359186 A combination of parallel plate capacitors is maintained at a certain potential difference. When a 3 \(mm\) thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between plates in increased by 2.4 \(mm\). Find the dielectric constant of the slab.

359187 In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is \(4\mu F\), then its new capacity is

359188 A parallel plate capacitor of area \(A\), plate separation \(d\) and capacitance \(C\) is filled with three different dielectric material having dielectric constants \({K_1},{K_2}\) and \({K_3}\) as shown. If a single dielectric material is to be used to have the same capacitance \(C\) in this capacitor, then its dielectric constant \(k\) is given by

359189 If a capacitor \({C_0}\) has plate area \(A\) and distance between plates is \(‘d’\). Now a dielectric of dielectric constant \(‘k’\) is placed between capacitor as shown in figure. Find new capacitance :

359186 A combination of parallel plate capacitors is maintained at a certain potential difference. When a 3 \(mm\) thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between plates in increased by 2.4 \(mm\). Find the dielectric constant of the slab.

359187 In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is \(4\mu F\), then its new capacity is

359188 A parallel plate capacitor of area \(A\), plate separation \(d\) and capacitance \(C\) is filled with three different dielectric material having dielectric constants \({K_1},{K_2}\) and \({K_3}\) as shown. If a single dielectric material is to be used to have the same capacitance \(C\) in this capacitor, then its dielectric constant \(k\) is given by

359189 If a capacitor \({C_0}\) has plate area \(A\) and distance between plates is \(‘d’\). Now a dielectric of dielectric constant \(‘k’\) is placed between capacitor as shown in figure. Find new capacitance :

359186 A combination of parallel plate capacitors is maintained at a certain potential difference. When a 3 \(mm\) thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between plates in increased by 2.4 \(mm\). Find the dielectric constant of the slab.

359187 In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is \(4\mu F\), then its new capacity is

359188 A parallel plate capacitor of area \(A\), plate separation \(d\) and capacitance \(C\) is filled with three different dielectric material having dielectric constants \({K_1},{K_2}\) and \({K_3}\) as shown. If a single dielectric material is to be used to have the same capacitance \(C\) in this capacitor, then its dielectric constant \(k\) is given by

359189 If a capacitor \({C_0}\) has plate area \(A\) and distance between plates is \(‘d’\). Now a dielectric of dielectric constant \(‘k’\) is placed between capacitor as shown in figure. Find new capacitance :

359186 A combination of parallel plate capacitors is maintained at a certain potential difference. When a 3 \(mm\) thick slab is introduced between all the plates, in order to maintain the same potential difference, the distance between plates in increased by 2.4 \(mm\). Find the dielectric constant of the slab.

359187 In a parallel plate air capacitor the distance between plates is reduced to one fourth and the space between them is filled with a dielectric medium of constant 2. If the initial capacity of the capacitor is \(4\mu F\), then its new capacity is

359188 A parallel plate capacitor of area \(A\), plate separation \(d\) and capacitance \(C\) is filled with three different dielectric material having dielectric constants \({K_1},{K_2}\) and \({K_3}\) as shown. If a single dielectric material is to be used to have the same capacitance \(C\) in this capacitor, then its dielectric constant \(k\) is given by

359189 If a capacitor \({C_0}\) has plate area \(A\) and distance between plates is \(‘d’\). Now a dielectric of dielectric constant \(‘k’\) is placed between capacitor as shown in figure. Find new capacitance :