Explanation:
\(\begin{array}{l} 2\left| \!{\underline {\, {15} \,}} \right. \\ 2\left| \!{\underline {\, {7 - 1} \,}} \right. \\ 2\left| \!{\underline {\, {3 - 1} \,}} \right. \\ 2\left| \!{\underline {\, {1 - 1} \,}} \right. \quad \therefore {15_{{\rm{(}}10{\rm{)}}}} = {1111_{{\rm{(}}2{\rm{)}}}}\\ 0 - 1 \end{array}\)