 / 4}}\)
PHXI06:WORK ENERGY AND POWER

355245 A ball falls from a height of \(20\;m\) on the floor and rebounds to a height of \(5\;m.\) Time of contact is \(0.02 s\). Find the acceleration during impact

1 \(1200\;m{s^{ - 2}}\)
2 \(1000\;m{s^{ - 2}}\)
3 \(2000\;m{s^{ - 2}}\)
4 \(1500\;m{s^{ - 2}}\)
PHXI06:WORK ENERGY AND POWER

355246 On a frictionless surface a block of mass \(M\) moving at speed \(v\) collides elastically with another block of mass \(M\) which is initially at rest. After collision the first block moves at an angle 90 to the direction of second particle and has a speed \(\dfrac{v}{3}\). The second block's speed after the collision is

1 \(\dfrac{2 \sqrt{2}}{3} v\)
2 \(\dfrac{3}{\sqrt{2}} v\)
3 \(\dfrac{\sqrt{3}}{2} v\)
4 \(\dfrac{3}{4} v\)
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PHXI06:WORK ENERGY AND POWER

355243 Two particles of masses \({m_{1}}\) and \({m_{2}}\) move with initial velocities \({u_{1}}\) and \({u_{2}}\), respectively. On collision, one of the particles gets excited to a higher level, after absorbing energy \({\varepsilon}\). If the final velocities of particles are \({v_{1}}\) and \({v_{2}}\), then

1 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}-\varepsilon}\)
2 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}-\varepsilon=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}}\)
3 \({\dfrac{1}{2} m_{1}^{2} u_{1}^{2}+\dfrac{1}{2} m_{2}^{2} u_{2}^{2}+\varepsilon=\dfrac{1}{2} m_{1}^{2} v_{1}^{2}+\dfrac{1}{2} m_{2}^{2} v_{2}^{2}}\)
4 \({m_{1}^{2} u_{1}+m_{2}^{2} u_{2}-\varepsilon=m_{1}^{2} v_{1}+m_{2}^{2} v_{2}}\)
PHXI06:WORK ENERGY AND POWER

355244 If a body dropped from a certain height \(h\) hits the ground with a velocity \(\dfrac{\sqrt{2 g h}}{2}\) after second rebound, then coefficient of restitution between the body and ground is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{\sqrt{2}}\)
3 \(\dfrac{1}{4}\)
4 \(\dfrac{1}{2^{1 / 4}}\)
PHXI06:WORK ENERGY AND POWER

355245 A ball falls from a height of \(20\;m\) on the floor and rebounds to a height of \(5\;m.\) Time of contact is \(0.02 s\). Find the acceleration during impact

1 \(1200\;m{s^{ - 2}}\)
2 \(1000\;m{s^{ - 2}}\)
3 \(2000\;m{s^{ - 2}}\)
4 \(1500\;m{s^{ - 2}}\)
PHXI06:WORK ENERGY AND POWER

355246 On a frictionless surface a block of mass \(M\) moving at speed \(v\) collides elastically with another block of mass \(M\) which is initially at rest. After collision the first block moves at an angle 90 to the direction of second particle and has a speed \(\dfrac{v}{3}\). The second block's speed after the collision is

1 \(\dfrac{2 \sqrt{2}}{3} v\)
2 \(\dfrac{3}{\sqrt{2}} v\)
3 \(\dfrac{\sqrt{3}}{2} v\)
4 \(\dfrac{3}{4} v\)
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PHXI06:WORK ENERGY AND POWER

355243 Two particles of masses \({m_{1}}\) and \({m_{2}}\) move with initial velocities \({u_{1}}\) and \({u_{2}}\), respectively. On collision, one of the particles gets excited to a higher level, after absorbing energy \({\varepsilon}\). If the final velocities of particles are \({v_{1}}\) and \({v_{2}}\), then

1 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}-\varepsilon}\)
2 \({\dfrac{1}{2} m_{1} u_{1}^{2}+\dfrac{1}{2} m_{2} u_{2}^{2}-\varepsilon=\dfrac{1}{2} m_{1} v_{1}^{2}+\dfrac{1}{2} m_{2} v_{2}^{2}}\)
3 \({\dfrac{1}{2} m_{1}^{2} u_{1}^{2}+\dfrac{1}{2} m_{2}^{2} u_{2}^{2}+\varepsilon=\dfrac{1}{2} m_{1}^{2} v_{1}^{2}+\dfrac{1}{2} m_{2}^{2} v_{2}^{2}}\)
4 \({m_{1}^{2} u_{1}+m_{2}^{2} u_{2}-\varepsilon=m_{1}^{2} v_{1}+m_{2}^{2} v_{2}}\)
PHXI06:WORK ENERGY AND POWER

355244 If a body dropped from a certain height \(h\) hits the ground with a velocity \(\dfrac{\sqrt{2 g h}}{2}\) after second rebound, then coefficient of restitution between the body and ground is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{\sqrt{2}}\)
3 \(\dfrac{1}{4}\)
4 \(\dfrac{1}{2^{1 / 4}}\)
PHXI06:WORK ENERGY AND POWER

355245 A ball falls from a height of \(20\;m\) on the floor and rebounds to a height of \(5\;m.\) Time of contact is \(0.02 s\). Find the acceleration during impact

1 \(1200\;m{s^{ - 2}}\)
2 \(1000\;m{s^{ - 2}}\)
3 \(2000\;m{s^{ - 2}}\)
4 \(1500\;m{s^{ - 2}}\)
PHXI06:WORK ENERGY AND POWER

355246 On a frictionless surface a block of mass \(M\) moving at speed \(v\) collides elastically with another block of mass \(M\) which is initially at rest. After collision the first block moves at an angle 90 to the direction of second particle and has a speed \(\dfrac{v}{3}\). The second block's speed after the collision is

1 \(\dfrac{2 \sqrt{2}}{3} v\)
2 \(\dfrac{3}{\sqrt{2}} v\)
3 \(\dfrac{\sqrt{3}}{2} v\)
4 \(\dfrac{3}{4} v\)
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