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PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359332 A short electric dipole has a dipole moment of $16 \times 10^{- 9} c m$ . The electric potential due to the dipole at a point at a distance of 0.6 $m$ form the center of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : $(\frac{1}{4 π ε_{0} = 9} \times 10^{9} N m^{2} / C^{2})$

1

200 V

2

400 V

3

Z e r o

4

50 V

Explanation:

$V = \frac{k P \cos θ}{r^{2}} = \frac{9 \times 10^{9} \times 16 \times 10^{- 9}}{{(0.6)}^{2}} \times \frac{1}{2}$
$= 200 V$

NEET - 2020

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359333 Two dipoles each having dipole moment $P$ are placed as shown in the figure. Find the point at which the potential is minimum.
supporting img

1

A

2

B

3

C

4

D

Explanation:

The resultant dipole is shown in the figure.
The point which is closest to the tail of the resultant dipole has minimum potential. The point $C$ has the lowest potential
supporting img

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359334 An electric dipole of moment $\vec{p}$ is placed in a uniform electric field $\vec{E}$ . Then
(i) the torque on the dipole is $\vec{p} \times \vec{E}$ .
(ii) the potential energy of the system is $- \vec{p} \cdot \vec{E}$
(iii) the resultant force on the dipole is zero

1 (i), (ii) and (iii) are correct.

2 (i) and (iii) are correct and (ii) is wrong

3 only (i) is correct

4 (i) and (ii) are correct and (iii) is wrong.

Explanation:

In a uniform electric field $\vec{E}$ , dipole experiences a torque $\vec{τ}$ given by $\vec{τ} = \vec{p} \times \vec{E}$ but experiances no force.
The potential energy of the dipole in a uniform electric field $\vec{E}$ is $U = - \vec{p} \cdot \vec{E}$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359335 The ratio of electric potential due to an electric dipole on the axial position to that on the equitorial on position for the same distance from it, is

1

\infty

2

2

3

1

4

Z e r o

Explanation:

For a dipole, $V_{a x i a l p o s i t i o n} = \frac{K p}{x^{2}}$
$V_{e q u i t o r i a l p o s i t i o n} = 0$
Their ratio $= \infty$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359332 A short electric dipole has a dipole moment of $16 \times 10^{- 9} c m$ . The electric potential due to the dipole at a point at a distance of 0.6 $m$ form the center of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : $(\frac{1}{4 π ε_{0} = 9} \times 10^{9} N m^{2} / C^{2})$

1

200 V

2

400 V

3

Z e r o

4

50 V

Explanation:

$V = \frac{k P \cos θ}{r^{2}} = \frac{9 \times 10^{9} \times 16 \times 10^{- 9}}{{(0.6)}^{2}} \times \frac{1}{2}$
$= 200 V$

NEET - 2020

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359333 Two dipoles each having dipole moment $P$ are placed as shown in the figure. Find the point at which the potential is minimum.
supporting img

1

A

2

B

3

C

4

D

Explanation:

The resultant dipole is shown in the figure.
The point which is closest to the tail of the resultant dipole has minimum potential. The point $C$ has the lowest potential
supporting img

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359334 An electric dipole of moment $\vec{p}$ is placed in a uniform electric field $\vec{E}$ . Then
(i) the torque on the dipole is $\vec{p} \times \vec{E}$ .
(ii) the potential energy of the system is $- \vec{p} \cdot \vec{E}$
(iii) the resultant force on the dipole is zero

1 (i), (ii) and (iii) are correct.

2 (i) and (iii) are correct and (ii) is wrong

3 only (i) is correct

4 (i) and (ii) are correct and (iii) is wrong.

Explanation:

In a uniform electric field $\vec{E}$ , dipole experiences a torque $\vec{τ}$ given by $\vec{τ} = \vec{p} \times \vec{E}$ but experiances no force.
The potential energy of the dipole in a uniform electric field $\vec{E}$ is $U = - \vec{p} \cdot \vec{E}$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359335 The ratio of electric potential due to an electric dipole on the axial position to that on the equitorial on position for the same distance from it, is

1

\infty

2

2

3

1

4

Z e r o

Explanation:

