364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
