Kepler’s Laws
« Previous Topic: Gravitational Potential Next Topic: Miscellaneous Problems on Gravitation »
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI08:GRAVITATION

359967 A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution?

1 50
2 25
3 100
4 20
JEE - 2024
PHXI08:GRAVITATION

359968 The earth revolves around the sun in one year. If the distance between them becomes double, then the new time period of revolution will be

1 \(4\sqrt 2 \,yr\)
2 \(2\sqrt 2 \,yr\)
3 \(4\,yr\)
4 \(8\,yr\)
PHXI08:GRAVITATION

359969 The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become:

1 10 hours
2 80 hours
3 40 hours
4 20 hours
PHXI08:GRAVITATION

359970 If a graph is plotted between \(T^{2}\) and \(r^{3}\) for a planet, then its slope will be (where \(M_{s}\) is the mass of the sun)

1 \(\dfrac{G M_{s}}{4 \pi}\)
2 \(\dfrac{4 \pi^{2}}{G M_{s}}\)
3 \(G{M_s}\)
4 \(4 \pi G M_{s}\)
NEET DIGITAL LIBRARY
PHXI08:GRAVITATION

359967 A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution?

1 50
2 25
3 100
4 20
JEE - 2024
PHXI08:GRAVITATION

359968 The earth revolves around the sun in one year. If the distance between them becomes double, then the new time period of revolution will be

1 \(4\sqrt 2 \,yr\)
2 \(2\sqrt 2 \,yr\)
3 \(4\,yr\)
4 \(8\,yr\)
PHXI08:GRAVITATION

359969 The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become:

1 10 hours
2 80 hours
3 40 hours
4 20 hours
PHXI08:GRAVITATION

359970 If a graph is plotted between \(T^{2}\) and \(r^{3}\) for a planet, then its slope will be (where \(M_{s}\) is the mass of the sun)

1 \(\dfrac{G M_{s}}{4 \pi}\)
2 \(\dfrac{4 \pi^{2}}{G M_{s}}\)
3 \(G{M_s}\)
4 \(4 \pi G M_{s}\)
Join With Us for More Updates
PHXI08:GRAVITATION

359967 A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution?

1 50
2 25
3 100
4 20
JEE - 2024
PHXI08:GRAVITATION

359968 The earth revolves around the sun in one year. If the distance between them becomes double, then the new time period of revolution will be

1 \(4\sqrt 2 \,yr\)
2 \(2\sqrt 2 \,yr\)
3 \(4\,yr\)
4 \(8\,yr\)
PHXI08:GRAVITATION

359969 The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become:

1 10 hours
2 80 hours
3 40 hours
4 20 hours
PHXI08:GRAVITATION

359970 If a graph is plotted between \(T^{2}\) and \(r^{3}\) for a planet, then its slope will be (where \(M_{s}\) is the mass of the sun)

1 \(\dfrac{G M_{s}}{4 \pi}\)
2 \(\dfrac{4 \pi^{2}}{G M_{s}}\)
3 \(G{M_s}\)
4 \(4 \pi G M_{s}\)
For More Updates join with Us
PHXI08:GRAVITATION

359967 A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution?

1 50
2 25
3 100
4 20
JEE - 2024
PHXI08:GRAVITATION

359968 The earth revolves around the sun in one year. If the distance between them becomes double, then the new time period of revolution will be

1 \(4\sqrt 2 \,yr\)
2 \(2\sqrt 2 \,yr\)
3 \(4\,yr\)
4 \(8\,yr\)
PHXI08:GRAVITATION

359969 The time period of a satellite of earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become:

1 10 hours
2 80 hours
3 40 hours
4 20 hours
PHXI08:GRAVITATION

359970 If a graph is plotted between \(T^{2}\) and \(r^{3}\) for a planet, then its slope will be (where \(M_{s}\) is the mass of the sun)

1 \(\dfrac{G M_{s}}{4 \pi}\)
2 \(\dfrac{4 \pi^{2}}{G M_{s}}\)
3 \(G{M_s}\)
4 \(4 \pi G M_{s}\)
NEET DIGITAL LIBRARY