364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
364710
Assertion : For observing traffic at our back, we prefer to use a convex mirror. Reason : A convex mirror has a much larger field of view than a plane mirror or a concave mirror.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Convex mirrors produce virtual, erect, and smaller images, making them suitable for rearview purposes. for a wider field of vision in traffic. So correct option is (1).
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364711
Assertion : Magnification of a convex mirror is always positive and less than unity. Reason : The image formed by convex mirror is always erect and virtual.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Here object is at finite distance (shown). If object at infinity, image I G will be point - sized at F. So, correct option is (1)
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364712
Two objects \(A\) and \(B\) are placed at \(15\;cm\) and \(25\;cm\) from the pole in front of a concave mirror having radius of curvature \(40\;cm\). The distance between images formed by the mirror is
1 \(40\;cm\)
2 \(160\;cm\)
3 \(60\;cm\)
4 \(60\;cm\)
Explanation:
\(R = 40\;cm,f = R/2 = - 20\;cm\) \({u_A} = - 15\;cm,{u_B} = - 25\;cm\) By the mirror formula, \(\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}\) \( - \frac{1}{{20}} = \frac{1}{{{v_A}}} - \frac{1}{{15}} \Rightarrow {v_A} = 60\;cm\) Now, \(\frac{1}{{ - 20}} = \frac{1}{{{v_B}}} - \frac{1}{{25}} \Rightarrow {v_B} = - 100\;cm\) Distance between the images formed by the mirror \( = \left| {{v_A}} \right| + \left| {{v_B}} \right| = 60 + 100 = 160\;cm\)
JEE - 2023
PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
364713
A boy stands straight infront of a mirror at a distance of \(30\;cm\) from it. He sees his erect image whose height is \(\dfrac{1}{5}\)of his real height. The mirror he is using, is
1 plane
2 convex
3 concave
4 plano-concave
Explanation:
Both concave and convex mirrors give virtual image but a concave mirror gives a magnified virtual image (when object is placed between \(F\) and \(P\) ). Since, the boy sees his image of diminished size, so the mirror must be convex.
