Superposition of Transverse Waves
PHXI15:WAVES

355113 Two wires are fixed on a sonometer wire. Their tensions are in the ratio \(8: 1\), the lengths in the ratio \(36: 35\), the diameters in the ratio \(4: 1\) and the densities in the ratio \(1: 2\). Find the frequency of the beats produced if the note of the higher pitch has frequency of 360 \(Hz\) .

1 \(15\,Hz\)
2 \(30\,Hz\)
3 \(10\,Hz\)
4 \(25\,Hz\)
PHXI15:WAVES

355114 Two wires \(W_{1}\) and \(W_{2}\) have the same radius \(r\) and respective densities \(\rho_{1}\) and \(\rho_{2}\) such that \(\rho_{2}=4 \rho_{1}\). They are joined together at the point \(O\), as shown in the figure. The combination is used as a sonometer wire and kept under tension \(T\). The point \(O\) is midway between the bridges. When a stationary waves is set up in the composite wire, the joint is formed to be a node. The ratio of the number of antinodes formed in \(W_{1}\) to \(W_{2}\) is :
supporting img

1 \(1: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(4: 1\)
PHXI15:WAVES

355115 Two parts of sonometer wirehaving length \(1\;m\), divided by a movable kinfe-edge, differ in length by \(2\;cm\) and produce 1 beat/s when sounded together. Assume that each part is oscillating in fundamental mode, find fundmental frequency of each part.

1 \(25.5\;Hz,24.5\;Hz\)
2 \(18\;Hz,19\;Hz\)
3 \(32.5\;Hz,31.5\;Hz\)
4 \(45.5\;Hz,44.5\;Hz\)
PHXI15:WAVES

355116 When the length of the vibrating segment of a sonometer wire is increased by \(1 \%\), the percentage change in its frequency is

1 \(\dfrac{100}{101}\)
2 \(\dfrac{99}{100}\)
3 \(1\)
4 \(2\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI15:WAVES

355113 Two wires are fixed on a sonometer wire. Their tensions are in the ratio \(8: 1\), the lengths in the ratio \(36: 35\), the diameters in the ratio \(4: 1\) and the densities in the ratio \(1: 2\). Find the frequency of the beats produced if the note of the higher pitch has frequency of 360 \(Hz\) .

1 \(15\,Hz\)
2 \(30\,Hz\)
3 \(10\,Hz\)
4 \(25\,Hz\)
PHXI15:WAVES

355114 Two wires \(W_{1}\) and \(W_{2}\) have the same radius \(r\) and respective densities \(\rho_{1}\) and \(\rho_{2}\) such that \(\rho_{2}=4 \rho_{1}\). They are joined together at the point \(O\), as shown in the figure. The combination is used as a sonometer wire and kept under tension \(T\). The point \(O\) is midway between the bridges. When a stationary waves is set up in the composite wire, the joint is formed to be a node. The ratio of the number of antinodes formed in \(W_{1}\) to \(W_{2}\) is :
supporting img

1 \(1: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(4: 1\)
PHXI15:WAVES

355115 Two parts of sonometer wirehaving length \(1\;m\), divided by a movable kinfe-edge, differ in length by \(2\;cm\) and produce 1 beat/s when sounded together. Assume that each part is oscillating in fundamental mode, find fundmental frequency of each part.

1 \(25.5\;Hz,24.5\;Hz\)
2 \(18\;Hz,19\;Hz\)
3 \(32.5\;Hz,31.5\;Hz\)
4 \(45.5\;Hz,44.5\;Hz\)
PHXI15:WAVES

355116 When the length of the vibrating segment of a sonometer wire is increased by \(1 \%\), the percentage change in its frequency is

1 \(\dfrac{100}{101}\)
2 \(\dfrac{99}{100}\)
3 \(1\)
4 \(2\)
PHXI15:WAVES

355113 Two wires are fixed on a sonometer wire. Their tensions are in the ratio \(8: 1\), the lengths in the ratio \(36: 35\), the diameters in the ratio \(4: 1\) and the densities in the ratio \(1: 2\). Find the frequency of the beats produced if the note of the higher pitch has frequency of 360 \(Hz\) .

1 \(15\,Hz\)
2 \(30\,Hz\)
3 \(10\,Hz\)
4 \(25\,Hz\)
PHXI15:WAVES

355114 Two wires \(W_{1}\) and \(W_{2}\) have the same radius \(r\) and respective densities \(\rho_{1}\) and \(\rho_{2}\) such that \(\rho_{2}=4 \rho_{1}\). They are joined together at the point \(O\), as shown in the figure. The combination is used as a sonometer wire and kept under tension \(T\). The point \(O\) is midway between the bridges. When a stationary waves is set up in the composite wire, the joint is formed to be a node. The ratio of the number of antinodes formed in \(W_{1}\) to \(W_{2}\) is :
supporting img

1 \(1: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(4: 1\)
PHXI15:WAVES

355115 Two parts of sonometer wirehaving length \(1\;m\), divided by a movable kinfe-edge, differ in length by \(2\;cm\) and produce 1 beat/s when sounded together. Assume that each part is oscillating in fundamental mode, find fundmental frequency of each part.

1 \(25.5\;Hz,24.5\;Hz\)
2 \(18\;Hz,19\;Hz\)
3 \(32.5\;Hz,31.5\;Hz\)
4 \(45.5\;Hz,44.5\;Hz\)
PHXI15:WAVES

355116 When the length of the vibrating segment of a sonometer wire is increased by \(1 \%\), the percentage change in its frequency is

1 \(\dfrac{100}{101}\)
2 \(\dfrac{99}{100}\)
3 \(1\)
4 \(2\)
PHXI15:WAVES

355113 Two wires are fixed on a sonometer wire. Their tensions are in the ratio \(8: 1\), the lengths in the ratio \(36: 35\), the diameters in the ratio \(4: 1\) and the densities in the ratio \(1: 2\). Find the frequency of the beats produced if the note of the higher pitch has frequency of 360 \(Hz\) .

1 \(15\,Hz\)
2 \(30\,Hz\)
3 \(10\,Hz\)
4 \(25\,Hz\)
PHXI15:WAVES

355114 Two wires \(W_{1}\) and \(W_{2}\) have the same radius \(r\) and respective densities \(\rho_{1}\) and \(\rho_{2}\) such that \(\rho_{2}=4 \rho_{1}\). They are joined together at the point \(O\), as shown in the figure. The combination is used as a sonometer wire and kept under tension \(T\). The point \(O\) is midway between the bridges. When a stationary waves is set up in the composite wire, the joint is formed to be a node. The ratio of the number of antinodes formed in \(W_{1}\) to \(W_{2}\) is :
supporting img

1 \(1: 1\)
2 \(1: 2\)
3 \(1: 3\)
4 \(4: 1\)
PHXI15:WAVES

355115 Two parts of sonometer wirehaving length \(1\;m\), divided by a movable kinfe-edge, differ in length by \(2\;cm\) and produce 1 beat/s when sounded together. Assume that each part is oscillating in fundamental mode, find fundmental frequency of each part.

1 \(25.5\;Hz,24.5\;Hz\)
2 \(18\;Hz,19\;Hz\)
3 \(32.5\;Hz,31.5\;Hz\)
4 \(45.5\;Hz,44.5\;Hz\)
PHXI15:WAVES

355116 When the length of the vibrating segment of a sonometer wire is increased by \(1 \%\), the percentage change in its frequency is

1 \(\dfrac{100}{101}\)
2 \(\dfrac{99}{100}\)
3 \(1\)
4 \(2\)