Explanation:
Let \(A^{\prime}\) be the angle of flint glass prism.
Here, \(A=5^{\circ}\) and \(\mu=1.51\) for crown
glass prism.
Deviation produced by flint glass,
\(\delta^{\prime}=(\mu-1) A=(1.51-1) \times 5=2.55^{\circ}\)
For no deviation, \(\delta^{\prime}=\delta\)
or \(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0.65{A^\prime } = 2.55\)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{A^\prime } = \frac{{2.55}}{{0.65}} = {3.92^ \circ }\)