366002 When a body slides down a smooth inclined plane having an angle \(\theta\), it reaches the bottom with velocity \(v\). If a sphere rolls down the same inclined plane, its linear velocity at the bottom of the plane is

366003 A uniform cylinder (mass \(M\) ) of radius \(R\) is kept on an accelerating platform (mass \(M\) ) as shown in figure. If the cylinder rolls without slipping on the platform, determine the magnitude of acceleration of the centre of mass of cylinder. Assuming the coefficient of friction \(\mu=0.4\). determine the maximum acceleration of the platform may have without slip between the cylinder and the platform. (Take \(g=10 {~m} / {s}^{2}\) )

366004 A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity \(v\;{\rm{m}}{{\rm{s}}^{ - 1}}\). If it is to climb the inclined surface to a height ' \(h\) ', then \(v\) should be

366005 The ratio of the accelerations for a solid sphere (mass \(m\) and radius \(R\)) rolling down an incline of angle \(\theta\) without slipping and slipping down the incline without rolling is

366006 A cylinder of mass \(M_{c}\) and sphere of mass \(M_{s}\) are placed at points \(\mathrm{A}\) and \(\mathrm{B}\) of two inclines respectively. (See Figure). If they roll on the incline without slipping such that their accelerations are the same, then ratio of \(\dfrac{\sin \theta_{\mathrm{C}}}{\sin \theta_{\mathrm{s}}}\) is :

366002 When a body slides down a smooth inclined plane having an angle \(\theta\), it reaches the bottom with velocity \(v\). If a sphere rolls down the same inclined plane, its linear velocity at the bottom of the plane is

366003 A uniform cylinder (mass \(M\) ) of radius \(R\) is kept on an accelerating platform (mass \(M\) ) as shown in figure. If the cylinder rolls without slipping on the platform, determine the magnitude of acceleration of the centre of mass of cylinder. Assuming the coefficient of friction \(\mu=0.4\). determine the maximum acceleration of the platform may have without slip between the cylinder and the platform. (Take \(g=10 {~m} / {s}^{2}\) )

366004 A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity \(v\;{\rm{m}}{{\rm{s}}^{ - 1}}\). If it is to climb the inclined surface to a height ' \(h\) ', then \(v\) should be

366005 The ratio of the accelerations for a solid sphere (mass \(m\) and radius \(R\)) rolling down an incline of angle \(\theta\) without slipping and slipping down the incline without rolling is

366006 A cylinder of mass \(M_{c}\) and sphere of mass \(M_{s}\) are placed at points \(\mathrm{A}\) and \(\mathrm{B}\) of two inclines respectively. (See Figure). If they roll on the incline without slipping such that their accelerations are the same, then ratio of \(\dfrac{\sin \theta_{\mathrm{C}}}{\sin \theta_{\mathrm{s}}}\) is :

366002 When a body slides down a smooth inclined plane having an angle \(\theta\), it reaches the bottom with velocity \(v\). If a sphere rolls down the same inclined plane, its linear velocity at the bottom of the plane is

366003 A uniform cylinder (mass \(M\) ) of radius \(R\) is kept on an accelerating platform (mass \(M\) ) as shown in figure. If the cylinder rolls without slipping on the platform, determine the magnitude of acceleration of the centre of mass of cylinder. Assuming the coefficient of friction \(\mu=0.4\). determine the maximum acceleration of the platform may have without slip between the cylinder and the platform. (Take \(g=10 {~m} / {s}^{2}\) )

366004 A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity \(v\;{\rm{m}}{{\rm{s}}^{ - 1}}\). If it is to climb the inclined surface to a height ' \(h\) ', then \(v\) should be

366005 The ratio of the accelerations for a solid sphere (mass \(m\) and radius \(R\)) rolling down an incline of angle \(\theta\) without slipping and slipping down the incline without rolling is

366006 A cylinder of mass \(M_{c}\) and sphere of mass \(M_{s}\) are placed at points \(\mathrm{A}\) and \(\mathrm{B}\) of two inclines respectively. (See Figure). If they roll on the incline without slipping such that their accelerations are the same, then ratio of \(\dfrac{\sin \theta_{\mathrm{C}}}{\sin \theta_{\mathrm{s}}}\) is :

366002 When a body slides down a smooth inclined plane having an angle \(\theta\), it reaches the bottom with velocity \(v\). If a sphere rolls down the same inclined plane, its linear velocity at the bottom of the plane is

366003 A uniform cylinder (mass \(M\) ) of radius \(R\) is kept on an accelerating platform (mass \(M\) ) as shown in figure. If the cylinder rolls without slipping on the platform, determine the magnitude of acceleration of the centre of mass of cylinder. Assuming the coefficient of friction \(\mu=0.4\). determine the maximum acceleration of the platform may have without slip between the cylinder and the platform. (Take \(g=10 {~m} / {s}^{2}\) )

366004 A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity \(v\;{\rm{m}}{{\rm{s}}^{ - 1}}\). If it is to climb the inclined surface to a height ' \(h\) ', then \(v\) should be

366005 The ratio of the accelerations for a solid sphere (mass \(m\) and radius \(R\)) rolling down an incline of angle \(\theta\) without slipping and slipping down the incline without rolling is

366006 A cylinder of mass \(M_{c}\) and sphere of mass \(M_{s}\) are placed at points \(\mathrm{A}\) and \(\mathrm{B}\) of two inclines respectively. (See Figure). If they roll on the incline without slipping such that their accelerations are the same, then ratio of \(\dfrac{\sin \theta_{\mathrm{C}}}{\sin \theta_{\mathrm{s}}}\) is :

366002 When a body slides down a smooth inclined plane having an angle \(\theta\), it reaches the bottom with velocity \(v\). If a sphere rolls down the same inclined plane, its linear velocity at the bottom of the plane is

366003 A uniform cylinder (mass \(M\) ) of radius \(R\) is kept on an accelerating platform (mass \(M\) ) as shown in figure. If the cylinder rolls without slipping on the platform, determine the magnitude of acceleration of the centre of mass of cylinder. Assuming the coefficient of friction \(\mu=0.4\). determine the maximum acceleration of the platform may have without slip between the cylinder and the platform. (Take \(g=10 {~m} / {s}^{2}\) )

366004 A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity \(v\;{\rm{m}}{{\rm{s}}^{ - 1}}\). If it is to climb the inclined surface to a height ' \(h\) ', then \(v\) should be

366005 The ratio of the accelerations for a solid sphere (mass \(m\) and radius \(R\)) rolling down an incline of angle \(\theta\) without slipping and slipping down the incline without rolling is

366006 A cylinder of mass \(M_{c}\) and sphere of mass \(M_{s}\) are placed at points \(\mathrm{A}\) and \(\mathrm{B}\) of two inclines respectively. (See Figure). If they roll on the incline without slipping such that their accelerations are the same, then ratio of \(\dfrac{\sin \theta_{\mathrm{C}}}{\sin \theta_{\mathrm{s}}}\) is :