359224 Consider a parallel plate capacitor of capacity \(10\mu F\) filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)

359225 A capacitor of capacitance \(15\,\mu F\) having dielectric slab of \(\varepsilon_{r}=2.5\), dielectric strength \(30\,MV{\rm{/}}m\) and potential difference \( = 30\;V\). Calculate the area of the plate.

359226 A capacitor has charge \(50\mu C.\)When the gap between the plates is filled with glass wool then \(120\mu C\) charge flows through the battery. The dielectric constant of glass wool is

359227 A parallel plate capacitor has plate area \(40\;c{m^2}\) and plate separation of \(2\;mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\;mm\) and dielectric constant 5 . The capacitance of the system is

359228 The space between the plates of a parallel plate capacitor is filled with \(a\) ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :\(K({\rm{x}}) = {K_o} + \lambda {\rm{x}}\) \((\lambda \)= a constant ) The capacitance \(C\), of this capacitor, would be related to its ‘vacuum’ capacitance \({C_0}\) as per the relation (\(d\) is the separation between the plates)

359224 Consider a parallel plate capacitor of capacity \(10\mu F\) filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)

359225 A capacitor of capacitance \(15\,\mu F\) having dielectric slab of \(\varepsilon_{r}=2.5\), dielectric strength \(30\,MV{\rm{/}}m\) and potential difference \( = 30\;V\). Calculate the area of the plate.

359226 A capacitor has charge \(50\mu C.\)When the gap between the plates is filled with glass wool then \(120\mu C\) charge flows through the battery. The dielectric constant of glass wool is

359227 A parallel plate capacitor has plate area \(40\;c{m^2}\) and plate separation of \(2\;mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\;mm\) and dielectric constant 5 . The capacitance of the system is

359228 The space between the plates of a parallel plate capacitor is filled with \(a\) ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :\(K({\rm{x}}) = {K_o} + \lambda {\rm{x}}\) \((\lambda \)= a constant ) The capacitance \(C\), of this capacitor, would be related to its ‘vacuum’ capacitance \({C_0}\) as per the relation (\(d\) is the separation between the plates)

359224 Consider a parallel plate capacitor of capacity \(10\mu F\) filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)

359225 A capacitor of capacitance \(15\,\mu F\) having dielectric slab of \(\varepsilon_{r}=2.5\), dielectric strength \(30\,MV{\rm{/}}m\) and potential difference \( = 30\;V\). Calculate the area of the plate.

359226 A capacitor has charge \(50\mu C.\)When the gap between the plates is filled with glass wool then \(120\mu C\) charge flows through the battery. The dielectric constant of glass wool is

359227 A parallel plate capacitor has plate area \(40\;c{m^2}\) and plate separation of \(2\;mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\;mm\) and dielectric constant 5 . The capacitance of the system is

359228 The space between the plates of a parallel plate capacitor is filled with \(a\) ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :\(K({\rm{x}}) = {K_o} + \lambda {\rm{x}}\) \((\lambda \)= a constant ) The capacitance \(C\), of this capacitor, would be related to its ‘vacuum’ capacitance \({C_0}\) as per the relation (\(d\) is the separation between the plates)

359224 Consider a parallel plate capacitor of capacity \(10\mu F\) filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)

359225 A capacitor of capacitance \(15\,\mu F\) having dielectric slab of \(\varepsilon_{r}=2.5\), dielectric strength \(30\,MV{\rm{/}}m\) and potential difference \( = 30\;V\). Calculate the area of the plate.

359226 A capacitor has charge \(50\mu C.\)When the gap between the plates is filled with glass wool then \(120\mu C\) charge flows through the battery. The dielectric constant of glass wool is

359227 A parallel plate capacitor has plate area \(40\;c{m^2}\) and plate separation of \(2\;mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\;mm\) and dielectric constant 5 . The capacitance of the system is

359228 The space between the plates of a parallel plate capacitor is filled with \(a\) ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :\(K({\rm{x}}) = {K_o} + \lambda {\rm{x}}\) \((\lambda \)= a constant ) The capacitance \(C\), of this capacitor, would be related to its ‘vacuum’ capacitance \({C_0}\) as per the relation (\(d\) is the separation between the plates)

359224 Consider a parallel plate capacitor of capacity \(10\mu F\) filled with air. When the gap between the plate is filled partly with a dielectric of dielectric constant 4, as shown in figure. The new capacity of the capacitor is (A is the area of plates)

359225 A capacitor of capacitance \(15\,\mu F\) having dielectric slab of \(\varepsilon_{r}=2.5\), dielectric strength \(30\,MV{\rm{/}}m\) and potential difference \( = 30\;V\). Calculate the area of the plate.

359226 A capacitor has charge \(50\mu C.\)When the gap between the plates is filled with glass wool then \(120\mu C\) charge flows through the battery. The dielectric constant of glass wool is

359227 A parallel plate capacitor has plate area \(40\;c{m^2}\) and plate separation of \(2\;mm\). The space between the plates is filled with a dielectric medium of a thickness \(1\;mm\) and dielectric constant 5 . The capacitance of the system is

359228 The space between the plates of a parallel plate capacitor is filled with \(a\) ‘dielectric’ whose ‘dielectric constant’ varies with distance as per the relation :\(K({\rm{x}}) = {K_o} + \lambda {\rm{x}}\) \((\lambda \)= a constant ) The capacitance \(C\), of this capacitor, would be related to its ‘vacuum’ capacitance \({C_0}\) as per the relation (\(d\) is the separation between the plates)