Capacitors with Dielectric
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359212 The capacitance of a parallel plate capacitor with air as medium is \(3\mu F\). With the introduction of a dielectric medium between the plates, the capacitance becomes \(15\mu F\). The permitivity of the medium in \(SI\) unit is \(\left[ {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{\rm{SI}}\,{\rm{unit}}} \right]\)

1 \(8.845 \times {10^{ - 11}}\)
2 \(0.4425 \times {10^{ - 10}}\)
3 \(15\)
4 \(5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359213 Find the capacitance as shown in the figure.
supporting img

1 \(2 K A \varepsilon_{0} /(K+1) d\)
2 \(\dfrac{2 K A \varepsilon_{0}}{d}\)
3 \((K+1) A \varepsilon_{0} / 2 d\)
4 \(\dfrac{2 K A \varepsilon_{0}}{\left(K^{2}+1\right) d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359214 The plates of a paralle plate capacitor are charged upto 200 \(V\). A dielectric slab of thickness 4 \(mm\) is inserted between its plates. Then, to maintain the same potential difference betweent the plates of the capacitor, the distance between the plates is increased by 3.2 \(mm\). The dielectric constant of the dielectric slab is

1 \(1\)
2 \(4\)
3 \(5\)
4 \(6\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359215 As shown in the figure, a very thin sheet of an aluminium is placed in between the plates of the condenser. Then the capacity
supporting img

1 Remains unchanged
2 Will increase
3 May increase or decrease
4 Will decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359212 The capacitance of a parallel plate capacitor with air as medium is \(3\mu F\). With the introduction of a dielectric medium between the plates, the capacitance becomes \(15\mu F\). The permitivity of the medium in \(SI\) unit is \(\left[ {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{\rm{SI}}\,{\rm{unit}}} \right]\)

1 \(8.845 \times {10^{ - 11}}\)
2 \(0.4425 \times {10^{ - 10}}\)
3 \(15\)
4 \(5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359213 Find the capacitance as shown in the figure.
supporting img

1 \(2 K A \varepsilon_{0} /(K+1) d\)
2 \(\dfrac{2 K A \varepsilon_{0}}{d}\)
3 \((K+1) A \varepsilon_{0} / 2 d\)
4 \(\dfrac{2 K A \varepsilon_{0}}{\left(K^{2}+1\right) d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359214 The plates of a paralle plate capacitor are charged upto 200 \(V\). A dielectric slab of thickness 4 \(mm\) is inserted between its plates. Then, to maintain the same potential difference betweent the plates of the capacitor, the distance between the plates is increased by 3.2 \(mm\). The dielectric constant of the dielectric slab is

1 \(1\)
2 \(4\)
3 \(5\)
4 \(6\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359215 As shown in the figure, a very thin sheet of an aluminium is placed in between the plates of the condenser. Then the capacity
supporting img

1 Remains unchanged
2 Will increase
3 May increase or decrease
4 Will decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359212 The capacitance of a parallel plate capacitor with air as medium is \(3\mu F\). With the introduction of a dielectric medium between the plates, the capacitance becomes \(15\mu F\). The permitivity of the medium in \(SI\) unit is \(\left[ {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{\rm{SI}}\,{\rm{unit}}} \right]\)

1 \(8.845 \times {10^{ - 11}}\)
2 \(0.4425 \times {10^{ - 10}}\)
3 \(15\)
4 \(5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359213 Find the capacitance as shown in the figure.
supporting img

1 \(2 K A \varepsilon_{0} /(K+1) d\)
2 \(\dfrac{2 K A \varepsilon_{0}}{d}\)
3 \((K+1) A \varepsilon_{0} / 2 d\)
4 \(\dfrac{2 K A \varepsilon_{0}}{\left(K^{2}+1\right) d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359214 The plates of a paralle plate capacitor are charged upto 200 \(V\). A dielectric slab of thickness 4 \(mm\) is inserted between its plates. Then, to maintain the same potential difference betweent the plates of the capacitor, the distance between the plates is increased by 3.2 \(mm\). The dielectric constant of the dielectric slab is

1 \(1\)
2 \(4\)
3 \(5\)
4 \(6\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359215 As shown in the figure, a very thin sheet of an aluminium is placed in between the plates of the condenser. Then the capacity
supporting img

1 Remains unchanged
2 Will increase
3 May increase or decrease
4 Will decrease
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359212 The capacitance of a parallel plate capacitor with air as medium is \(3\mu F\). With the introduction of a dielectric medium between the plates, the capacitance becomes \(15\mu F\). The permitivity of the medium in \(SI\) unit is \(\left[ {{\varepsilon _0} = 8.85 \times {{10}^{ - 12}}{\rm{SI}}\,{\rm{unit}}} \right]\)

1 \(8.845 \times {10^{ - 11}}\)
2 \(0.4425 \times {10^{ - 10}}\)
3 \(15\)
4 \(5\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359213 Find the capacitance as shown in the figure.
supporting img

1 \(2 K A \varepsilon_{0} /(K+1) d\)
2 \(\dfrac{2 K A \varepsilon_{0}}{d}\)
3 \((K+1) A \varepsilon_{0} / 2 d\)
4 \(\dfrac{2 K A \varepsilon_{0}}{\left(K^{2}+1\right) d}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359214 The plates of a paralle plate capacitor are charged upto 200 \(V\). A dielectric slab of thickness 4 \(mm\) is inserted between its plates. Then, to maintain the same potential difference betweent the plates of the capacitor, the distance between the plates is increased by 3.2 \(mm\). The dielectric constant of the dielectric slab is

1 \(1\)
2 \(4\)
3 \(5\)
4 \(6\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359215 As shown in the figure, a very thin sheet of an aluminium is placed in between the plates of the condenser. Then the capacity
supporting img

1 Remains unchanged
2 Will increase
3 May increase or decrease
4 Will decrease