For a dipole, $V_{a x i a l p o s i t i o n} = \frac{K p}{x^{2}}$
$V_{e q u i t o r i a l p o s i t i o n} = 0$
Their ratio $= \infty$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359332 A short electric dipole has a dipole moment of $16 \times 10^{- 9} c m$ . The electric potential due to the dipole at a point at a distance of 0.6 $m$ form the center of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : $(\frac{1}{4 π ε_{0} = 9} \times 10^{9} N m^{2} / C^{2})$

1

200 V

2

400 V

3

Z e r o

4

50 V

Explanation:

$V = \frac{k P \cos θ}{r^{2}} = \frac{9 \times 10^{9} \times 16 \times 10^{- 9}}{{(0.6)}^{2}} \times \frac{1}{2}$
$= 200 V$

NEET - 2020

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359333 Two dipoles each having dipole moment $P$ are placed as shown in the figure. Find the point at which the potential is minimum.
supporting img

1

A

2

B

3

C

4

D

Explanation:

The resultant dipole is shown in the figure.
The point which is closest to the tail of the resultant dipole has minimum potential. The point $C$ has the lowest potential
supporting img

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359334 An electric dipole of moment $\vec{p}$ is placed in a uniform electric field $\vec{E}$ . Then
(i) the torque on the dipole is $\vec{p} \times \vec{E}$ .
(ii) the potential energy of the system is $- \vec{p} \cdot \vec{E}$
(iii) the resultant force on the dipole is zero

1 (i), (ii) and (iii) are correct.

2 (i) and (iii) are correct and (ii) is wrong

3 only (i) is correct

4 (i) and (ii) are correct and (iii) is wrong.

Explanation:

In a uniform electric field $\vec{E}$ , dipole experiences a torque $\vec{τ}$ given by $\vec{τ} = \vec{p} \times \vec{E}$ but experiances no force.
The potential energy of the dipole in a uniform electric field $\vec{E}$ is $U = - \vec{p} \cdot \vec{E}$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359335 The ratio of electric potential due to an electric dipole on the axial position to that on the equitorial on position for the same distance from it, is

1

\infty

2

2

3

1

4

Z e r o

Explanation:

For a dipole, $V_{a x i a l p o s i t i o n} = \frac{K p}{x^{2}}$
$V_{e q u i t o r i a l p o s i t i o n} = 0$
Their ratio $= \infty$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359332 A short electric dipole has a dipole moment of $16 \times 10^{- 9} c m$ . The electric potential due to the dipole at a point at a distance of 0.6 $m$ form the center of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : $(\frac{1}{4 π ε_{0} = 9} \times 10^{9} N m^{2} / C^{2})$

1

200 V

2

400 V

3

Z e r o

4

50 V

Explanation:

$V = \frac{k P \cos θ}{r^{2}} = \frac{9 \times 10^{9} \times 16 \times 10^{- 9}}{{(0.6)}^{2}} \times \frac{1}{2}$
$= 200 V$

NEET - 2020

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359333 Two dipoles each having dipole moment $P$ are placed as shown in the figure. Find the point at which the potential is minimum.
supporting img

1

A

2

B

3

C

4

D

Explanation:

The resultant dipole is shown in the figure.
The point which is closest to the tail of the resultant dipole has minimum potential. The point $C$ has the lowest potential
supporting img

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359334 An electric dipole of moment $\vec{p}$ is placed in a uniform electric field $\vec{E}$ . Then
(i) the torque on the dipole is $\vec{p} \times \vec{E}$ .
(ii) the potential energy of the system is $- \vec{p} \cdot \vec{E}$
(iii) the resultant force on the dipole is zero

1 (i), (ii) and (iii) are correct.

2 (i) and (iii) are correct and (ii) is wrong

3 only (i) is correct

4 (i) and (ii) are correct and (iii) is wrong.

Explanation:

In a uniform electric field $\vec{E}$ , dipole experiences a torque $\vec{τ}$ given by $\vec{τ} = \vec{p} \times \vec{E}$ but experiances no force.
The potential energy of the dipole in a uniform electric field $\vec{E}$ is $U = - \vec{p} \cdot \vec{E}$

PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359335 The ratio of electric potential due to an electric dipole on the axial position to that on the equitorial on position for the same distance from it, is

1

\infty

2

2

3

1

4

Z e r o

Explanation:

For a dipole, $V_{a x i a l p o s i t i o n} = \frac{K p}{x^{2}}$
$V_{e q u i t o r i a l p o s i t i o n} = 0$
Their ratio $= \infty$

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