NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXI08:GRAVITATION
360048
Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will
1 Move towards each other.
2 Move away from each other.
3 Will become stationary
4 Keep floating at same distance between them.
Explanation:
Astronauts move towards each other due to mutual gravitational force of attraction.
NEET - 2017
PHXI08:GRAVITATION
360049
Masses \(2 m, m, m\) are kept at the vertices of an equilateral triangle of side \(l\), as shown in figure. Another mass \(2 m\) is kept at their centroid. The force on the \(2 m\) at the centroid due to other is \((A G=G B=G C=1 \mathrm{~m})\)
360050
A research satellite of mass \(200\;kg\) circle the Earth in an orbit of average radius \(\dfrac{3 R}{2}\). Assuming the gravitational pull of mass of \(1\;kg\) on earth's surface to be \(10\;N\), the pull on the satellite will be:
360051
Three identical point massess, each of mass 1\(kg\) lie in the \(x-y\) plane at points \((0,0),(0,0.2\;m)\) and \((0.2\;m,0)\). The net gravitational force on the mass at the origin is
1 \(1.67 \times 10^{-9}(\hat{i}-\hat{j}) N\)
2 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
3 \(1.67 \times 10^{-9}(\hat{i}+\hat{j}) N\)
4 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
Explanation:
Let particle \(A\) lies at origin, particle \(B\) and \(C\) on \(y\) and \(x\)-axis respectively \({\overrightarrow F _{AC}} = \frac{{G{m_A}{m_C}}}{{r_{AC}^2}}\hat i\) \( = \frac{{6.67 \times {{10}^{ - 11}} \times 1 \times 1}}{{{{(0.2)}^2}}}\hat i = 1.67 \times {10^{ - 9}}N\hat i\) Similarly \({{\vec F}_{AB}} = 1.67 \times {10^{ - 9}}Nj\) \(\therefore\) Net force on particle \(A\) \(\vec{F}=\vec{F}_{A C}+\vec{F}_{A B}=1.67 \times 10^{-9} N(\hat{i}+\hat{j})\)
360048
Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will
1 Move towards each other.
2 Move away from each other.
3 Will become stationary
4 Keep floating at same distance between them.
Explanation:
Astronauts move towards each other due to mutual gravitational force of attraction.
NEET - 2017
PHXI08:GRAVITATION
360049
Masses \(2 m, m, m\) are kept at the vertices of an equilateral triangle of side \(l\), as shown in figure. Another mass \(2 m\) is kept at their centroid. The force on the \(2 m\) at the centroid due to other is \((A G=G B=G C=1 \mathrm{~m})\)
360050
A research satellite of mass \(200\;kg\) circle the Earth in an orbit of average radius \(\dfrac{3 R}{2}\). Assuming the gravitational pull of mass of \(1\;kg\) on earth's surface to be \(10\;N\), the pull on the satellite will be:
360051
Three identical point massess, each of mass 1\(kg\) lie in the \(x-y\) plane at points \((0,0),(0,0.2\;m)\) and \((0.2\;m,0)\). The net gravitational force on the mass at the origin is
1 \(1.67 \times 10^{-9}(\hat{i}-\hat{j}) N\)
2 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
3 \(1.67 \times 10^{-9}(\hat{i}+\hat{j}) N\)
4 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
Explanation:
Let particle \(A\) lies at origin, particle \(B\) and \(C\) on \(y\) and \(x\)-axis respectively \({\overrightarrow F _{AC}} = \frac{{G{m_A}{m_C}}}{{r_{AC}^2}}\hat i\) \( = \frac{{6.67 \times {{10}^{ - 11}} \times 1 \times 1}}{{{{(0.2)}^2}}}\hat i = 1.67 \times {10^{ - 9}}N\hat i\) Similarly \({{\vec F}_{AB}} = 1.67 \times {10^{ - 9}}Nj\) \(\therefore\) Net force on particle \(A\) \(\vec{F}=\vec{F}_{A C}+\vec{F}_{A B}=1.67 \times 10^{-9} N(\hat{i}+\hat{j})\)
360048
Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will
1 Move towards each other.
2 Move away from each other.
3 Will become stationary
4 Keep floating at same distance between them.
Explanation:
Astronauts move towards each other due to mutual gravitational force of attraction.
