Capacitors with Dielectric
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359190 Four identical plates 1, 2, 3 and 4 placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant \(k = 2\). The capacitance of the system between 1 and 3 & 2 and 4 are \({C_{13}}\) and \({C_{24}}\) respectively. The ratio \(\frac{{{C_{13}}}}{{{C_{24}}}}\) is :
supporting img

1 \(\frac{5}{7}\)
2 \(\frac{3}{5}\)
3 \(\frac{5}{3}\)
4 \(1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359191 The capacitance of a parallel plate capacitor is \({C_a}\) (Fig. \(a\)). A dielectric constant \(K\) is inserted as shown in fig (\(b\)) and (\(c\)). If \({C_b}\) and \({C_c}\) denote the capacitances in fig (\(b\)) and (\(c\)), then
supporting img

1 \({C_c} > {C_a}\) while \({C_b} > {C_a}\)
2 \({C_b} = {C_c} < {C_a}\)
3 \({C_a} = {C_b} = {C_c}\)
4 Both \({C_b},{C_c} < {C_a}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359192 Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

1 Work is not done to take out the slab
2 Energy stored in the capacitor reduces
3 Potential difference across the capacitor is decreased
4 Potential difference across the capacitor is increased
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359193 A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

1 charge \({Q}\)
2 potential \({V}\)
3 capacity \({C}\)
4 energy \({U}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359190 Four identical plates 1, 2, 3 and 4 placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant \(k = 2\). The capacitance of the system between 1 and 3 & 2 and 4 are \({C_{13}}\) and \({C_{24}}\) respectively. The ratio \(\frac{{{C_{13}}}}{{{C_{24}}}}\) is :
supporting img

1 \(\frac{5}{7}\)
2 \(\frac{3}{5}\)
3 \(\frac{5}{3}\)
4 \(1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359191 The capacitance of a parallel plate capacitor is \({C_a}\) (Fig. \(a\)). A dielectric constant \(K\) is inserted as shown in fig (\(b\)) and (\(c\)). If \({C_b}\) and \({C_c}\) denote the capacitances in fig (\(b\)) and (\(c\)), then
supporting img

1 \({C_c} > {C_a}\) while \({C_b} > {C_a}\)
2 \({C_b} = {C_c} < {C_a}\)
3 \({C_a} = {C_b} = {C_c}\)
4 Both \({C_b},{C_c} < {C_a}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359192 Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

1 Work is not done to take out the slab
2 Energy stored in the capacitor reduces
3 Potential difference across the capacitor is decreased
4 Potential difference across the capacitor is increased
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359193 A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

1 charge \({Q}\)
2 potential \({V}\)
3 capacity \({C}\)
4 energy \({U}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359190 Four identical plates 1, 2, 3 and 4 placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant \(k = 2\). The capacitance of the system between 1 and 3 & 2 and 4 are \({C_{13}}\) and \({C_{24}}\) respectively. The ratio \(\frac{{{C_{13}}}}{{{C_{24}}}}\) is :
supporting img

1 \(\frac{5}{7}\)
2 \(\frac{3}{5}\)
3 \(\frac{5}{3}\)
4 \(1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359191 The capacitance of a parallel plate capacitor is \({C_a}\) (Fig. \(a\)). A dielectric constant \(K\) is inserted as shown in fig (\(b\)) and (\(c\)). If \({C_b}\) and \({C_c}\) denote the capacitances in fig (\(b\)) and (\(c\)), then
supporting img

1 \({C_c} > {C_a}\) while \({C_b} > {C_a}\)
2 \({C_b} = {C_c} < {C_a}\)
3 \({C_a} = {C_b} = {C_c}\)
4 Both \({C_b},{C_c} < {C_a}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359192 Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

1 Work is not done to take out the slab
2 Energy stored in the capacitor reduces
3 Potential difference across the capacitor is decreased
4 Potential difference across the capacitor is increased
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359193 A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

1 charge \({Q}\)
2 potential \({V}\)
3 capacity \({C}\)
4 energy \({U}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359190 Four identical plates 1, 2, 3 and 4 placed parallel to each other at equal distance as shown in the figure. Plates 1 and 4 are joined together and the space between 2 and 3 is filled with a dielectric of dielectric constant \(k = 2\). The capacitance of the system between 1 and 3 & 2 and 4 are \({C_{13}}\) and \({C_{24}}\) respectively. The ratio \(\frac{{{C_{13}}}}{{{C_{24}}}}\) is :
supporting img

1 \(\frac{5}{7}\)
2 \(\frac{3}{5}\)
3 \(\frac{5}{3}\)
4 \(1\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359191 The capacitance of a parallel plate capacitor is \({C_a}\) (Fig. \(a\)). A dielectric constant \(K\) is inserted as shown in fig (\(b\)) and (\(c\)). If \({C_b}\) and \({C_c}\) denote the capacitances in fig (\(b\)) and (\(c\)), then
supporting img

1 \({C_c} > {C_a}\) while \({C_b} > {C_a}\)
2 \({C_b} = {C_c} < {C_a}\)
3 \({C_a} = {C_b} = {C_c}\)
4 Both \({C_b},{C_c} < {C_a}\)
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359192 Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

1 Work is not done to take out the slab
2 Energy stored in the capacitor reduces
3 Potential difference across the capacitor is decreased
4 Potential difference across the capacitor is increased
PHXII02:ELECTROSTATIC POTENTIAL AND CAPACITANCE

359193 A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is

1 charge \({Q}\)
2 potential \({V}\)
3 capacity \({C}\)
4 energy \({U}\)