Combination of Capacitors
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359264 A series combination of \(n_{1}\) capacitors, each of value \(C_{1}\) is charges by a source of potential difference \(4 V\). When another parallel combination of \(n_{2}\) capacitors, each of value \(C_{2}\) is charges by a source of potential difference \(V\), it has the same (total) energy stored in it, as the first combination has. The value of \(C_{2}\), in terms of \(C_{1}\) is, then:

1 \(\dfrac{2 C_{1}}{n_{1} n_{2}}\)
2 \(16 \dfrac{n_{1}}{n_{2}} C_{1}\)
3 \(2 \dfrac{n_{2}}{n_{1}} C_{1}\)
4 \(\dfrac{16 C_{1}}{n_{1} n_{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359265 In the circuit shown in figure, each capacitor has a capacity of \(3\mu F.\) The equivalent capacity between \(A\) and \(B\) is :
supporting img

1 \(3\mu F.\)
2 \(\frac{3}{4}\mu F\)
3 \(5\mu F\)
4 \(6\mu F\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359266 Find the charge on the middle plate, given area of each plate is \(A\) and separation between two consecutive plates is \(d\).
supporting img

1 \(\frac{{{\varepsilon _0}AV}}{d}\)
2 \(\frac{{2{\varepsilon _0}AV}}{d}\)
3 \(0\)
4 \(\frac{{3{\varepsilon _0}AV}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359267 Plates of area \(A\) are arranged as shown. The distance between consecutive plates is \(d\), the net capacitance between \(a\) and \(b\) is
supporting img

1 \(\frac{{5{\varepsilon _o}A}}{d}\)
2 \(\frac{{{\varepsilon _o}A}}{d}\)
3 \(\frac{{6{\varepsilon _o}A}}{d}\)
4 \(\frac{{7{\varepsilon _o}A}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359264 A series combination of \(n_{1}\) capacitors, each of value \(C_{1}\) is charges by a source of potential difference \(4 V\). When another parallel combination of \(n_{2}\) capacitors, each of value \(C_{2}\) is charges by a source of potential difference \(V\), it has the same (total) energy stored in it, as the first combination has. The value of \(C_{2}\), in terms of \(C_{1}\) is, then:

1 \(\dfrac{2 C_{1}}{n_{1} n_{2}}\)
2 \(16 \dfrac{n_{1}}{n_{2}} C_{1}\)
3 \(2 \dfrac{n_{2}}{n_{1}} C_{1}\)
4 \(\dfrac{16 C_{1}}{n_{1} n_{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359265 In the circuit shown in figure, each capacitor has a capacity of \(3\mu F.\) The equivalent capacity between \(A\) and \(B\) is :
supporting img

1 \(3\mu F.\)
2 \(\frac{3}{4}\mu F\)
3 \(5\mu F\)
4 \(6\mu F\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359266 Find the charge on the middle plate, given area of each plate is \(A\) and separation between two consecutive plates is \(d\).
supporting img

1 \(\frac{{{\varepsilon _0}AV}}{d}\)
2 \(\frac{{2{\varepsilon _0}AV}}{d}\)
3 \(0\)
4 \(\frac{{3{\varepsilon _0}AV}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359267 Plates of area \(A\) are arranged as shown. The distance between consecutive plates is \(d\), the net capacitance between \(a\) and \(b\) is
supporting img

1 \(\frac{{5{\varepsilon _o}A}}{d}\)
2 \(\frac{{{\varepsilon _o}A}}{d}\)
3 \(\frac{{6{\varepsilon _o}A}}{d}\)
4 \(\frac{{7{\varepsilon _o}A}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359264 A series combination of \(n_{1}\) capacitors, each of value \(C_{1}\) is charges by a source of potential difference \(4 V\). When another parallel combination of \(n_{2}\) capacitors, each of value \(C_{2}\) is charges by a source of potential difference \(V\), it has the same (total) energy stored in it, as the first combination has. The value of \(C_{2}\), in terms of \(C_{1}\) is, then:

1 \(\dfrac{2 C_{1}}{n_{1} n_{2}}\)
2 \(16 \dfrac{n_{1}}{n_{2}} C_{1}\)
3 \(2 \dfrac{n_{2}}{n_{1}} C_{1}\)
4 \(\dfrac{16 C_{1}}{n_{1} n_{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359265 In the circuit shown in figure, each capacitor has a capacity of \(3\mu F.\) The equivalent capacity between \(A\) and \(B\) is :
supporting img

1 \(3\mu F.\)
2 \(\frac{3}{4}\mu F\)
3 \(5\mu F\)
4 \(6\mu F\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359266 Find the charge on the middle plate, given area of each plate is \(A\) and separation between two consecutive plates is \(d\).
supporting img

1 \(\frac{{{\varepsilon _0}AV}}{d}\)
2 \(\frac{{2{\varepsilon _0}AV}}{d}\)
3 \(0\)
4 \(\frac{{3{\varepsilon _0}AV}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359267 Plates of area \(A\) are arranged as shown. The distance between consecutive plates is \(d\), the net capacitance between \(a\) and \(b\) is
supporting img

1 \(\frac{{5{\varepsilon _o}A}}{d}\)
2 \(\frac{{{\varepsilon _o}A}}{d}\)
3 \(\frac{{6{\varepsilon _o}A}}{d}\)
4 \(\frac{{7{\varepsilon _o}A}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359264 A series combination of \(n_{1}\) capacitors, each of value \(C_{1}\) is charges by a source of potential difference \(4 V\). When another parallel combination of \(n_{2}\) capacitors, each of value \(C_{2}\) is charges by a source of potential difference \(V\), it has the same (total) energy stored in it, as the first combination has. The value of \(C_{2}\), in terms of \(C_{1}\) is, then:

1 \(\dfrac{2 C_{1}}{n_{1} n_{2}}\)
2 \(16 \dfrac{n_{1}}{n_{2}} C_{1}\)
3 \(2 \dfrac{n_{2}}{n_{1}} C_{1}\)
4 \(\dfrac{16 C_{1}}{n_{1} n_{2}}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359265 In the circuit shown in figure, each capacitor has a capacity of \(3\mu F.\) The equivalent capacity between \(A\) and \(B\) is :
supporting img

1 \(3\mu F.\)
2 \(\frac{3}{4}\mu F\)
3 \(5\mu F\)
4 \(6\mu F\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359266 Find the charge on the middle plate, given area of each plate is \(A\) and separation between two consecutive plates is \(d\).
supporting img

1 \(\frac{{{\varepsilon _0}AV}}{d}\)
2 \(\frac{{2{\varepsilon _0}AV}}{d}\)
3 \(0\)
4 \(\frac{{3{\varepsilon _0}AV}}{d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359267 Plates of area \(A\) are arranged as shown. The distance between consecutive plates is \(d\), the net capacitance between \(a\) and \(b\) is
supporting img

1 \(\frac{{5{\varepsilon _o}A}}{d}\)
2 \(\frac{{{\varepsilon _o}A}}{d}\)
3 \(\frac{{6{\varepsilon _o}A}}{d}\)
4 \(\frac{{7{\varepsilon _o}A}}{d}\)