365845
If the resultant of all the external forces acting on a system of particles is zero, then from an inertial frame, one can surely say that
1 Potential energy of the system does not change in time
2 Angular momentum of the system does not change in time
3 Kinetic energy of the system does not change in time
4 Linear momentum of the system does not change in time
Explanation:
Since there is no resultant external force linear momentum of the system remains constant
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365846
Assertion : A quick collision between two bodies is more violent than a slow collision; even when the initial and final velocities are identical. Reason : The momentum is greater in first case.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In 'quick' collision, the time - interval \((\Delta t)\) is small \(\Rightarrow F=\left(\dfrac{\Delta p}{\Delta t}\right)\) is large \(\Rightarrow\) Assertion is correct \(\Rightarrow(\Delta p)\) is greater in 'quicker' (first case) collision than 'slow collision'. But 'Reason' states about 'total momentum' but not change in momentum. Reason is false. So correct option is (3).
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365847
A body of mass \(10\;kg\) moves with a velocity of \(2\;m{s^{ - 1}}\) along a circular path of radius \(8\;m.\) The power produced by the body will be
1 \(10\,J{s^{ - 1}}\)
2 \(98\,J{s^{ - 1}}\)
3 \(49\,J{s^{ - 1}}\)
4 zero
Explanation:
Power is defined as the rate of change of energy in a system or the time rate of doing work. \(P=\dfrac{d E}{d t}=\dfrac{d W}{d t}\) Also, work \(=\) force \(\times\) displacement\(=F \times d\) In a circular motion, displacement is zero, therefore \(P=\dfrac{d}{d t}(F \times d)=\dfrac{d}{d t}(0)=0\)
365845
If the resultant of all the external forces acting on a system of particles is zero, then from an inertial frame, one can surely say that
1 Potential energy of the system does not change in time
2 Angular momentum of the system does not change in time
3 Kinetic energy of the system does not change in time
4 Linear momentum of the system does not change in time
Explanation:
Since there is no resultant external force linear momentum of the system remains constant
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365846
Assertion : A quick collision between two bodies is more violent than a slow collision; even when the initial and final velocities are identical. Reason : The momentum is greater in first case.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In 'quick' collision, the time - interval \((\Delta t)\) is small \(\Rightarrow F=\left(\dfrac{\Delta p}{\Delta t}\right)\) is large \(\Rightarrow\) Assertion is correct \(\Rightarrow(\Delta p)\) is greater in 'quicker' (first case) collision than 'slow collision'. But 'Reason' states about 'total momentum' but not change in momentum. Reason is false. So correct option is (3).
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365847
A body of mass \(10\;kg\) moves with a velocity of \(2\;m{s^{ - 1}}\) along a circular path of radius \(8\;m.\) The power produced by the body will be
1 \(10\,J{s^{ - 1}}\)
2 \(98\,J{s^{ - 1}}\)
3 \(49\,J{s^{ - 1}}\)
4 zero
Explanation:
Power is defined as the rate of change of energy in a system or the time rate of doing work. \(P=\dfrac{d E}{d t}=\dfrac{d W}{d t}\) Also, work \(=\) force \(\times\) displacement\(=F \times d\) In a circular motion, displacement is zero, therefore \(P=\dfrac{d}{d t}(F \times d)=\dfrac{d}{d t}(0)=0\)
365845
If the resultant of all the external forces acting on a system of particles is zero, then from an inertial frame, one can surely say that
1 Potential energy of the system does not change in time
2 Angular momentum of the system does not change in time
3 Kinetic energy of the system does not change in time
4 Linear momentum of the system does not change in time
Explanation:
Since there is no resultant external force linear momentum of the system remains constant
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365846
Assertion : A quick collision between two bodies is more violent than a slow collision; even when the initial and final velocities are identical. Reason : The momentum is greater in first case.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
In 'quick' collision, the time - interval \((\Delta t)\) is small \(\Rightarrow F=\left(\dfrac{\Delta p}{\Delta t}\right)\) is large \(\Rightarrow\) Assertion is correct \(\Rightarrow(\Delta p)\) is greater in 'quicker' (first case) collision than 'slow collision'. But 'Reason' states about 'total momentum' but not change in momentum. Reason is false. So correct option is (3).
PHXI07:SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
365847
A body of mass \(10\;kg\) moves with a velocity of \(2\;m{s^{ - 1}}\) along a circular path of radius \(8\;m.\) The power produced by the body will be
1 \(10\,J{s^{ - 1}}\)
2 \(98\,J{s^{ - 1}}\)
3 \(49\,J{s^{ - 1}}\)
4 zero
Explanation:
Power is defined as the rate of change of energy in a system or the time rate of doing work. \(P=\dfrac{d E}{d t}=\dfrac{d W}{d t}\) Also, work \(=\) force \(\times\) displacement\(=F \times d\) In a circular motion, displacement is zero, therefore \(P=\dfrac{d}{d t}(F \times d)=\dfrac{d}{d t}(0)=0\)