NEET - 2017
PHXI08:GRAVITATION
360049
Masses \(2 m, m, m\) are kept at the vertices of an equilateral triangle of side \(l\), as shown in figure. Another mass \(2 m\) is kept at their centroid. The force on the \(2 m\) at the centroid due to other is \((A G=G B=G C=1 \mathrm{~m})\)
360050
A research satellite of mass \(200\;kg\) circle the Earth in an orbit of average radius \(\dfrac{3 R}{2}\). Assuming the gravitational pull of mass of \(1\;kg\) on earth's surface to be \(10\;N\), the pull on the satellite will be:
360051
Three identical point massess, each of mass 1\(kg\) lie in the \(x-y\) plane at points \((0,0),(0,0.2\;m)\) and \((0.2\;m,0)\). The net gravitational force on the mass at the origin is
1 \(1.67 \times 10^{-9}(\hat{i}-\hat{j}) N\)
2 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
3 \(1.67 \times 10^{-9}(\hat{i}+\hat{j}) N\)
4 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
Explanation:
Let particle \(A\) lies at origin, particle \(B\) and \(C\) on \(y\) and \(x\)-axis respectively \({\overrightarrow F _{AC}} = \frac{{G{m_A}{m_C}}}{{r_{AC}^2}}\hat i\) \( = \frac{{6.67 \times {{10}^{ - 11}} \times 1 \times 1}}{{{{(0.2)}^2}}}\hat i = 1.67 \times {10^{ - 9}}N\hat i\) Similarly \({{\vec F}_{AB}} = 1.67 \times {10^{ - 9}}Nj\) \(\therefore\) Net force on particle \(A\) \(\vec{F}=\vec{F}_{A C}+\vec{F}_{A B}=1.67 \times 10^{-9} N(\hat{i}+\hat{j})\)
360048
Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will
1 Move towards each other.
2 Move away from each other.
3 Will become stationary
4 Keep floating at same distance between them.
Explanation:
Astronauts move towards each other due to mutual gravitational force of attraction.
NEET - 2017
PHXI08:GRAVITATION
360049
Masses \(2 m, m, m\) are kept at the vertices of an equilateral triangle of side \(l\), as shown in figure. Another mass \(2 m\) is kept at their centroid. The force on the \(2 m\) at the centroid due to other is \((A G=G B=G C=1 \mathrm{~m})\)
360050
A research satellite of mass \(200\;kg\) circle the Earth in an orbit of average radius \(\dfrac{3 R}{2}\). Assuming the gravitational pull of mass of \(1\;kg\) on earth's surface to be \(10\;N\), the pull on the satellite will be:
360051
Three identical point massess, each of mass 1\(kg\) lie in the \(x-y\) plane at points \((0,0),(0,0.2\;m)\) and \((0.2\;m,0)\). The net gravitational force on the mass at the origin is
1 \(1.67 \times 10^{-9}(\hat{i}-\hat{j}) N\)
2 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
3 \(1.67 \times 10^{-9}(\hat{i}+\hat{j}) N\)
4 \(3.34 \times 10^{-10}(\hat{i}+\hat{j}) N\)
Explanation:
Let particle \(A\) lies at origin, particle \(B\) and \(C\) on \(y\) and \(x\)-axis respectively \({\overrightarrow F _{AC}} = \frac{{G{m_A}{m_C}}}{{r_{AC}^2}}\hat i\) \( = \frac{{6.67 \times {{10}^{ - 11}} \times 1 \times 1}}{{{{(0.2)}^2}}}\hat i = 1.67 \times {10^{ - 9}}N\hat i\) Similarly \({{\vec F}_{AB}} = 1.67 \times {10^{ - 9}}Nj\) \(\therefore\) Net force on particle \(A\) \(\vec{F}=\vec{F}_{A C}+\vec{F}_{A B}=1.67 \times 10^{-9} N(\hat{i}+\hat{j})\)
