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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365076 A certain prism is found to produce a minimum deviation of $38^{\circ}$ . It produces a deviation of when the angle of incidence is either $42^{\circ}$ or $62^{\circ}$ . What is the angle of incidence when it is undergoing minimum deviation?

1

49^{\circ}

2

30^{\circ}

3

60^{\circ}

4

40^{\circ}

Explanation:

Deviation is $δ = 44^{\circ}$ when angle of incidence is either $i_{1} = 42^{\circ}$ or $i_{2} = 62^{\circ}$ .
$∴$ Angle of prism,
$A = i_{1} + i_{2} - δ = (42^{\circ} + 62^{\circ} - 44^{\circ}) = 60^{\circ}$
$∴$ For minimum deviation $δ_{min} = 38^{\circ}$ , angle of incidence
$i = \frac{1}{2} (A + δ_{min}) = \frac{1}{2} (60^{\circ} + 38^{\circ}) = 49^{\circ}$

KCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365077 Three prisms 1,2 and 3 have the prism angle $A = 60^{\circ},$ but their refractive indices are respectively 1.4, 1.5 and 1.6. If $δ_{1}, δ_{2}, δ_{3}$ be their respective angles of deviation then

1

δ_{1} > δ_{2} > δ_{3}

2

δ_{3} > δ_{2} > δ_{1}

3

δ_{2} > δ_{1} > δ_{3}

4

δ_{1} = δ_{2} = δ_{3}

Explanation:

$δ \propto (μ - 1)$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365078 A prism of crown glass with refracting angle of $5^{\circ}$ and mean refractive index $= 1.51$ is combined with a flint glass prism of refractive index $= 1.65$ to produce no deviation. Find the angle of flint glass.

1

{3.92}^{\circ}

2

{4.68}^{\circ}

3

{5.32}^{\circ}

4

{7.28}^{\circ}

Explanation:

Let $A^{'}$ be the angle of flint glass prism.
Here, $A = 5^{\circ}$ and $μ = 1.51$ for crown
glass prism.
Deviation produced by flint glass,
$δ^{'} = (μ - 1) A = (1.51 - 1) \times 5 = {2.55}^{\circ}$
For no deviation, $δ^{'} = δ$
or $0.65 A^{'} = 2.55$
$A^{'} = \frac{2.55}{0.65} = {3.92}^{\circ}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365079 In the achromatic prism, we have

1 Deviation without dispersion

2 Dispersion without deviation

3 Refraction without deviation

4 Deviation and dispersion

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365076 A certain prism is found to produce a minimum deviation of $38^{\circ}$ . It produces a deviation of when the angle of incidence is either $42^{\circ}$ or $62^{\circ}$ . What is the angle of incidence when it is undergoing minimum deviation?

1

49^{\circ}

2

30^{\circ}

3

60^{\circ}

4

40^{\circ}

Explanation:

Deviation is $δ = 44^{\circ}$ when angle of incidence is either $i_{1} = 42^{\circ}$ or $i_{2} = 62^{\circ}$ .
$∴$ Angle of prism,
$A = i_{1} + i_{2} - δ = (42^{\circ} + 62^{\circ} - 44^{\circ}) = 60^{\circ}$
$∴$ For minimum deviation $δ_{min} = 38^{\circ}$ , angle of incidence
$i = \frac{1}{2} (A + δ_{min}) = \frac{1}{2} (60^{\circ} + 38^{\circ}) = 49^{\circ}$

KCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365077 Three prisms 1,2 and 3 have the prism angle $A = 60^{\circ},$ but their refractive indices are respectively 1.4, 1.5 and 1.6. If $δ_{1}, δ_{2}, δ_{3}$ be their respective angles of deviation then

1

δ_{1} > δ_{2} > δ_{3}

2

δ_{3} > δ_{2} > δ_{1}

3

δ_{2} > δ_{1} > δ_{3}

4

δ_{1} = δ_{2} = δ_{3}

Explanation:

$δ \propto (μ - 1)$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365078 A prism of crown glass with refracting angle of $5^{\circ}$ and mean refractive index $= 1.51$ is combined with a flint glass prism of refractive index $= 1.65$ to produce no deviation. Find the angle of flint glass.

1

{3.92}^{\circ}

2

{4.68}^{\circ}

3

{5.32}^{\circ}

4

{7.28}^{\circ}

Explanation:

Let $A^{'}$ be the angle of flint glass prism.
Here, $A = 5^{\circ}$ and $μ = 1.51$ for crown
glass prism.
Deviation produced by flint glass,
$δ^{'} = (μ - 1) A = (1.51 - 1) \times 5 = {2.55}^{\circ}$
For no deviation, $δ^{'} = δ$
or $0.65 A^{'} = 2.55$
$A^{'} = \frac{2.55}{0.65} = {3.92}^{\circ}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365079 In the achromatic prism, we have

1 Deviation without dispersion

2 Dispersion without deviation

3 Refraction without deviation

4 Deviation and dispersion

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365076 A certain prism is found to produce a minimum deviation of $38^{\circ}$ . It produces a deviation of when the angle of incidence is either $42^{\circ}$ or $62^{\circ}$ . What is the angle of incidence when it is undergoing minimum deviation?

