Capacitors with Dielectric
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359224 Consider a parallel plate capacitor of capacity 10μF filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)
supporting img

1 20μF
2 10μF
3 2.5μF
4 25μF
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359225 A capacitor of capacitance 15μF having dielectric slab of εr=2.5, dielectric strength 30MV/m and potential difference =30V. Calculate the area of the plate.

1 6.7×104m2
2 4.2×104m2
3 8.0×104m2
4 9.85×104m2
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359226 A capacitor has charge 50μC.When the gap between the plates is filled with glass wool then 120μC charge flows through the battery. The dielectric constant of glass wool is

1 1.4
2 2.4
3 3.4
4 None of these
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359227 A parallel plate capacitor has plate area 40cm2 and plate separation of 2mm. The space between the plates is filled with a dielectric medium of a thickness 1mm and dielectric constant 5 . The capacitance of the system is

1 103ε0F
2 24ε0F
3 310ε0F
4 10ε0F
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359224 Consider a parallel plate capacitor of capacity 10μF filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)
supporting img

1 20μF
2 10μF
3 2.5μF
4 25μF
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359225 A capacitor of capacitance 15μF having dielectric slab of εr=2.5, dielectric strength 30MV/m and potential difference =30V. Calculate the area of the plate.

1 6.7×104m2
2 4.2×104m2
3 8.0×104m2
4 9.85×104m2
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359226 A capacitor has charge 50μC.When the gap between the plates is filled with glass wool then 120μC charge flows through the battery. The dielectric constant of glass wool is

1 1.4
2 2.4
3 3.4
4 None of these
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359227 A parallel plate capacitor has plate area 40cm2 and plate separation of 2mm. The space between the plates is filled with a dielectric medium of a thickness 1mm and dielectric constant 5 . The capacitance of the system is

1 103ε0F
2 24ε0F
3 310ε0F
4 10ε0F
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359228 The space between the plates of a parallel plate capacitor is filled with a ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :K(x)=Ko+λx (λ= a constant ) The capacitance C, of this capacitor, would be related to its ‘vacuum’ capacitance C0 as per the relation (d is the separation between the plates)

1 C=λdn(1+K0/λd)C0
2 C=λdn(1+K0λd)C0
3 C=λdn(1+K0λd)C0
4 C=λdn(1+λd/K0)C0
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359224 Consider a parallel plate capacitor of capacity 10μF filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)
supporting img

1 20μF
2 10μF
3 2.5μF
4 25μF
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359225 A capacitor of capacitance 15μF having dielectric slab of εr=2.5, dielectric strength 30MV/m and potential difference =30V. Calculate the area of the plate.

1 6.7×104m2
2 4.2×104m2
3 8.0×104m2
4 9.85×104m2
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359226 A capacitor has charge 50μC.When the gap between the plates is filled with glass wool then 120μC charge flows through the battery. The dielectric constant of glass wool is

1 1.4
2 2.4
3 3.4
4 None of these
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359227 A parallel plate capacitor has plate area 40cm2 and plate separation of 2mm. The space between the plates is filled with a dielectric medium of a thickness 1mm and dielectric constant 5 . The capacitance of the system is

1 103ε0F
2 24ε0F
3 310ε0F
4 10ε0F
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359228 The space between the plates of a parallel plate capacitor is filled with a ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :K(x)=Ko+λx (λ= a constant ) The capacitance C, of this capacitor, would be related to its ‘vacuum’ capacitance C0 as per the relation (d is the separation between the plates)

1 C=λdn(1+K0/λd)C0
2 C=λdn(1+K0λd)C0
3 C=λdn(1+K0λd)C0
4 C=λdn(1+λd/K0)C0
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359224 Consider a parallel plate capacitor of capacity 10μF filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)
supporting img

1 20μF
2 10μF
3 2.5μF
4 25μF
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359225 A capacitor of capacitance 15μF having dielectric slab of εr=2.5, dielectric strength 30MV/m and potential difference =30V. Calculate the area of the plate.

1 6.7×104m2
2 4.2×104m2
3 8.0×104m2
4 9.85×104m2
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359226 A capacitor has charge 50μC.When the gap between the plates is filled with glass wool then 120μC charge flows through the battery. The dielectric constant of glass wool is

1 1.4
2 2.4
3 3.4
4 None of these
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359227 A parallel plate capacitor has plate area 40cm2 and plate separation of 2mm. The space between the plates is filled with a dielectric medium of a thickness 1mm and dielectric constant 5 . The capacitance of the system is

1 103ε0F
2 24ε0F
3 310ε0F
4 10ε0F
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359228 The space between the plates of a parallel plate capacitor is filled with a ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :K(x)=Ko+λx (λ= a constant ) The capacitance C, of this capacitor, would be related to its ‘vacuum’ capacitance C0 as per the relation (d is the separation between the plates)

1 C=λdn(1+K0/λd)C0
2 C=λdn(1+K0λd)C0
3 C=λdn(1+K0λd)C0
4 C=λdn(1+λd/K0)C0
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359224 Consider a parallel plate capacitor of capacity 10μF filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)
supporting img

1 20μF
2 10μF
3 2.5μF
4 25μF
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359225 A capacitor of capacitance 15μF having dielectric slab of εr=2.5, dielectric strength 30MV/m and potential difference =30V. Calculate the area of the plate.

1 6.7×104m2
2 4.2×104m2
3 8.0×104m2
4 9.85×104m2
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359226 A capacitor has charge 50μC.When the gap between the plates is filled with glass wool then 120μC charge flows through the battery. The dielectric constant of glass wool is

1 1.4
2 2.4
3 3.4
4 None of these
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359227 A parallel plate capacitor has plate area 40cm2 and plate separation of 2mm. The space between the plates is filled with a dielectric medium of a thickness 1mm and dielectric constant 5 . The capacitance of the system is

1 103ε0F
2 24ε0F
3 310ε0F
4 10ε0F
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359228 The space between the plates of a parallel plate capacitor is filled with a ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :K(x)=Ko+λx (λ= a constant ) The capacitance C, of this capacitor, would be related to its ‘vacuum’ capacitance C0 as per the relation (d is the separation between the plates)

1 C=λdn(1+K0/λd)C0
2 C=λdn(1+K0λd)C0
3 C=λdn(1+K0λd)C0
4 C=λdn(1+λd/K0)C0