Earth Satellites
PHXI08:GRAVITATION

359787 The time period of a satellite, revolving above earth's surface at a height equal to \(R\) will be (Given \(g = {\pi ^2}\;m/{s^2},R = \) radius of earth)

1 \(\sqrt{2 R}\)
2 \(\sqrt{4 R}\)
3 \(\sqrt{32 R}\)
4 \(\sqrt{8 R}\)
PHXI08:GRAVITATION

359788 The satellite of mass \(m\) revolving in a circular orbit of radius \(r\) around the earth has kinetic energy \(E\). Then its angular momentum will be

1 \(\sqrt{2 E m r}\)
2 \(\sqrt{2 E m r^{2}}\)
3 \(\dfrac{E}{2 m r^{2}}\)
4 \(\sqrt{\dfrac{E}{2 m r^{2}}}\)
PHXI08:GRAVITATION

359789 Two planets \(X\) and \(Y\) travel counter clockwise in circular orbits around a star as show in the figure below. The radii of their orbits are in the ratio \(3 \sqrt{9}: 1\). At some time, they are aligned as in fig. (\(A\)) making a straight line with the star. After five Earth years the angular displacement of planet \(X\) is \(90^{\circ}\), as in fig \(B\). What is the angular displacement of planet \(Y\) at this time?
supporting img

1 \(180^{\circ}\)
2 \(270^{\circ}\)
3 \(90^{\circ}\)
4 \(360^{\circ}\)
PHXI08:GRAVITATION

359790 An artificial satellite revolves around earth in circular orbit of radius \(r\) with time period \(T\). The satellite is made to stop in the orbit which makes it fall onto earth. Time of fall of the satellite on the earth is

1 \(\dfrac{T}{4}\)
2 \(\dfrac{T}{2}\)
3 \(\dfrac{T}{\sqrt{2}}\)
4 \(\dfrac{T}{4 \sqrt{2}}\)
PHXI08:GRAVITATION

359791 Two satellites \(A\) and \(B\) go round a planet is circular orbits having radii 4\(R\) and \(R\), respectively. If the speed of satellite \(A\) is \(3 v\), then speed of satellite \(B\) is

1 \(6 v\)
2 \(\dfrac{4 v}{2}\)
3 \(12 v\)
4 \(\dfrac{3 v}{2}\)
PHXI08:GRAVITATION

359787 The time period of a satellite, revolving above earth's surface at a height equal to \(R\) will be (Given \(g = {\pi ^2}\;m/{s^2},R = \) radius of earth)

1 \(\sqrt{2 R}\)
2 \(\sqrt{4 R}\)
3 \(\sqrt{32 R}\)
4 \(\sqrt{8 R}\)
PHXI08:GRAVITATION

359788 The satellite of mass \(m\) revolving in a circular orbit of radius \(r\) around the earth has kinetic energy \(E\). Then its angular momentum will be

1 \(\sqrt{2 E m r}\)
2 \(\sqrt{2 E m r^{2}}\)
3 \(\dfrac{E}{2 m r^{2}}\)
4 \(\sqrt{\dfrac{E}{2 m r^{2}}}\)
PHXI08:GRAVITATION

359789 Two planets \(X\) and \(Y\) travel counter clockwise in circular orbits around a star as show in the figure below. The radii of their orbits are in the ratio \(3 \sqrt{9}: 1\). At some time, they are aligned as in fig. (\(A\)) making a straight line with the star. After five Earth years the angular displacement of planet \(X\) is \(90^{\circ}\), as in fig \(B\). What is the angular displacement of planet \(Y\) at this time?
supporting img

1 \(180^{\circ}\)
2 \(270^{\circ}\)
3 \(90^{\circ}\)
4 \(360^{\circ}\)
PHXI08:GRAVITATION

359790 An artificial satellite revolves around earth in circular orbit of radius \(r\) with time period \(T\). The satellite is made to stop in the orbit which makes it fall onto earth. Time of fall of the satellite on the earth is

1 \(\dfrac{T}{4}\)
2 \(\dfrac{T}{2}\)
3 \(\dfrac{T}{\sqrt{2}}\)
4 \(\dfrac{T}{4 \sqrt{2}}\)
PHXI08:GRAVITATION

359791 Two satellites \(A\) and \(B\) go round a planet is circular orbits having radii 4\(R\) and \(R\), respectively. If the speed of satellite \(A\) is \(3 v\), then speed of satellite \(B\) is

1 \(6 v\)
2 \(\dfrac{4 v}{2}\)
3 \(12 v\)
4 \(\dfrac{3 v}{2}\)
PHXI08:GRAVITATION

359787 The time period of a satellite, revolving above earth's surface at a height equal to \(R\) will be (Given \(g = {\pi ^2}\;m/{s^2},R = \) radius of earth)

1 \(\sqrt{2 R}\)
2 \(\sqrt{4 R}\)
3 \(\sqrt{32 R}\)
4 \(\sqrt{8 R}\)
PHXI08:GRAVITATION

359788 The satellite of mass \(m\) revolving in a circular orbit of radius \(r\) around the earth has kinetic energy \(E\). Then its angular momentum will be

1 \(\sqrt{2 E m r}\)
2 \(\sqrt{2 E m r^{2}}\)
3 \(\dfrac{E}{2 m r^{2}}\)
4 \(\sqrt{\dfrac{E}{2 m r^{2}}}\)
PHXI08:GRAVITATION

359789 Two planets \(X\) and \(Y\) travel counter clockwise in circular orbits around a star as show in the figure below. The radii of their orbits are in the ratio \(3 \sqrt{9}: 1\). At some time, they are aligned as in fig. (\(A\)) making a straight line with the star. After five Earth years the angular displacement of planet \(X\) is \(90^{\circ}\), as in fig \(B\). What is the angular displacement of planet \(Y\) at this time?
supporting img

