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PHXI15:WAVES

355139 If you set up the ninth harmonic on a string fixed at a both ends, its frequency compared to the seventh harmonic

1 Equal

2 Higher

3 Lower

4 None of these

PHXI15:WAVES

355140 A standing wave $y = A \sin (\frac{20}{3} π x) \cos$ $(1000 π t)$ is maintained in a taut string where $x$ and $y$ are expressed in meters. The distance between the successive points oscillating with the amplitude $A / 2$ between two adjacent nodes is

1

10 c m

2

25 c m

3

25 c m

4

20 c m

Explanation:

From the given equation the amplitude is
$A_{R} = A \sin (\frac{20 π}{3} x) A_{R} = \frac{A}{2} = A \sin (\frac{20 π}{3} x)$
$\Rightarrow \sin (\frac{20 π}{3} x) = \frac{1}{2}$
$\frac{20 π}{3} x_{1} = \frac{π}{6} \Rightarrow x_{1} = \frac{1}{40} m = 2.5 c m$
$\frac{20 π}{3} x_{2} = \frac{π}{2} + \frac{π}{3} \Rightarrow x_{2} = 12.5 c m$
at $x = 0$ it is a node
The distance between points having amplitudes $\frac{A}{2} is 10 c m$

PHXI15:WAVES

355141 The fifth harmonic for vibrations of a stretched string is shown in figure. How many nodes are present here?
supporting img

1 6

2 4

3 10

4 5

PHXI15:WAVES

355142 The amplitude of vibration of any particle in a standing wave, produced along a stretched string depends on

1 Frequency of incident wave

2 Time period of selected wave

3 Location of particle

4 Time

PHXI15:WAVES

355139 If you set up the ninth harmonic on a string fixed at a both ends, its frequency compared to the seventh harmonic

1 Equal

2 Higher

3 Lower

4 None of these

PHXI15:WAVES

355140 A standing wave $y = A \sin (\frac{20}{3} π x) \cos$ $(1000 π t)$ is maintained in a taut string where $x$ and $y$ are expressed in meters. The distance between the successive points oscillating with the amplitude $A / 2$ between two adjacent nodes is

1

10 c m

2

25 c m

3

25 c m

4

20 c m

Explanation:

From the given equation the amplitude is
$A_{R} = A \sin (\frac{20 π}{3} x) A_{R} = \frac{A}{2} = A \sin (\frac{20 π}{3} x)$
$\Rightarrow \sin (\frac{20 π}{3} x) = \frac{1}{2}$
$\frac{20 π}{3} x_{1} = \frac{π}{6} \Rightarrow x_{1} = \frac{1}{40} m = 2.5 c m$
$\frac{20 π}{3} x_{2} = \frac{π}{2} + \frac{π}{3} \Rightarrow x_{2} = 12.5 c m$
at $x = 0$ it is a node
The distance between points having amplitudes $\frac{A}{2} is 10 c m$

PHXI15:WAVES

355141 The fifth harmonic for vibrations of a stretched string is shown in figure. How many nodes are present here?
supporting img

1 6

2 4

3 10

4 5

PHXI15:WAVES

355142 The amplitude of vibration of any particle in a standing wave, produced along a stretched string depends on

1 Frequency of incident wave

2 Time period of selected wave

3 Location of particle

4 Time

PHXI15:WAVES

355139 If you set up the ninth harmonic on a string fixed at a both ends, its frequency compared to the seventh harmonic

1 Equal

2 Higher

3 Lower

4 None of these

PHXI15:WAVES

355140 A standing wave $y = A \sin (\frac{20}{3} π x) \cos$ $(1000 π t)$ is maintained in a taut string where $x$ and $y$ are expressed in meters. The distance between the successive points oscillating with the amplitude $A / 2$ between two adjacent nodes is

1

10 c m

2

25 c m

3

25 c m

4

20 c m

Explanation:

From the given equation the amplitude is
$A_{R} = A \sin (\frac{20 π}{3} x) A_{R} = \frac{A}{2} = A \sin (\frac{20 π}{3} x)$
$\Rightarrow \sin (\frac{20 π}{3} x) = \frac{1}{2}$
$\frac{20 π}{3} x_{1} = \frac{π}{6} \Rightarrow x_{1} = \frac{1}{40} m = 2.5 c m$
$\frac{20 π}{3} x_{2} = \frac{π}{2} + \frac{π}{3} \Rightarrow x_{2} = 12.5 c m$
at $x = 0$ it is a node
The distance between points having amplitudes $\frac{A}{2} is 10 c m$

PHXI15:WAVES

355141 The fifth harmonic for vibrations of a stretched string is shown in figure. How many nodes are present here?
supporting img

1 6

2 4

3 10

4 5

PHXI15:WAVES

355142 The amplitude of vibration of any particle in a standing wave, produced along a stretched string depends on

1 Frequency of incident wave

2 Time period of selected wave

3 Location of particle

4 Time

PHXI15:WAVES

355139 If you set up the ninth harmonic on a string fixed at a both ends, its frequency compared to the seventh harmonic

1 Equal

2 Higher

3 Lower

4 None of these

PHXI15:WAVES

355140 A standing wave $y = A \sin (\frac{20}{3} π x) \cos$ $(1000 π t)$ is maintained in a taut string where $x$ and $y$ are expressed in meters. The distance between the successive points oscillating with the amplitude $A / 2$ between two adjacent nodes is

1

10 c m

2

25 c m

3

25 c m

4

20 c m

Explanation:

From the given equation the amplitude is
$A_{R} = A \sin (\frac{20 π}{3} x) A_{R} = \frac{A}{2} = A \sin (\frac{20 π}{3} x)$
$\Rightarrow \sin (\frac{20 π}{3} x) = \frac{1}{2}$
$\frac{20 π}{3} x_{1} = \frac{π}{6} \Rightarrow x_{1} = \frac{1}{40} m = 2.5 c m$
$\frac{20 π}{3} x_{2} = \frac{π}{2} + \frac{π}{3} \Rightarrow x_{2} = 12.5 c m$
at $x = 0$ it is a node
The distance between points having amplitudes $\frac{A}{2} is 10 c m$

PHXI15:WAVES

355141 The fifth harmonic for vibrations of a stretched string is shown in figure. How many nodes are present here?
supporting img

1 6

2 4

3 10

4 5

PHXI15:WAVES

355142 The amplitude of vibration of any particle in a standing wave, produced along a stretched string depends on

1 Frequency of incident wave

2 Time period of selected wave

3 Location of particle

4 Time