1

49^{\circ}

2

30^{\circ}

3

60^{\circ}

4

40^{\circ}

Explanation:

Deviation is $δ = 44^{\circ}$ when angle of incidence is either $i_{1} = 42^{\circ}$ or $i_{2} = 62^{\circ}$ .
$∴$ Angle of prism,
$A = i_{1} + i_{2} - δ = (42^{\circ} + 62^{\circ} - 44^{\circ}) = 60^{\circ}$
$∴$ For minimum deviation $δ_{min} = 38^{\circ}$ , angle of incidence
$i = \frac{1}{2} (A + δ_{min}) = \frac{1}{2} (60^{\circ} + 38^{\circ}) = 49^{\circ}$

KCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365077 Three prisms 1,2 and 3 have the prism angle $A = 60^{\circ},$ but their refractive indices are respectively 1.4, 1.5 and 1.6. If $δ_{1}, δ_{2}, δ_{3}$ be their respective angles of deviation then

1

δ_{1} > δ_{2} > δ_{3}

2

δ_{3} > δ_{2} > δ_{1}

3

δ_{2} > δ_{1} > δ_{3}

4

δ_{1} = δ_{2} = δ_{3}

Explanation:

$δ \propto (μ - 1)$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365078 A prism of crown glass with refracting angle of $5^{\circ}$ and mean refractive index $= 1.51$ is combined with a flint glass prism of refractive index $= 1.65$ to produce no deviation. Find the angle of flint glass.

1

{3.92}^{\circ}

2

{4.68}^{\circ}

3

{5.32}^{\circ}

4

{7.28}^{\circ}

Explanation:

Let $A^{'}$ be the angle of flint glass prism.
Here, $A = 5^{\circ}$ and $μ = 1.51$ for crown
glass prism.
Deviation produced by flint glass,
$δ^{'} = (μ - 1) A = (1.51 - 1) \times 5 = {2.55}^{\circ}$
For no deviation, $δ^{'} = δ$
or $0.65 A^{'} = 2.55$
$A^{'} = \frac{2.55}{0.65} = {3.92}^{\circ}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365079 In the achromatic prism, we have

1 Deviation without dispersion

2 Dispersion without deviation

3 Refraction without deviation

4 Deviation and dispersion

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365076 A certain prism is found to produce a minimum deviation of $38^{\circ}$ . It produces a deviation of when the angle of incidence is either $42^{\circ}$ or $62^{\circ}$ . What is the angle of incidence when it is undergoing minimum deviation?

1

49^{\circ}

2

30^{\circ}

3

60^{\circ}

4

40^{\circ}

Explanation:

Deviation is $δ = 44^{\circ}$ when angle of incidence is either $i_{1} = 42^{\circ}$ or $i_{2} = 62^{\circ}$ .
$∴$ Angle of prism,
$A = i_{1} + i_{2} - δ = (42^{\circ} + 62^{\circ} - 44^{\circ}) = 60^{\circ}$
$∴$ For minimum deviation $δ_{min} = 38^{\circ}$ , angle of incidence
$i = \frac{1}{2} (A + δ_{min}) = \frac{1}{2} (60^{\circ} + 38^{\circ}) = 49^{\circ}$

KCET - 2019

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365077 Three prisms 1,2 and 3 have the prism angle $A = 60^{\circ},$ but their refractive indices are respectively 1.4, 1.5 and 1.6. If $δ_{1}, δ_{2}, δ_{3}$ be their respective angles of deviation then

1

δ_{1} > δ_{2} > δ_{3}

2

δ_{3} > δ_{2} > δ_{1}

3

δ_{2} > δ_{1} > δ_{3}

4

δ_{1} = δ_{2} = δ_{3}

Explanation:

$δ \propto (μ - 1)$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365078 A prism of crown glass with refracting angle of $5^{\circ}$ and mean refractive index $= 1.51$ is combined with a flint glass prism of refractive index $= 1.65$ to produce no deviation. Find the angle of flint glass.

1

{3.92}^{\circ}

2

{4.68}^{\circ}

3

{5.32}^{\circ}

4

{7.28}^{\circ}

Explanation:

Let $A^{'}$ be the angle of flint glass prism.
Here, $A = 5^{\circ}$ and $μ = 1.51$ for crown
glass prism.
Deviation produced by flint glass,
$δ^{'} = (μ - 1) A = (1.51 - 1) \times 5 = {2.55}^{\circ}$
For no deviation, $δ^{'} = δ$
or $0.65 A^{'} = 2.55$
$A^{'} = \frac{2.55}{0.65} = {3.92}^{\circ}$

PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS

365079 In the achromatic prism, we have

1 Deviation without dispersion

2 Dispersion without deviation

3 Refraction without deviation

4 Deviation and dispersion

Explanation:

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