1 \(180^{\circ}\)
2 \(270^{\circ}\)
3 \(90^{\circ}\)
4 \(360^{\circ}\)
PHXI08:GRAVITATION

359790 An artificial satellite revolves around earth in circular orbit of radius \(r\) with time period \(T\). The satellite is made to stop in the orbit which makes it fall onto earth. Time of fall of the satellite on the earth is

1 \(\dfrac{T}{4}\)
2 \(\dfrac{T}{2}\)
3 \(\dfrac{T}{\sqrt{2}}\)
4 \(\dfrac{T}{4 \sqrt{2}}\)
PHXI08:GRAVITATION

359791 Two satellites \(A\) and \(B\) go round a planet is circular orbits having radii 4\(R\) and \(R\), respectively. If the speed of satellite \(A\) is \(3 v\), then speed of satellite \(B\) is

1 \(6 v\)
2 \(\dfrac{4 v}{2}\)
3 \(12 v\)
4 \(\dfrac{3 v}{2}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI08:GRAVITATION

359787 The time period of a satellite, revolving above earth's surface at a height equal to \(R\) will be (Given \(g = {\pi ^2}\;m/{s^2},R = \) radius of earth)

1 \(\sqrt{2 R}\)
2 \(\sqrt{4 R}\)
3 \(\sqrt{32 R}\)
4 \(\sqrt{8 R}\)
PHXI08:GRAVITATION

359788 The satellite of mass \(m\) revolving in a circular orbit of radius \(r\) around the earth has kinetic energy \(E\). Then its angular momentum will be

1 \(\sqrt{2 E m r}\)
2 \(\sqrt{2 E m r^{2}}\)
3 \(\dfrac{E}{2 m r^{2}}\)
4 \(\sqrt{\dfrac{E}{2 m r^{2}}}\)
PHXI08:GRAVITATION

359789 Two planets \(X\) and \(Y\) travel counter clockwise in circular orbits around a star as show in the figure below. The radii of their orbits are in the ratio \(3 \sqrt{9}: 1\). At some time, they are aligned as in fig. (\(A\)) making a straight line with the star. After five Earth years the angular displacement of planet \(X\) is \(90^{\circ}\), as in fig \(B\). What is the angular displacement of planet \(Y\) at this time?
supporting img

1 \(180^{\circ}\)
2 \(270^{\circ}\)
3 \(90^{\circ}\)
4 \(360^{\circ}\)
PHXI08:GRAVITATION

359790 An artificial satellite revolves around earth in circular orbit of radius \(r\) with time period \(T\). The satellite is made to stop in the orbit which makes it fall onto earth. Time of fall of the satellite on the earth is

1 \(\dfrac{T}{4}\)
2 \(\dfrac{T}{2}\)
3 \(\dfrac{T}{\sqrt{2}}\)
4 \(\dfrac{T}{4 \sqrt{2}}\)
PHXI08:GRAVITATION

359791 Two satellites \(A\) and \(B\) go round a planet is circular orbits having radii 4\(R\) and \(R\), respectively. If the speed of satellite \(A\) is \(3 v\), then speed of satellite \(B\) is

1 \(6 v\)
2 \(\dfrac{4 v}{2}\)
3 \(12 v\)
4 \(\dfrac{3 v}{2}\)
PHXI08:GRAVITATION

359787 The time period of a satellite, revolving above earth's surface at a height equal to \(R\) will be (Given \(g = {\pi ^2}\;m/{s^2},R = \) radius of earth)

1 \(\sqrt{2 R}\)
2 \(\sqrt{4 R}\)
3 \(\sqrt{32 R}\)
4 \(\sqrt{8 R}\)
PHXI08:GRAVITATION

359788 The satellite of mass \(m\) revolving in a circular orbit of radius \(r\) around the earth has kinetic energy \(E\). Then its angular momentum will be

1 \(\sqrt{2 E m r}\)
2 \(\sqrt{2 E m r^{2}}\)
3 \(\dfrac{E}{2 m r^{2}}\)
4 \(\sqrt{\dfrac{E}{2 m r^{2}}}\)
PHXI08:GRAVITATION

359789 Two planets \(X\) and \(Y\) travel counter clockwise in circular orbits around a star as show in the figure below. The radii of their orbits are in the ratio \(3 \sqrt{9}: 1\). At some time, they are aligned as in fig. (\(A\)) making a straight line with the star. After five Earth years the angular displacement of planet \(X\) is \(90^{\circ}\), as in fig \(B\). What is the angular displacement of planet \(Y\) at this time?
supporting img

1 \(180^{\circ}\)
2 \(270^{\circ}\)
3 \(90^{\circ}\)
4 \(360^{\circ}\)
PHXI08:GRAVITATION

359790 An artificial satellite revolves around earth in circular orbit of radius \(r\) with time period \(T\). The satellite is made to stop in the orbit which makes it fall onto earth. Time of fall of the satellite on the earth is

1 \(\dfrac{T}{4}\)
2 \(\dfrac{T}{2}\)
3 \(\dfrac{T}{\sqrt{2}}\)
4 \(\dfrac{T}{4 \sqrt{2}}\)
PHXI08:GRAVITATION

359791 Two satellites \(A\) and \(B\) go round a planet is circular orbits having radii 4\(R\) and \(R\), respectively. If the speed of satellite \(A\) is \(3 v\), then speed of satellite \(B\) is

1 \(6 v\)
2 \(\dfrac{4 v}{2}\)
3 \(12 v\)
4 \(\dfrac{3 v}{2}\)